Seems to me this would be a fairly common situation (if not commonly asked and answered), but the posts I did find about this subject didn't seem to
Given this basic code:
<form id="form" action="">
<input id="submit1">
[code]....
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
In my html head tag i have a script like as below
$(
function
(
)
[Code].....
I am trying to update some values on the page when an img is clicked. There are many img tags on the page. I am not sure how can i determine which one is clicked.
Do i have to add an onclick event to my img tags with some id parameter or is there a possibility to detect which element is clicked on the page without calling a function?
I have several <a> tags with the class 'a-menu-description', and an equal number of divs with the class 'menu-description'.
I am trying to get it so that only one div opens for the appropriate <a> tag, but when I click any of the <a> tags, all of the divs open up.
Here is my code:
Does anybody know what I can add in so that only the div associated with the <a> tag opens as opposed to all of them?
[url]
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedI have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
View 1 Replies View RelatedI have a form with several submit buttons. I've used $(#myform).ajaxForm(options) method to make the form submittable with ajax. the problem is that no matter what button I click the form data is the same and <input type="submit"> element is not included into the form data, as if it were not a "successul control". so at this point form doesn't work as expected. is there a way to convey information of which button was clicked with the form plugin?
View 4 Replies View RelatedHow could I determine when ANY link on a page is clicked and what that link points to without having to add a function call into onClick of every href tag?
View 3 Replies View RelatedI have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
im trying to learn how jquery ajax function works by validating some form after submit is clicked.
[Code]....
the alert didnt pop until i added the registration_ok = false; right before, so im assuming it has something to do with the ajax functions's scope.... why does the ajax function not affect the registration_ok variable outside the function? and how should i solve this problem? any better way of doing it?
I have written some code below which hopefully changes teh value of the flag using JavaScript, I now want to request the value of the flag to see if it's a 1 or a 2?
<script>
function collatedata()
{[code].....
i have a form with two buttons to submit it. One button (must be left) goes to a detail-page and the second button (must be right) goes to a basket-page. Also there is a input-field.
My problem: onLoad i give focus to the input-field. But when user submits the form with return, the first button ("show details") is executed, and you see the detail-page.
But i want to give focus to the ("into basket") button, but it comes after
the detail-button in source.
I cant change the buttons because it's not allowed by the designer :-(
Also on load of that page, the border of the first submit button is more
thick (i think 2 px) than the second (maybe 1px). How can i submit to basket, with the return-key and give them the same look?
I am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form');
productPreviewForm.submit = function() {
if(this.validator.validate()) {[code]....
What I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I need to make a form with 2 submit buttons the first one sends the data of the form to a blank page and the other send the data to another self page.
Description:
1st button is to preview the form data in a blank page (preview.php,"Blank")
2nd button is to send data to make do a query in the database (add.php,"self")
I have one-field form on my website, which is supposed to be filled with barcode number. It was functional until few days age when the need emerged for the auto-submit. As you can see, I have to make script which will automatically submit form when data is filled in barcode field.
View 9 Replies View RelatedVery new to JavaScript so I'm sorry if this is a daft question, I have searched for answers first and could not find anything that works for me ... so .. One html form with two submit buttons. On submit (save changes) posts back to the same page and updates a database. The other submit button (preview) should open a op-up showing what the data would look like if the user should press save.
[Code]...
What I need to do is to pass a conditional variable to the target URL,
when the form is submitted, depending on which graphic button is pressed.
So, the form already sends several variables when the form is submitted
(at the onclick event). I've confirmed this by capturing the HTTP POST
variables and displaying them when the page executes.
Now, depending on which graphic button is selected, I would like to pass
another variable.
For example, when the Create button is pressed, I would like to pass
create=true (or something signifying that 'create' is set) to the target
URL......
If I disable JS is running everything as I need. (but it isn't my objective)
<form id='RequestData' action='request.php' method='post'>
<button type='submit' name='par[1]' value='V1'>
<button type='submit' name='par[2]' value='V2'>
[code]....
Script work, but send wrong data, always send to request par[3]='V9' how I can do to send data' from buttons which I click ?
Myobjective it data:
par => array(
[1] => 'V1'
)
only one value of array PAR
What happens is the user selects the number of buttons depending on the number entered in the text box. If the number is 3 in the text box, then the user can only select 3 buttons, if more buttons are selected then it comes with an alert message saying user is beyond limit deselect a button to be able to choose another button.
But these are the problems I have encounted: If I type in "2" in the textbox for example, it allows me to select 2 buttons and comes up with alert if more buttons clicked.
problem 1: but if I change the figure in text box from "2" to "5", then it only allows me to select 3 buttons (I think it is adding 2 from the previous value and 3 to make the current value 5)
problem 2: If I enter a value less than current value, so in this example if I enter in 1 in the textbox which is obviously less than 2, then it lets the user select unlimited number of buttons.
So does anyone know how to fix these problems so that the amount of buttons selected matches correctly to the value in the textbox?
I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedI am creating a website that uses columns (example) and I would like to be able to click left and right buttons to scroll horizontally one column at a time without the header and footer scrolling with the content.
I have tried using Scrollable and JCarousel but both require you to scroll through a set of list items. I need to be able to scroll 320px at a time. Is this possible?
I have the following javascript code:
Code JavaScript:
for (var i=0; i < myRadio.length; i++) {
if (myRadio[i].checked) {
myChecked = 1;
[Code]....
This works fine when I have more than 1 radio button. However for just a single radio button it does not work. I don't know how many radio buttons I will have since they are being created from a mysql query.
I'm very bad with javascript, so how should I amend the code so that it also works with only one radio button? I just need to check if they are trying to submit the form without selecting any radio buttons.
I want my radio buttons to become submit buttons as well. So when a user clicks on a radio button it submits the action and refreshes the page accordingly. As of now using only using onclick="this.form.submit()" the page only refreshes with no change. Here is a copy of the entire form. It is a custom shipping options form (I did not create it).
<!-- Custom shipping form -->
<form action="" method="post" name="update_shipping">
<table width="300">
<tr>
<td><label>
<input <?php if (!(strcmp($_SESSION['shippingmethod'],"1"))) {echo "checked="checked"";} ?>
[Code]...
I have a submit-event attached to my form. The form contains a few different submit-buttons and I wan't to chech which one of them that triggered the submit. Shouldn't be to hard but i can't find out how to do it.
View 2 Replies View Relatedif I have more submit buttons in the form, is it possible to choose defaut button for $(form).submit() event?
View 2 Replies View Related