I have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
I have a JSP page with several forms on it. Some of these forms are
generated dynamically, and each of them submits some information to a
database.
Handling one form is easy, as I can simply make the form post to
itself, and handle the
data using a single bean. Since I have multiple forms, I now have a
problem. Several of the forms on the page handle the same type of data
(same input names), and a 'setproperty *' call for each of the form
beans would change data in several beasn, not just the form/bean that
sent the data.
I am attempting to write a separate JSP with a single bean that
handles a form submission. However, I'm not sure how to make this page
go back to the referring page from which the data was submitted.
I have a php page with java script embed in it, i have 3 forms in a single page ... namely form1, form2, form3 . form 1 and form2 have a text box , these text boxes get input from users. Now my task is to get the value of these 2 tex boxes in form3 when the user click the submit button, so that i pass the values in those text boxes to next page for calculation.
I tried the following code in form3 but it result in vain :
It doesn't appear to be possible to validate multiple forms on a pages that only has a single <form> tag, using the JQuery Validation Plugin offered by Jörn Zaefferer. The reason I need to do this is because my pages are created with ASP.NET whose architecture generally calls for a single page-wide <form> tag. In my designs, I'd like to submit my data using a custom ajax call to a web-method, and link it to a click event on a button.
Below is an example:
<!
DOCTYPE
html
PUBLIC
"-//W3C//DTDXHTML1.0Transitional//EN" "[URL]" >
<
html
xmlns
=
"[URL]"
> .....
I'm not sure that I fully understand the documentation for the Validation plugin, but it doesn't seem like this is possible, as the plugin seems to need a <form> for each form.
I have made a site with 5 pages, each page contains a form. Each form is a checklist with a dropdown to choose an answer for each individual item.
Here is a same of the form code:
I am trying to write a script that will be called with onclick event from the "Next" button. This script will collect all the "notOK" option value/names and send them to a document, concatenating the info from the next forms until a single report is created with a list of all the "notOK" values. One the user gets to the end of the last form, there will be a submit button which sends the entire report to a specific email address.
Here is the script I have so far, which pulls the "notOK" values for each page:
This piece of code works great for an individual page, but I need to expand it to send the data to a report instead of window.alert, and I need to add some way of concatenating the data from each form to a single page, doc, etc.
I want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
View 2 Replies View RelatedI am trying to change each forms .submit function like so (below) but each submit button gets the function of the last iteration. I want each form to have a different submit function without using onclick events.
var x = document.getElementsByTagName("form");
for(i=0; i < x.length; i++){
var ele = x[i].elements;[code].....
I need to submit two forms using a single submit button. What's ur suggestion. I found that JavaScript is the only way to go here, right?
View 1 Replies View RelatedHow can one submit multiple forms at a time. At the same time the values must get Forwarded another page.
View 4 Replies View RelatedI'm trying to use a single submit button to submit 3 forms on a single page. 1 form I use and process, the other 2 are sent to other sites.
Everything works great except in Google Chrome (and Safari) due to some restriction/bug in WebKit.
Code:
This works perfectly fine in IE and FireFox, but in Chrome - as it sits, it will submit the first 2 forms only. Yes, I know the return false prevents anything else, I'm getting to that.
With the return false in, it will submit the 2 forms. Removing return false only processes the form named Test1 and not the other 2.
I've shown code for attaching to the click event hoping that I could sneak my submits in on that, then let Chrome carry through to the submit function, but that doesn't work either.
I would like to allow the user to be able to use the Enter key in lieu of the submit button on a page that has several forms.I'm assuming that toaccomplish that I need to detect which form's elements are being edited (have focus?) and programmatically fire the submit button's action for that form.How do I do something like that?
____________________________________
f u cn rd ths u cn gt a gd jb n prgrmmng
How can I use jQuery to submit multiple forms with different types, values, and actions? For example:
Code:
<form name="form1" method="get" action="submit1.php">
<input name="value1" type="text" value="">
</form>[code]....
Can I start the jQuery process from within a function when clicking on the submit button?
Seems to me this would be a fairly common situation (if not commonly asked and answered), but the posts I did find about this subject didn't seem to
Given this basic code:
<form id="form" action="">
<input id="submit1">
[code]....
I'm simply trying to get one form's submit button to submit another form.. Just can't seem to figure out why it does not work.. Could anybody take a look?Click Here
$(document).ready(function(){
$('#submit1').click(function(){
$('#form2').submit();
[code]....
I'm trying to get a form submit working for all browsers, and I am using document.forms['formname'].submit().
