I know how to do Sumbit buttons in Forms, and I know how to do custom buttons in Javascript.
What I can't seem to find is how to do custom Submit buttons using Javascript!
Anybody out there have any pagesthat might provide a clue?
How can I create a custom textfield with buttons? Can I use JQuery to do that? See my attached image for a explanation of what I need to do.AttachmentstextfieldButtons.pngSize : 1.2 KB Download : 324
View 1 Replies View RelatedOn my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIf I disable JS is running everything as I need. (but it isn't my objective)
<form id='RequestData' action='request.php' method='post'>
<button type='submit' name='par[1]' value='V1'>
<button type='submit' name='par[2]' value='V2'>
[code]....
Script work, but send wrong data, always send to request par[3]='V9' how I can do to send data' from buttons which I click ?
Myobjective it data:
par => array(
[1] => 'V1'
)
only one value of array PAR
I want my radio buttons to become submit buttons as well. So when a user clicks on a radio button it submits the action and refreshes the page accordingly. As of now using only using onclick="this.form.submit()" the page only refreshes with no change. Here is a copy of the entire form. It is a custom shipping options form (I did not create it).
<!-- Custom shipping form -->
<form action="" method="post" name="update_shipping">
<table width="300">
<tr>
<td><label>
<input <?php if (!(strcmp($_SESSION['shippingmethod'],"1"))) {echo "checked="checked"";} ?>
[Code]...
I'm trying to create custom prompt. When I click on the button, appears custom prompt and ask "Do you realy want to submit?". When I click "Yes", the form isn't submitted. Here's html code...
View 5 Replies View RelatedI'm adding a Microsoft Dynamics CRM Online form to a webpage. It looks like pretty standard html and Javascript. The Microsoft website creates the code automatically and it provides the html code snippet. I provides a standard dull grey button. I'm simply trying to change the standard grey button to a nice looking orange image.
I have the form looking great...only problem is that it doesn't work. I tried it with the standard button and it works fine. When I try to substitute the image, CRM doesn't get the submitted form information. Here is the applicable part of the code:
<input type="hidden" id="dl_qs" name="dl_qs" />
<input type="hidden" id="dl_r" name="dl_r" />
<input type="submit" onclick="document.getElementById('dl_leadForm').dl_qs.value =
[code]....
I tried this, but it didn't work:
<input type="image" src="images/contact-us-button.gif" value="Submit" border="0" <onclick="document.getElementById('dl_leadForm').dl_qs.value = window.location.search;document.getElementById('dl_leadForm').dl_r.value = document.referrer;" value="Submit" >
</form>
I would like to keep any validation built into the form. I'm very new to Javascript, so it's probably something obvious to pros.
whats the script for setting a Submit button to clickable in JS? Right now I've got a few submit buttons but i dont want the next one to be available until the last information was submitted.
View 3 Replies View RelatedI have written some code below which hopefully changes teh value of the flag using JavaScript, I now want to request the value of the flag to see if it's a 1 or a 2?
<script>
function collatedata()
{[code].....
Exclamation Javascript problem with submit buttons placed close to each other.there are two buttons which have been called by a javascript here. Both have been coded to redirect to different pages. However, when I hover my mouse on the Regret button it automatically highlights both buttons and when I click regret it redirects to the page where the Confirm button is supposed to redirect. The Confirm button itself is working fine and taking me to the desired page. where the problem is with the Regret button. Basically each button should redirect only to where it is supposed to as I've specified in the Javascript code.
View 10 Replies View Relatedi have a form with two buttons to submit it. One button (must be left) goes to a detail-page and the second button (must be right) goes to a basket-page. Also there is a input-field.
My problem: onLoad i give focus to the input-field. But when user submits the form with return, the first button ("show details") is executed, and you see the detail-page.
But i want to give focus to the ("into basket") button, but it comes after
the detail-button in source.
I cant change the buttons because it's not allowed by the designer :-(
Also on load of that page, the border of the first submit button is more
thick (i think 2 px) than the second (maybe 1px). How can i submit to basket, with the return-key and give them the same look?
if I have more submit buttons in the form, is it possible to choose defaut button for $(form).submit() event?
View 2 Replies View RelatedI am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form');
productPreviewForm.submit = function() {
if(this.validator.validate()) {[code]....
What I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I need to make a form with 2 submit buttons the first one sends the data of the form to a blank page and the other send the data to another self page.
Description:
1st button is to preview the form data in a blank page (preview.php,"Blank")
2nd button is to send data to make do a query in the database (add.php,"self")
I have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
View 1 Replies View RelatedI have a form, that uses validation with jquery, it contains 2 submit-buttons: one is 'back' the other is 'forward'
How it should be: By clicking the 'forward'-submit-button, jquery should validate, if clicking the 'back'-submit-button, jquery should ignore validation
But the problem is: jquery validates at each submit
Now my question: How can I get it, that there is no Validation, when I click on 'back'-submit-button, or in other words, that jquery can differentiate on whitch submit-button it should validate?
