Exclamation Javascript problem with submit buttons placed close to each other.there are two buttons which have been called by a javascript here. Both have been coded to redirect to different pages. However, when I hover my mouse on the Regret button it automatically highlights both buttons and when I click regret it redirects to the page where the Confirm button is supposed to redirect. The Confirm button itself is working fine and taking me to the desired page. where the problem is with the Regret button. Basically each button should redirect only to where it is supposed to as I've specified in the Javascript code.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
I want my radio buttons to become submit buttons as well. So when a user clicks on a radio button it submits the action and refreshes the page accordingly. As of now using only using onclick="this.form.submit()" the page only refreshes with no change. Here is a copy of the entire form. It is a custom shipping options form (I did not create it).
to create a hyperlink which closes the window. However with pages which display data retrieved from a database using PHP i use a form to submit a search on the page which displays results. At the bottom of the page is the close window link, however it fails to work once a form has been submitted on the page. It only works when the page first loads.
Any ideas guys on how i can get a close window option that works on my results page after submitting a search?
Safari 4.0.5 and FF 3.6.3 have this problem IE and Chrome are ok The first time when i click the link, two instances of close button shows. If during the same load, i click on another item, the previous clue tip hides and the new one shows with only one close button (right behavior). Image attached. Property closePosition "top and bottom" both have this behavior. closePosition value "title" only shows one close button but it is not clickable.
I have a popup window that opens from a page on my website. This popup is a form with several fields. Upon submit button it redirects to a server side ASP page which writes all data to the DB.
I would like the popup to close immediately after the submit button is clicked, and data is saved, (or cancel button) - but this does not happen. The popup window remains open, even though I have a "return false;" after window.open in the onclick event.
What am I missing?
<a href="myurl.asp" 'title','toolbar=no,width=700,height=600'); return false;">post a note</a>;
whats the script for setting a Submit button to clickable in JS? Right now I've got a few submit buttons but i dont want the next one to be available until the last information was submitted.
as the title says, "close popup window after submit then redirect to parent". how do i do that? i google it and i saw that some people are using the following code:
window.close(); window.opener.location.reload();
The problem is, i dont know how to use and where them.
I'm using Gravity forms for a fancybox popup here- hit the 'JOIN' button and you'll see the popup. What I need to do is close the popup when the submit button is hit and then redirect the parent page to a specific url. I cannot wrap the submit button itself in a link because I'm using Gravity Forms. Is there another way to do this?
I have written some code below which hopefully changes teh value of the flag using JavaScript, I now want to request the value of the flag to see if it's a 1 or a 2?
i have a form with two buttons to submit it. One button (must be left) goes to a detail-page and the second button (must be right) goes to a basket-page. Also there is a input-field.
My problem: onLoad i give focus to the input-field. But when user submits the form with return, the first button ("show details") is executed, and you see the detail-page. But i want to give focus to the ("into basket") button, but it comes after the detail-button in source.
I cant change the buttons because it's not allowed by the designer :-( Also on load of that page, the border of the first submit button is more thick (i think 2 px) than the second (maybe 1px). How can i submit to basket, with the return-key and give them the same look?
I am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form'); productPreviewForm.submit = function() { if(this.validator.validate()) {[code]....
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I need to make a form with 2 submit buttons the first one sends the data of the form to a blank page and the other send the data to another self page. Description: 1st button is to preview the form data in a blank page (preview.php,"Blank") 2nd button is to send data to make do a query in the database (add.php,"self")
I have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
I have a form, that uses validation with jquery, it contains 2 submit-buttons: one is 'back' the other is 'forward'
How it should be: By clicking the 'forward'-submit-button, jquery should validate, if clicking the 'back'-submit-button, jquery should ignore validation
But the problem is: jquery validates at each submit
Now my question: How can I get it, that there is no Validation, when I click on 'back'-submit-button, or in other words, that jquery can differentiate on whitch submit-button it should validate?
Within my project, using PHP/HTML/Javascript, I am trying to set up a page where a corresponding submit button is enabled when a given checkbox is checked. What complicates my attempt is that the checkboxes and submit buttons are in the form of arrays. Here is a snippet of my code:
<form name="myform4" id="list_apps" method="post"> <?php for ($i=0; $i<$num_rows;$i++)
I have one-field form on my website, which is supposed to be filled with barcode number. It was functional until few days age when the need emerged for the auto-submit. As you can see, I have to make script which will automatically submit form when data is filled in barcode field.
I have a form with 2 submit buttons, each with a different value attribute. I can tell which one was clicked after the form has been submitted but I need to check it client side. Here's why: I am doing form validation using the onSubmit event, but I only want to validate if one of the buttons was clicked and not the other.
What's the best way to do this? I thought about having a hidden form field that I set with the onClick of the button I don't want to validate. Is this the best way?
I tried checking myform.Submit.value in my form validation but it comes up "undefined". I guess it isn't defined until the values are actually posted to the server. Or am I missing something here?
- individually (one submit button next to the field) - globally (a submit button at the end of the form).
Before submitting the form, a validation needs to be performed.... so I added: onSubmit="return isValid()".
If the validation does not pass, the form needs to be shown with the data previously entered by the user.
Now, I haven't even come to the previous problem I have mentioned..... my problem is that if a field is empty, the function isValid() recognize it (message sent) .... but the reDirect function is performed!
