On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 RepliesI have a php form and it has 3 submit buttons namely "delete" , "update_quantity" and "place_order".They all work fine but I want to build in a check for each one just in case the user click one of the buttons by mistake.So Each one must have a different message like for delete it must be, "Are you sure you want to delete Record nr ......" OK or Cancle.
And for update " Are you sure you want to update Quantity to....." OK or Cancle.
i want to use confirmation() function to confirm submit button and if its true ...then submit form... else keep on same page (thats logic)am using php as server scripting ..and i wrote ..in php
PHP Code:
<form action="del_cat.php" name="myform" method="post"> [code]....
my problem is if i click "OK" or "Cancel" both case the form is automatically submitting ..see ...i used
PHP Code:
if (isset($_POST['delete'])) [code].....this code to invoke the function ..
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have some problem while while working on a script..i want to use confirmation() function to confirm submit button and if its true ...then submit form... else keep on same page (thats logic)
Am using php as server scripting..and i wrote..in php
And used a javascript in head
My problem is if i click "OK" or "Cancel" both case the form is automatically submitting ...
See i used:
This code to invoke the function ..
I am submitting a form using an image as the link to a js file. The image calls a js function which checks fields- issuing alerts for errors - if no errors it then submits the form.
I would like to have a final confirm box run from the function before the form is submitted. I guess I would have to use the return statement somehow but I can't see quite how.
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
On the server side, I'm using a web framework that use submit button "name" attribute to decide which action to perform. On the client side, I have an script that submit forms in Ajax with the "serialize()" functions.
But as the JQuery documentation said, the serialize() function don't send the submit buttons names. I have tried to get the event.target object but this object is the form itself. So, I wonder to know if he is a way to discover obtains the name of the button that has triggered the form submission.
I have a form with a bunch of selects and a single text input.Form data is sent via $.post whenever the inputs are changed, so a submit button isn't needed. The form does contain one regular button (using the button tag, not the input tag). The button shows a jQuery UI dialog when clicked.
If you press the enter key in the text field, the browser submits the form but it also acts like you clicked the button (the dialog appears). That makes no sense to me. Why is this happening and how can I stop it?I've already tried adding a few things to the form's submit handler, but they don't make a difference.
$('#filters').submit(function(event) {
event.preventDefault();
event.stopPropagation();
clearTimeout(window.refresh_timer);
[Code]....
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
[Code]...
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
If I disable JS is running everything as I need. (but it isn't my objective)
<form id='RequestData' action='request.php' method='post'>
<button type='submit' name='par[1]' value='V1'>
<button type='submit' name='par[2]' value='V2'>
[code]....
Script work, but send wrong data, always send to request par[3]='V9' how I can do to send data' from buttons which I click ?
Myobjective it data:
par => array(
[1] => 'V1'
)
only one value of array PAR
I'm using an image as my submit button. I want it to check to ensure all boxes have a value before submitting (I will make the verification more stringent later), and if there is none, to cancel the form submission. I created a readonly input box that changes from white to a visible color to use as a status indicator for now.It displays the correct status in either scenario, but return false doesn't seem to be stopping the page from loading. What function would do that?
[Code]...
I'm using external js, not jQuery.I have two different forms on two different web pages. I'd like for the same validating script to handle both forms. I had this:
document.getElementById('form1').onsubmit = validate;
document.getElementById('form2').onsubmit = validate;
But this always causes an error because at least one of those elements will always not exist. How can I get around this and use one js file?
If you write javascript:document.forms[0].submit(); in the location bar, automatically it submits the form, which bypass the form validation. It there any trick to block this form submit?
View 4 Replies View RelatedThere are several forms on this page and I have absolutely no control over them. The page is provided by a 3rd party and all we can do is add javascript.
The form is a google checkout. I need to halt submission (preventDefault) do some stuff and continue the submittion of that form.
This is what I have:
The FORM:
The SCRIPT:
Does the "submit" button always submit form data in non-ajax way?What are the best practices for submitting forms using xhr?
View 1 Replies View RelatedI have written some code below which hopefully changes teh value of the flag using JavaScript, I now want to request the value of the flag to see if it's a 1 or a 2?
<script>
function collatedata()
{[code].....
i have a form with two buttons to submit it. One button (must be left) goes to a detail-page and the second button (must be right) goes to a basket-page. Also there is a input-field.
My problem: onLoad i give focus to the input-field. But when user submits the form with return, the first button ("show details") is executed, and you see the detail-page.
But i want to give focus to the ("into basket") button, but it comes after
the detail-button in source.
I cant change the buttons because it's not allowed by the designer :-(
Also on load of that page, the border of the first submit button is more
thick (i think 2 px) than the second (maybe 1px). How can i submit to basket, with the return-key and give them the same look?
I am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form');
productPreviewForm.submit = function() {
if(this.validator.validate()) {[code]....
What I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I need to make a form with 2 submit buttons the first one sends the data of the form to a blank page and the other send the data to another self page.
Description:
1st button is to preview the form data in a blank page (preview.php,"Blank")
2nd button is to send data to make do a query in the database (add.php,"self")
I have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
View 1 Replies View Related