I have a php page with java script embed in it, i have 3 forms in a single page ... namely form1, form2, form3 . form 1 and form2 have a text box , these text boxes get input from users. Now my task is to get the value of these 2 tex boxes in form3 when the user click the submit button, so that i pass the values in those text boxes to next page for calculation.
I tried the following code in form3 but it result in vain :
I am working on single form divided into multiple pages using <div id="">. I am using next and previous buttons <input type="button"> to navigate between these pages but I am unable to validate each page before moving to next page using next button.
I am displaying next page form by using "element.style.display = 'none' & element.style.display = 'block' " method.
How to with validation on the current page before moving to next page.
I am adding my code below:
I have a JSP page with several forms on it. Some of these forms are
generated dynamically, and each of them submits some information to a
database.
Handling one form is easy, as I can simply make the form post to
itself, and handle the
data using a single bean. Since I have multiple forms, I now have a
problem. Several of the forms on the page handle the same type of data
(same input names), and a 'setproperty *' call for each of the form
beans would change data in several beasn, not just the form/bean that
sent the data.
I am attempting to write a separate JSP with a single bean that
handles a form submission. However, I'm not sure how to make this page
go back to the referring page from which the data was submitted.
It doesn't appear to be possible to validate multiple forms on a pages that only has a single <form> tag, using the JQuery Validation Plugin offered by Jörn Zaefferer. The reason I need to do this is because my pages are created with ASP.NET whose architecture generally calls for a single page-wide <form> tag. In my designs, I'd like to submit my data using a custom ajax call to a web-method, and link it to a click event on a button.
Below is an example:
<!
DOCTYPE
html
PUBLIC
"-//W3C//DTDXHTML1.0Transitional//EN" "[URL]" >
<
html
xmlns
=
"[URL]"
> .....
I'm not sure that I fully understand the documentation for the Validation plugin, but it doesn't seem like this is possible, as the plugin seems to need a <form> for each form.
I have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
I have made a site with 5 pages, each page contains a form. Each form is a checklist with a dropdown to choose an answer for each individual item.
Here is a same of the form code:
I am trying to write a script that will be called with onclick event from the "Next" button. This script will collect all the "notOK" option value/names and send them to a document, concatenating the info from the next forms until a single report is created with a list of all the "notOK" values. One the user gets to the end of the last form, there will be a submit button which sends the entire report to a specific email address.
Here is the script I have so far, which pulls the "notOK" values for each page:
This piece of code works great for an individual page, but I need to expand it to send the data to a report instead of window.alert, and I need to add some way of concatenating the data from each form to a single page, doc, etc.
I have a single form on a single page with some js that is supposed to take the first and last name entered and add them to the select list. There seems to be some kind of communication stop between the js and html, because nothing happening.
Here is the code:
<script language="javascript" type="text/javascript">
/* <[CDATA[ */
function Member (){
this.lastName = "";
this.firstName = "";
this.position = "";
this.phone = "";
this.email = ""; .....
I've many dynamic form on my current project. One if them have a two radio button, acting a little bit like tabs. If you select the first radio, the end of the form change to display the "branche #1", and if you select the second radio button, the end of the form change to display the "branche #2".
Let recap with dummy code:
And now I will have to make 3 validations:
1) The first one for the common field.
2) The second one, if buyer is selected.
3) The third one, if seller is selected.
So the code should look like:
But is seem that only my common fields get validated. How should I handle that situation ?
I know that this must be quite trivial to most of you, but my skills
in JavaScript are weak.
I am looking for a way to validate all forms throughout a website
through one validation script.
How do I determine the form's name (or id) value to implement
conditional validation?
i.e. if (form1) { validate like this }; if (form2) { validate like
this };
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
Filename: summary.htm
Supporting files: back.jpg, edge.jpg, links.jpg, logo.jpg, summary.css
-->
Code:
<title>Conference Summary Page</title>
<link href="summary.css" rel="stylesheet" type="text/css" />
<script type="text/javascript">
var searchString = location.search.slice(1);
var formString = searchString.replace(/+/g, " ");
var dataString = unescape(formString);
data = dataString.split(/[&=]/g);
</script>
</head>
<body>
<div id="links"><img src="links.jpg" alt="" /></div>
<div id="head"><img src="logo.jpg" alt="CGIP Annual Conference" /></div>
<div id="edge"><img src="edge.jpg" alt="" /></div>
<div id="main">
<p id="intro"><b>10th Annual Conference of Computer Graphics and Image Processing</b><br />
University of Colorado, Boulder<br />
March 3 - March 7<br />
Conference Fee: $145
</p>
<table id="summary"> .....
I have developed one project and in that i have taken two css now i want to add jquery effects in that, But my display is not properely adjusted and extra enlargement is done so how i can add jquery in my php project without affecting another effect? And one more thing where i can get the jquery effect codes?
View 1 Replies View RelatedHow to use multiple .js files in a single web page??Is it possible to use both external .js file and inbuilt java script functions in a single page?
View 1 Replies View RelatedI have this script which is set to generate random anagrams of my name in rotation which works fine, but I can't work out how to put multiple instances of it on one page.
The code is:
And i'm calling the function using:
I am code a printing report web application, the report is simplest display on HTML form and using window.print() to print it out.
