I would like to allow the user to be able to use the Enter key in lieu of the submit button on a page that has several forms.I'm assuming that toaccomplish that I need to detect which form's elements are being edited (have focus?) and programmatically fire the submit button's action for that form.How do I do something like that?
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f u cn rd ths u cn gt a gd jb n prgrmmng
I am trying to change each forms .submit function like so (below) but each submit button gets the function of the last iteration. I want each form to have a different submit function without using onclick events.
var x = document.getElementsByTagName("form");
for(i=0; i < x.length; i++){
var ele = x[i].elements;[code].....
I haven't really used javasript in my site so far, but I think I need it here. I have a large text box where the user can enter several lines of text. The problem is, that I want the enter key to start a new line when the user is entering text, rather than submitting what has so far been entered. What I've got so far has stopped the enter key from submitting, but has also prevented it from starting a new line:
<form action='aaa.[php]' method='POST'>
<input type='text' name='text' onkeydown="if (event.keyCode==13){return false}" >
<input type='submit' name='zzz' value='Submit'>
This completely disables the enter key. How to make it so that the enter key starts new lines?
I have form within a form and I would like to disable the submit button in the inner form.Currently I have this for some other forms, and it works just finePHP Code:
<form method="post" action="index.php" onkeypress="return event.keyCode!=13">
<input type="text" name="first" value="" />
<input type="text" name="last" value="" />
[code]....
If I disable JS is running everything as I need. (but it isn't my objective)
<form id='RequestData' action='request.php' method='post'>
<button type='submit' name='par[1]' value='V1'>
<button type='submit' name='par[2]' value='V2'>
[code]....
Script work, but send wrong data, always send to request par[3]='V9' how I can do to send data' from buttons which I click ?
Myobjective it data:
par => array(
[1] => 'V1'
)
only one value of array PAR
I'm trying to use a single submit button to submit 3 forms on a single page. 1 form I use and process, the other 2 are sent to other sites.
Everything works great except in Google Chrome (and Safari) due to some restriction/bug in WebKit.
Code:
This works perfectly fine in IE and FireFox, but in Chrome - as it sits, it will submit the first 2 forms only. Yes, I know the return false prevents anything else, I'm getting to that.
With the return false in, it will submit the 2 forms. Removing return false only processes the form named Test1 and not the other 2.
I've shown code for attaching to the click event hoping that I could sneak my submits in on that, then let Chrome carry through to the submit function, but that doesn't work either.
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
How can I use jQuery to submit multiple forms with different types, values, and actions? For example:
Code:
<form name="form1" method="get" action="submit1.php">
<input name="value1" type="text" value="">
</form>[code]....
Can I start the jQuery process from within a function when clicking on the submit button?
I have a form that has 3 submit buttons with 2 input fields. The first input field is a search field that allows the users to search against the database for certain names that are found and not found.[code]...
View 1 Replies View RelatedI have a form with several submit buttons. I've used $(#myform).ajaxForm(options) method to make the form submittable with ajax. the problem is that no matter what button I click the form data is the same and <input type="submit"> element is not included into the form data, as if it were not a "successul control". so at this point form doesn't work as expected. is there a way to convey information of which button was clicked with the form plugin?
View 4 Replies View RelatedI am setting up a text search with 3 search buttons to allow 3 different searches from the one text box. Each search has different values for the 2 hidden elements. So far I've got the 3 submit buttons working with the below code but I can't figure how to get the hidden values to be inserted. For each of the 3 different submits I need to tell javascript what the 2 hidden values are.
<SCRIPT language="JavaScript">
function OnSubmitForm()
{
if(document.pressed == 'questions')
{
[Code]....
I need to submit two forms using a single submit button. What's ur suggestion. I found that JavaScript is the only way to go here, right?
View 1 Replies View RelatedHow can one submit multiple forms at a time. At the same time the values must get Forwarded another page.
View 4 Replies View RelatedI have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
I am trying to add an additional submit button to a form that has a separate action. This is for a shopping cart. The button I am trying to add is a "Preview" button. Which will have a different action then the "Add to Cart" button. Right now it works but after the "Preview" button is clicked the "Add to Cart" button will use the action that the "Preview" button is using. This is the script I am using for the "Preview" button.
var productPreviewForm = new VarienForm('product_addtocart_form');
productPreviewForm.submit = function() {
if(this.validator.validate()) {[code]....
I have a form with several fields.
Each field can be modified:
- individually (one submit button next to the field)
- globally (a submit button at the end of the form).
Before submitting the form, a validation needs to be performed.... so I added: onSubmit="return isValid()".
If the validation does not pass, the form needs to be shown with the data previously entered by the user.
