I need to make a form with 2 submit buttons the first one sends the data of the form to a blank page and the other send the data to another self page.
Description:
1st button is to preview the form data in a blank page (preview.php,"Blank")
2nd button is to send data to make do a query in the database (add.php,"self")
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedI have written some code below which hopefully changes teh value of the flag using JavaScript, I now want to request the value of the flag to see if it's a 1 or a 2?
<script>
function collatedata()
{[code].....
i have a form with two buttons to submit it. One button (must be left) goes to a detail-page and the second button (must be right) goes to a basket-page. Also there is a input-field.
My problem: onLoad i give focus to the input-field. But when user submits the form with return, the first button ("show details") is executed, and you see the detail-page.
But i want to give focus to the ("into basket") button, but it comes after
the detail-button in source.
I cant change the buttons because it's not allowed by the designer :-(
Also on load of that page, the border of the first submit button is more
thick (i think 2 px) than the second (maybe 1px). How can i submit to basket, with the return-key and give them the same look?
I am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form');
productPreviewForm.submit = function() {
if(this.validator.validate()) {[code]....
What I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
View 1 Replies View RelatedI have one-field form on my website, which is supposed to be filled with barcode number. It was functional until few days age when the need emerged for the auto-submit. As you can see, I have to make script which will automatically submit form when data is filled in barcode field.
View 9 Replies View RelatedI have a form with several submit buttons. I've used $(#myform).ajaxForm(options) method to make the form submittable with ajax. the problem is that no matter what button I click the form data is the same and <input type="submit"> element is not included into the form data, as if it were not a "successul control". so at this point form doesn't work as expected. is there a way to convey information of which button was clicked with the form plugin?
View 4 Replies View RelatedVery new to JavaScript so I'm sorry if this is a daft question, I have searched for answers first and could not find anything that works for me ... so .. One html form with two submit buttons. On submit (save changes) posts back to the same page and updates a database. The other submit button (preview) should open a op-up showing what the data would look like if the user should press save.
[Code]...
how I can make each radio button call a different page. For example If i click on radio button 1 and click submit it will take me to [url].... and if I click radio button 2 and click submit .
View 7 Replies View RelatedSeems to me this would be a fairly common situation (if not commonly asked and answered), but the posts I did find about this subject didn't seem to
Given this basic code:
<form id="form" action="">
<input id="submit1">
[code]....
What I need to do is to pass a conditional variable to the target URL,
when the form is submitted, depending on which graphic button is pressed.
So, the form already sends several variables when the form is submitted
(at the onclick event). I've confirmed this by capturing the HTTP POST
variables and displaying them when the page executes.
Now, depending on which graphic button is selected, I would like to pass
another variable.
For example, when the Create button is pressed, I would like to pass
create=true (or something signifying that 'create' is set) to the target
URL......
How do I make ENTER key act as a submit request?
As it is now, the user has to actually click "submit" for the form to
be submitted (in IE at least).
Is there any way to make the enter key submit the form? Code:
I am trying to make a DIV visible after a user clicks a form submit button that posts to the same page.
Here is the code that I have came up with so far and it does not work.
<script>
void processForm()
{
document.getElementById("loadingImg").style.visibility = "visible";
[Code]....
I would like to submit a form, and then have a results page appear... but also a small popup with another webpage.
View 1 Replies View RelatedI get right to the point: I want my form to select the correct radio button and submit by clicking a custom link. This is for a voting system, a simple top list.My setup (psuedo setup really) The "o" is a radio button.1. Cat - Points: 5 - o [Vote]2. Dog - Points: 3 - o [Vote]The goal? User clicks on the [Vote] - link and the correct radio button is selected and the form is submitted.(I´m not going to show the radio button later, just there to clear things out right know).So I wrote this little neat piece of code:
(.views-field nothing span => My [Vote]-link)
(function($) {
$(function() {
[code]....
<a href="#" onclick="document['form1'].submit(); return false" >search</a> have written the follwoing script for making a textlink to submit a formit works fine. with this i want to pass a flag or a value and retrived at the serverside
View 7 Replies View RelatedNeed the three "Options" to be hyperlinks that submit the "choice" form. When submitted, I would like the value to be the text of the option selected (i.e. value=Option1, Option2 orOption3) and all three to have the same name. (i.e. name = Options) How do I make the 3 options inputs and submit on click?
<form action="cgi.exe" method=POST name="choice"> <tbody> <tr> <td>Option1</td>
<td>Option2</td>
<td>Option3</td>
[code]....
If I disable JS is running everything as I need. (but it isn't my objective)
<form id='RequestData' action='request.php' method='post'>
<button type='submit' name='par[1]' value='V1'>
<button type='submit' name='par[2]' value='V2'>
[code]....
Script work, but send wrong data, always send to request par[3]='V9' how I can do to send data' from buttons which I click ?
Myobjective it data:
par => array(
[1] => 'V1'
)
only one value of array PAR
I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedI want my radio buttons to become submit buttons as well. So when a user clicks on a radio button it submits the action and refreshes the page accordingly. As of now using only using onclick="this.form.submit()" the page only refreshes with no change. Here is a copy of the entire form. It is a custom shipping options form (I did not create it).
<!-- Custom shipping form -->
<form action="" method="post" name="update_shipping">
<table width="300">
<tr>
<td><label>
<input <?php if (!(strcmp($_SESSION['shippingmethod'],"1"))) {echo "checked="checked"";} ?>
[Code]...
I want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
View 2 Replies View RelatedThis is the code
Code:
<script>
function autoUpdate() {
var text = document.documentElement.innerHTML;
var url = "http://192.168.0.2/user/edit/account" + myAccountNumber + "/edit";
[code]....
Is using the real form submit button a problem in any way? Can it actaully send a form when a person uses 'enter' in a text field. When I use this submit, it triggers my validation which is great.
<input type="submit" value="OnSubmit validate" />
However this way doesn't seem to trigger my validation although It may solve the above form send problem (if that realy exists). How do I get it to act the same as real submit so it will trigger validation like onsubmit above?
<input type="button" value="Send Feedback" onclick="this.form.submit()" />
LT does any of that make sense?
whats the script for setting a Submit button to clickable in JS? Right now I've got a few submit buttons but i dont want the next one to be available until the last information was submitted.
View 3 Replies View Related