Within my project, using PHP/HTML/Javascript, I am trying to set up a page where a corresponding submit button is enabled when a given checkbox is checked. What complicates my attempt is that the checkboxes and submit buttons are in the form of arrays. Here is a snippet of my code:
<form name="myform4" id="list_apps" method="post">
<?php
for ($i=0; $i<$num_rows;$i++)
[code]....
I have one-field form on my website, which is supposed to be filled with barcode number. It was functional until few days age when the need emerged for the auto-submit. As you can see, I have to make script which will automatically submit form when data is filled in barcode field.
View 9 Replies View RelatedI have a form with 2 submit buttons, each with a different value attribute. I can tell which one was clicked after the form has been submitted but I need to check it client side. Here's why: I am doing form validation using the onSubmit event, but I only want to validate if one of the buttons was clicked and not the other.
What's the best way to do this? I thought about having a hidden form field that I set with the onClick of the button I don't want to validate. Is this the best way?
Here are my 2 input tags:
<input type="submit" name="Submit" value="Add reply">
<input type="submit" name="Submit" value="Close">
I tried checking myform.Submit.value in my form validation but it comes up "undefined". I guess it isn't defined until the values are actually posted to the server. Or am I missing something here?
I have a form with several fields.
Each field can be modified:
- individually (one submit button next to the field)
- globally (a submit button at the end of the form).
Before submitting the form, a validation needs to be performed.... so I added: onSubmit="return isValid()".
If the validation does not pass, the form needs to be shown with the data previously entered by the user.
Now, I haven't even come to the previous problem I have mentioned..... my problem is that if a field is empty, the function isValid() recognize it (message sent) .... but the reDirect function is performed!
I have form within a form and I would like to disable the submit button in the inner form.Currently I have this for some other forms, and it works just finePHP Code:
<form method="post" action="index.php" onkeypress="return event.keyCode!=13">
<input type="text" name="first" value="" />
<input type="text" name="last" value="" />
[code]....
So, here's my problem :
I've created a table in my document, presenting a list of items, one
can 'select' by clicking on it... (Kinda like a menu, you make your
choice from) But since this table can get very long, I've put
something of a 'search-form' on top, which enables the user to make a
selection of products from the list.
Now, the form uses a "post" method, and submits to itself, using the
form action. Some PHP script will make sure that the form is filled
out already, the next time it's presented.
The table, containing a list of products is presented, below the form.
When a user clicks on a product, the product should be "selected". At
first i just used a <a href="zoeken.php?prod_id=24"> link to do this,
but the problem is that my form won't remain in tact.
So now, the global idea is to submit the form after setting a hidden
form-field using JavaScript, using a onClick event.
Here's my code :
On the server side, I'm using a web framework that use submit button "name" attribute to decide which action to perform. On the client side, I have an script that submit forms in Ajax with the "serialize()" functions.
But as the JQuery documentation said, the serialize() function don't send the submit buttons names. I have tried to get the event.target object but this object is the form itself. So, I wonder to know if he is a way to discover obtains the name of the button that has triggered the form submission.
I have a complicated page with several submit buttons. I don't want to
create multiple forms because much of the input is shared and the code
is getting very ugly. However I would like to determine which values
will be submited.
Here is a simplified example that may better illustrate my question.
Or maybe there is a better approach...
<SCRIPT language="JavaScript">
function submitform1()
{
document.myform.submit();
}
function submitform2()
{
// logic to submit only name parameter
document.myform.submit();
}
function submitform3()
{
// logic to submit only address parameter
document.myform.submit();
}
</SCRIPT>
<form name="myform" action="#">
<TABLE>
<TR><TD>Name</TD><TD><input type='text' name='Name'></TD></TR>
<TR><TD>Address</TD><TD><input type='text' name='Address'></TD></TR>
<TR><TD>Phone</TD><TD><input type='text' name='Phone'></TD></TR>
<TR><TD></TD><td><input type="button" onClick="submitform1()"
value="submit all variables"> </TD></TR>
<TR><TD></TD><td><input type="button" onClick="submitform2()"
value="submit just name"> </TD></TR>
<TR><TD></TD><td><input type="button" onClick="submitform3()"
value="submit just address"> </TD></TR>
</TABLE>
</form>
I have a form with several submit buttons. I've used $(#myform).ajaxForm(options) method to make the form submittable with ajax. the problem is that no matter what button I click the form data is the same and <input type="submit"> element is not included into the form data, as if it were not a "successul control". so at this point form doesn't work as expected. is there a way to convey information of which button was clicked with the form plugin?
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