Now, I haven't even come to the previous problem I have mentioned..... my problem is that if a field is empty, the function isValid() recognize it (message sent) .... but the reDirect function is performed!
I have a complicated page with several submit buttons. I don't want to
create multiple forms because much of the input is shared and the code
is getting very ugly. However I would like to determine which values
will be submited.
Here is a simplified example that may better illustrate my question.
Or maybe there is a better approach...
<SCRIPT language="JavaScript">
function submitform1()
{
document.myform.submit();
}
function submitform2()
{
// logic to submit only name parameter
document.myform.submit();
}
function submitform3()
{
// logic to submit only address parameter
document.myform.submit();
}
</SCRIPT>
<form name="myform" action="#">
<TABLE>
<TR><TD>Name</TD><TD><input type='text' name='Name'></TD></TR>
<TR><TD>Address</TD><TD><input type='text' name='Address'></TD></TR>
<TR><TD>Phone</TD><TD><input type='text' name='Phone'></TD></TR>
<TR><TD></TD><td><input type="button" onClick="submitform1()"
value="submit all variables"> </TD></TR>
<TR><TD></TD><td><input type="button" onClick="submitform2()"
value="submit just name"> </TD></TR>
<TR><TD></TD><td><input type="button" onClick="submitform3()"
value="submit just address"> </TD></TR>
</TABLE>
</form>
I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedI want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
View 2 Replies View RelatedI have a simple form that works via a suggested results system [URL]
While in firefox the go button is greyed out and enter doesn't submit the form in IE pressing the enter key submits the form.
Is there any way with a bit of javascript to stop IE from doing a form submission on enter but only for this form (since there are many more on the site)
<form action="index.php" method="GET" name="qsform" id="qsform"><input type="hidden" name="p" id="p" value="compdetails" style="border:1px solid #000000;" /><input type="text" name="quicksearch" id="quicksearch" value="Find Company" style="border:1px solid #000000;" onFocus="clearText(this)" onBlur="clearText(this)" /><input type="hidden" name="cid" id="cid" value="" style="border:1px solid #000000;" /> <input type="submit" name="go" id="go" value="Go" disabled="true" /></form>
I have a form that I built, and I replaced the submit button with an image.When you click the image, it calls the .submit() jQuery function and submits the form.Because I am not using the normal submit input button, hitting enter in most browsers won't submit the form.I think that users are used to this happening, so I would like to replicate this.Can I trigger the .submit() function when the enter button is hit?
View 2 Replies View RelatedI am using jquery with the cookie plugin and I have multiple image buttons that can hide/show multiple elements. My question is how can I add a cookie to this code to remember whether each separate element is opened or closed?
The code,
$(document).ready(function() {
// choose text for the show/hide link - can contain HTML (e.g. an image)
var showText='<div class="expanddown"></div>';
var hideText='<div class="expandup"></div>';
// initialise the visibility check
var is_visible = false;
// append show/hide links to the element directly preceding the element with a class of "toggle"
$('.toggle').prev().append('<a href="#" class="togglelink">'+hideText+'</a>');
// capture clicks on the toggle links
$('a.togglelink').click(function() {
// switch visibility
is_visible = !is_visible;
// change the link depending on whether the element is shown or hidden
$(this).html( (!is_visible) ? hideText : showText);
// toggle the display - uncomment the next line for a basic "accordion" style
//$('.toggle').hide();$('a.toggleLink').html(showText);
$(this).parent().next('.toggle').slideToggle('fast');
// return false so any link destination is not followed
return false;
});
});
HTML,
<a class="togglelink" href="#"></a>
<div class="toggle">
Content
</div>
I have a form with a bunch of selects and a single text input.Form data is sent via $.post whenever the inputs are changed, so a submit button isn't needed. The form does contain one regular button (using the button tag, not the input tag). The button shows a jQuery UI dialog when clicked.
If you press the enter key in the text field, the browser submits the form but it also acts like you clicked the button (the dialog appears). That makes no sense to me. Why is this happening and how can I stop it?I've already tried adding a few things to the form's submit handler, but they don't make a difference.
$('#filters').submit(function(event) {
event.preventDefault();
event.stopPropagation();
clearTimeout(window.refresh_timer);
[Code]....
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedI need to have two separate forms, each using a different PHP script that I cannot modify to process them. I need to have both of these forms share the same submit button. Here is a simplified version of the html. I will also need simple validation on these and know Ill have to do all this via jQuery's AJAX function.
View 7 Replies View RelatedI'm trying to search for the correct code to make my form work. I have 3 select boxes - one with 2 options, one with 8 options, and the last with 2 options... All of this adds up to 32 different url paths. Can anyone tell me how to get this done?This is what I have so far: (and yea, I know I suck... I honestly have absolutely NO clue)
<html>
<head>
<script>
[code]....