However, despite having 'formname' set on the forms in both the name and id properties, Safari 3 will not submit the form correctly; when I debug, $_POST is empty. IE, FF both work here fine. If I use document.forms[0].submit() it works correctly, but this code will be working in a dynamic site where I can never be sure at what index a given form will reside. I can make it work using document.getElementById('formname').submit(), but that does not work with js turned off, and I need this to work with js on/off.
I want to make few forms but 1 submit button. I want to do 1 page, 5 forms, 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
View 2 Replies View RelatedI am working on single form divided into multiple pages using <div id="">. I am using next and previous buttons <input type="button"> to navigate between these pages but I am unable to validate each page before moving to next page using next button.
I am displaying next page form by using "element.style.display = 'none' & element.style.display = 'block' " method.
How to with validation on the current page before moving to next page.
I am adding my code below:
I've many dynamic form on my current project. One if them have a two radio button, acting a little bit like tabs. If you select the first radio, the end of the form change to display the "branche #1", and if you select the second radio button, the end of the form change to display the "branche #2".
Let recap with dummy code:
And now I will have to make 3 validations:
1) The first one for the common field.
2) The second one, if buyer is selected.
3) The third one, if seller is selected.
So the code should look like:
But is seem that only my common fields get validated. How should I handle that situation ?
I'm new to javascript and have stumbled yet again. Currently, my website has a form where you can type in your name, and generate a url.
Code:
<script>function updateURL() {
document.getElementById("theurl").innerHTML = '<a href="http://www.website.com/'+document.input.usersname.value+'/index.html">Here is the first link!</a>';
}
[Code]..
First, if I wanted to create an identical form and button, but with a different url (index1.html instead of index.html), do i just need to add numbers to the "updateURL();" parentheses on both the new input type=button, and the function script?
Second, if I can make this 2nd form and button, how can I make the 2nd input type="form" automatically mirror whatever is typed in the first input type="form"? Whether this be by button onClick, or live as they type it, it doesn't matter. I don't want to bypass the 2nd form however because I want to give users the option to erase the automatic mirrored text and put in a different name if they would like.
This is a ? about Ajax, PHP and form processing. When I submit the form further below, nothing happens I didnt set the form-"action" to anything. I left it out, to make the form submit to the same page, so I can validate on the same page too (Which is not made yet, as youll see. The form does work fine when I used in a "normal php script", but when I include it using Ajax, the form doesnt submit after it has been sent to the page.
Anyone knows what is going on, and what I can do to make it work? I guess it must be the action attribute of the form which is wrong, but I dont understand that since i made the form submit to itself, by leaving out the action attribute entirely.
I have two links on a page, which calls a javascript function, opening a xmlhttprequest: I have only shown one of the forms, as they are almost similar, but there are two forms, in the real page, which displays depending on the link selected.
[Code]...
I am running into a problem, that no one else in the world seems to have. When I make a form and submit the page is refreshed, or rather redirected to a state with the values filled after the ? [URL]
I have found solutions that have worked for other people, none of them work for me. I have tested my forms on multiple browsers on multiple systems and the problem persists.
Here is one example of my code where this happens.
<script type="text/javascript">
function checkCC(myForm)
{
var ccType;
var ccLength;
[Code].....
How do I get this to not happen? I've tried almost every fix I could find that worked for other people none have worked for me.
i have a table with three columns , quantity and rate amount.when user puts in quantity, and rate their multiplication is given in amount. and then these amounts will be added and total will be given.in the table you can add and delete rows dynamically.
View 5 Replies View RelatedI have a page which displays a list of resources in the database. For each of these resources I have a comment form. I am using jQuery form plugin to submit the form through ajax. After submitting I want to display the comment which was just submitted w/o reloading the page. But how do I know which form was submitted? I attach the resource ID as a GET variable to the action url of the form. If I can get the action url then I think I'm saved.
View 4 Replies View Related[URL] that is the code in all its basic form (just stripped out other html). I am trying to modify the form actions of the 3 forms when i click on the tabs at the top of the page. but only the action of the delete form (id=form-horse-delete) gets modified. the other 2 forms do not change. i am not sure what the problem is. in IE8, if i have the jquery modifying the action of the 2 forms (add/delete), it gives a JS error. if i take out the add/delete in jquery, there is no JS error.
View 3 Replies View RelatedI have a page with 2 product forms to add to shopping cart each form has the same fields.
when someone changes one of the dropdown boxes depending on the size it is to change the price to a certain value. This works ok whan you only have one form but now that there is two forms. When you change the second form dropdown box it changes the price on the first product.
OnChange='if (this.value<=16)ChangeHiddenPrice(90);'
I suspect it has to do with how i reference the form field
function ChangeHiddenPrice(newprice) {
document.getElementById('PRICE').value=newprice;
}