The report can be vary to 2 or more page depend the no. of record retrieved. I have a idea to print multiple page with user single click. Any method to make it real?
I am having trouble creating two slideshows on a single page. I know that there is a problem of one slideshow overriding the other, but I can't figure out what to change or where in order to make both functional. I've seen other posts related to this, but those I've tried don't work for me. Here's my partial code...I only included the parts I think are necessary.
<script language="JavaScript1.1">
var slideimages=new Array()
var slidelinks=new Array()
function slideshowimages(){
for (i=0;i<slideshowimages.arguments.length;i++){
slideimages[i]=new Image()
slideimages[i].src=slideshowimages.arguments[i]
} } .....
My site's working perfectly in the other browsers, and when I delete line 28 (see below) it works in IE but not exactly how I want. Is there a way to retain two jquery references on a single page in IE?
This is the head section of my code:
I have about 10 JQuery Books and they all talk about using Ajax(JQuery Load function) to insert either an HTML page or fragments of an HTML page into another page.
However, amazingly none of these books mentioned getting multiple items using the same function(document.ready).
Here is what I mean. I have a document.ready function which I use to get specific content from a page. However, to get additional items, I need to set up additional document.ready function.
So if I was retrieving 3 sets of content from a page, I will set up my script like this:
Code:
And the HTML
Code:
Is there a leaner better way to do this? Again all the books tells you how to grab a content, which I have done but do I have to create a new function for each item?
I'm new to javascript. I want to make multiple adjustable countdown timers on a single page. I've got a single timer working:
Code:
<script type="text/javascript">
var sec = 10; // set the seconds
var min = 00; // set the minutes
function countDown() {
sec--;
if (sec == -01) {
[Code]...
The page I'm working on has a week's worth of data blocks like this - pseudo code & markup:
<form 1>
field a 1
field b 1
submit 1
response 1
</form 1>
<form 2>
field a 2
field b 2
submit 2
response 2
</form 2>
and so on for either 7 or 14 days.
I'm trying to conceptualize an prototype based js function that can handle all the forms to submit the data to the backend.
What I have now, that works is like the following
Event.observe(window, 'load', ajax_init, false);
function ajax_init () {
Event.observe('form_1', 'submit', send_form_1);
Event.observe('form_2', 'submit', send_form_2);
}
function send_form_1 (e) {
$('response_1').innerHTML = 'doing the deed for 1!'
var myAjax = new Ajax.Updater('response_1', 'ajax_server.php', {method: 'post', parameters: Form.serialize(this)});
Event.stop(e);
}
function send_form_2 (e) {
$('response_2').innerHTML = 'doing the deed for 2!'
var myAjax = new Ajax.Updater('response_2', 'ajax_server.php', {method: 'post', parameters: Form.serialize(this)});
Event.stop(e);
}
But, in my mind, there has to be a way to streamline this so that one function 'send_form' can do the magic rather than having multiple iterations of it. I was looking at the bind functions in prototype, but perhaps it was the late night and lack of coffee, but I wasn't seeing the application of bindAsEventListener in this context.
I'm struggling with a script for an e-commerce site.When the user clicks the add to cart button they are currently taken to a PHP shopping cart page, but the client wants them to stay on the same page after they press the button and get notified that an item has been added to the cart.The add to cart button is a form submit button, because there is also a quantity field for each item. I would have cracked this by now but there are multiple add to cart buttons on each page and when I submit the form only the data from the first form in the page is sent to the cart page.Here's a dummy version the JavaScript:
Code:
$(document).ready(function(){
$('.subbtn').click(function(){
$('<p id="add">Added To Cart</p>').insertAfter(this).fadeOut(3000);[code].....
At the moment I've got it set so that AJAX returns information to the page (just so I know it works), but this won't happen on the actual page.So, as far as I can tell, I need a way of POSTING $(this).parent(); $('[name=quantity]').val(), but I can't seem to find the correct syntax.
I have a page which displays a list of resources in the database. For each of these resources I have a comment form. I am using jQuery form plugin to submit the form through ajax. After submitting I want to display the comment which was just submitted w/o reloading the page. But how do I know which form was submitted? I attach the resource ID as a GET variable to the action url of the form. If I can get the action url then I think I'm saved.
View 4 Replies View RelatedI have a page with 2 product forms to add to shopping cart each form has the same fields.
when someone changes one of the dropdown boxes depending on the size it is to change the price to a certain value. This works ok whan you only have one form but now that there is two forms. When you change the second form dropdown box it changes the price on the first product.
OnChange='if (this.value<=16)ChangeHiddenPrice(90);'
I suspect it has to do with how i reference the form field
function ChangeHiddenPrice(newprice) {
document.getElementById('PRICE').value=newprice;
}
I see it working in the demos I found this documentation
You can avoid having to duplicate the plugin settings by modifying the defaults. Use $.validator.setDefaults({…}) to override multiple settings at once.
But I do not understand what I have to do to make this work
I have a problem in form submit.
I have multiple forms in my page with different name, instead of submit button i have images, on click of image i am submitting the form. but while submitting its giving Object doesn't support this property or method error:
I tried "sticky, with arrows" (4th one) of cluetip-1.0.4 package. It's working fine. But when I used the same in multiple links in same page, only one is working.
At present the html code is :