Very new to JavaScript so I'm sorry if this is a daft question, I have searched for answers first and could not find anything that works for me ... so .. One html form with two submit buttons. On submit (save changes) posts back to the same page and updates a database. The other submit button (preview) should open a op-up showing what the data would look like if the user should press save.
[Code]...
I am working on an application and it needs to access a third party service through an iFrame. I basically need to know how I can have Javascript autofill the fields and then submit the form that is contained in an iframe. Is this possible?
View 3 Replies View Relatedi'm using greybox on my website, and using survey. i want when click submit button then post form data to opened greybox window.. but can't..
my form actions
<form action="anket.php?islem=ok" method="post" onSubmit="javascript:return GB_showCenter('Anket',this.action, 280, 350)" >
greybox window open, but can't show post data..
I would like to submit a form depending on the success data of an ajax post.
Below is my jquery code; as you see #theform is the main form and before submitting the form I need to check the availability of the the date and time and the room using$.ajax. However it doesn't submit the main form if the date, time and the room is available.
required=["txtCal_Event_CalendarID","txt_TreatmentRoom","txtTreatmentID","txtTreatmentTypeID","datepicker1","datepicker2","timepicker1","timepicker2"];
emptyerror="Please fill out this field.";
[Code].....
If I disable JS is running everything as I need. (but it isn't my objective)
<form id='RequestData' action='request.php' method='post'>
<button type='submit' name='par[1]' value='V1'>
<button type='submit' name='par[2]' value='V2'>
[code]....
Script work, but send wrong data, always send to request par[3]='V9' how I can do to send data' from buttons which I click ?
Myobjective it data:
par => array(
[1] => 'V1'
)
only one value of array PAR
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedI am writing a small data entry screen that will post the form data to a page and return a message. But i cannot get the Success or Error functions working properly.
Here's the code where strData is the posted querystring of:
I'm not sure whether it should be in a form and using the onsubmit or click of a button.
Here is a script and its uses a latest jquery
$(function(){
$(".submit").click(function(){
varname=$("#name").val();
varsurname=$("#surname").val();
[Code].....
Its sends only a M value ..The different IDs gives a undefined there is a problem with radio button DOM - Jquery
I want to post some HTML (contained in a div on the page) data using jQuery using $.ajax() method. But it is not working.
<script language="javascript" type="text/javascript">
function PostHTMLContentTOServer() {
var pageData = document.getElementById
("MainDiv").innerHTML;
[Code]....
how do I get the post data from html in jQuery which contains square brackets?
[code]........
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I have written some code below which hopefully changes teh value of the flag using JavaScript, I now want to request the value of the flag to see if it's a 1 or a 2?
<script>
function collatedata()
{[code].....
i have a form with two buttons to submit it. One button (must be left) goes to a detail-page and the second button (must be right) goes to a basket-page. Also there is a input-field.
My problem: onLoad i give focus to the input-field. But when user submits the form with return, the first button ("show details") is executed, and you see the detail-page.
But i want to give focus to the ("into basket") button, but it comes after
the detail-button in source.
I cant change the buttons because it's not allowed by the designer :-(
Also on load of that page, the border of the first submit button is more
thick (i think 2 px) than the second (maybe 1px). How can i submit to basket, with the return-key and give them the same look?
I am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form');
productPreviewForm.submit = function() {
if(this.validator.validate()) {[code]....
What I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I need to make a form with 2 submit buttons the first one sends the data of the form to a blank page and the other send the data to another self page.
Description:
1st button is to preview the form data in a blank page (preview.php,"Blank")
2nd button is to send data to make do a query in the database (add.php,"self")
I have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
View 1 Replies View RelatedI have one-field form on my website, which is supposed to be filled with barcode number. It was functional until few days age when the need emerged for the auto-submit. As you can see, I have to make script which will automatically submit form when data is filled in barcode field.
View 9 Replies View Relatedcan anybody help me in writing a javascript function which opens a
popup window with the target URL when the link "POST Request" is
clicked..
Points to note:
The HTML DOESNT and SHOULDNT HAVE A FORM TAG.
The URL data should be sent as POST and not GET..i.e the search
parameters should not be showin in the address bar when the page is
opened.
Sample code is:
I have a form that will always live in a sidebar. It has 2 fields: 'zip code' and 'keyword'. I need the results of that form to...
#1. Trigger a page on my site that contains an iframe
#2. Append the form results to an external URL to load in that iframe. (example: www.externalsite.com/zipcode/keyword)
I have a lot of tables and to get it to post some of the data into a form.
So say i have a location and a start date and end date, and when i select a radio and click submit the location and dates get put into the corresponding field in the form.
However i have a lot of tables and a lot of different options but want it to go to only one form. this form can be on a seperate page, but was wondering if its possible to get the form to appear on the same page, underneath the table.
I have a form with several submit buttons. I've used $(#myform).ajaxForm(options) method to make the form submittable with ajax. the problem is that no matter what button I click the form data is the same and <input type="submit"> element is not included into the form data, as if it were not a "successul control". so at this point form doesn't work as expected. is there a way to convey information of which button was clicked with the form plugin?
View 4 Replies View Relatedi need to post data from a form to a page on another domain, without leaving the current page.I am using ASP as a server language.
View 9 Replies View RelatedI have a problem with sending data from a form to a php script with AJAX. To test if it works, I try to send data from the form, print it in the php with "echo", and then put it back in the initial html file.
My Javascript code is:
The function stateChanged, basically says:
The problem is that the response is empty, but I don't know why. I have checked the input data and the postData variable says "firstName="+input (e.g. "firstName=Robert"), so that's not the error.
I've got a form which is acting as a calculator. Once the calculation is complete I want it so when the user presses a 'print' button it takes certain parts of the form data and displays them in a new window which would be designed for printing.
how can i go about this using only javascript?
I have an upload form that is working fine with a submit button, but I really would like it to submit on its own without a submit button onChange when a user selects an image. I have it sending the form with onChange but it is not sending the uploaded file like when you hit the button! It is sending it as "example.jpg" instead of actually sending the file for upload.
View 11 Replies View Related