Check Which Submit Buttand Then Confirm Submit Form?
Sep 25, 2009
I have a php form and it has 3 submit buttons namely "delete" , "update_quantity" and "place_order".They all work fine but I want to build in a check for each one just in case the user click one of the buttons by mistake.So Each one must have a different message like for delete it must be, "Are you sure you want to delete Record nr ......" OK or Cancle.
And for update " Are you sure you want to update Quantity to....." OK or Cancle.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
I am submitting a form using an image as the link to a js file. The image calls a js function which checks fields- issuing alerts for errors - if no errors it then submits the form.
I would like to have a final confirm box run from the function before the form is submitted. I guess I would have to use the return statement somehow but I can't see quite how.
I have a form with a text box where users can enter a 10 digit code. The 10 digit code can be just numbers/letters (eg. 0123456789 or abcdefghij) or it can be a mixture (eg. 0a1b2c3d4e). What I would like is if the user enters a code which is a mixture of numbers and letters then the submit url goes to mixed.php If the user enters a code which just has letters or numbers then the submit url goes to sole.php change the url from selecting radio buttons.
I'm using the submit and ajax functions to check a form. When the form is submitted the submit event executes and within that event the data (a code the user has to fill in) is sent to the server to check if it's correct. If it is correct, the submit event supposes to return true (so the form submits), if it's incorrect the submit event supposes to return false (so submitting the form cancels).
Here's my code that should do this: $(function(){ var submit = false; $('#login').submit(function(){ $('span.error').fadeOut('slow'); $.ajax({ url: '/ajax/login', type: 'POST', data: 'code=' + $('#code').val(), success: function(response){ if (response != ''){ $('span.error').fadeIn('slow').text(response); submit = false; }else{ submit = true; }}}) return submit; })});
But here's the problem: While jQuery does the ajax request, the script continues. So it will return false - even if the code is validated - because the var submit has been set to false at line 4. When I submit the form again, the form is validated because 'submit' is true (but that's set to true the first time). How can I ensure the submit function waits for the ajax request to finish?
I have a form with a text field and a submit button. I don't want the form to submit if the text field is filled in correctly. for example a email address typed in the text field area. I'm working with spry validation but i guess i need to add some kind of onSubmit event, with javascript. I have some idea but not sure what to fill in by the "if statements" in the script.
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() { $("#ARTransferForm").submit(function() { var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
i want to use confirmation() function to confirm submit button and if its true ...then submit form... else keep on same page (thats logic)am using php as server scripting ..and i wrote ..in php
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code: What I've tried so far is like this: savedSubmit = document.inputs.submit; document.inputs.submit = None; then later: document.inputs.submit = savedSubmit;
I am using the validate plugin to perform validations on a form.I would like to show a confirm message ( alert with ok and cancel ) upon submit and successful vaildation.I have tried the following but it does not work:[code]The form submits even If I click "Cancel". Is there anythingwrong with my code above?
I have some problem while while working on a script..i want to use confirmation() function to confirm submit button and if its true ...then submit form... else keep on same page (thats logic)
Am using php as server scripting..and i wrote..in php
And used a javascript in head
My problem is if i click "OK" or "Cancel" both case the form is automatically submitting ...
I've created a table in my document, presenting a list of items, one can 'select' by clicking on it... (Kinda like a menu, you make your choice from) But since this table can get very long, I've put something of a 'search-form' on top, which enables the user to make a selection of products from the list.
Now, the form uses a "post" method, and submits to itself, using the form action. Some PHP script will make sure that the form is filled out already, the next time it's presented.
The table, containing a list of products is presented, below the form. When a user clicks on a product, the product should be "selected". At first i just used a <a href="zoeken.php?prod_id=24"> link to do this, but the problem is that my form won't remain in tact.
So now, the global idea is to submit the form after setting a hidden form-field using JavaScript, using a onClick event.
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
<script> function autoUpdate() { var text = document.documentElement.innerHTML; var url = "http://192.168.0.2/user/edit/account" + myAccountNumber + "/edit";
I have a form with 2 submit buttons, each with a different value attribute. I can tell which one was clicked after the form has been submitted but I need to check it client side. Here's why: I am doing form validation using the onSubmit event, but I only want to validate if one of the buttons was clicked and not the other.
What's the best way to do this? I thought about having a hidden form field that I set with the onClick of the button I don't want to validate. Is this the best way?
I tried checking myform.Submit.value in my form validation but it comes up "undefined". I guess it isn't defined until the values are actually posted to the server. Or am I missing something here?
I have 3 check boxes and one submit button when the submit button is hit I need it to direct to one of 3 pages depending on which check box is checked.
I have a form where I click a button and it duplicates the inputs thus now having X of the same inputs. The input name looks like so: <select id="select" name="cs_quantity[]"> Is there a way I can check the all values of the quantity before submitting the form? I want to make sure they've chosen a quantity other than 0.
I'm probably not writing this the proper way, but I have code that almost works. $("#submit_button").click(function(){ $(".product").each(function(){ if ($(this).val() == '' ) { $("#product_failed").css("display", "inline"); $("#myForm").submit(function(){ return false; });//end submit false }else{ $("#product_failed").css("display", "none"); $("#myForm").submit(); };//end if });//end .product each function });//end submit button click The error message shows and hides properly based on whether the select menu value is "" or not, but if the value is not "" the form doesn't submit.
