Safari 3 Will Not Document.forms Submit The Form Correctly
Feb 23, 2009
I'm trying to get a form submit working for all browsers, and I am using document.forms['formname'].submit().
However, despite having 'formname' set on the forms in both the name and id properties, Safari 3 will not submit the form correctly; when I debug, $_POST is empty. IE, FF both work here fine. If I use document.forms[0].submit() it works correctly, but this code will be working in a dynamic site where I can never be sure at what index a given form will reside. I can make it work using document.getElementById('formname').submit(), but that does not work with js turned off, and I need this to work with js on/off.
I want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
I'm simply trying to get one form's submit button to submit another form.. Just can't seem to figure out why it does not work.. Could anybody take a look?Click Here
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){ var allOk = true; $(this).find("*[validation]").each(function(){[code]....
I have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
I want to make few forms but 1 submit button. I want to do 1 page, 5 forms, 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
This is a ? about Ajax, PHP and form processing. When I submit the form further below, nothing happens I didnt set the form-"action" to anything. I left it out, to make the form submit to the same page, so I can validate on the same page too (Which is not made yet, as youll see. The form does work fine when I used in a "normal php script", but when I include it using Ajax, the form doesnt submit after it has been sent to the page.
Anyone knows what is going on, and what I can do to make it work? I guess it must be the action attribute of the form which is wrong, but I dont understand that since i made the form submit to itself, by leaving out the action attribute entirely.
I have two links on a page, which calls a javascript function, opening a xmlhttprequest: I have only shown one of the forms, as they are almost similar, but there are two forms, in the real page, which displays depending on the link selected.
I am having a problem with the submit() method that is driving me nuts. I'm using document.form.submit() with large text fields (approx. 2000 characters) and am getting a "Invalid Syntax" error. If I do the same thing with a text field of under 1500 characters, it works fine.
Is there some size limit here that I don't know about?
I'm trying to make a simple IQ test using javascript and forms that allows me to calculate the questions answered correctly and give the user a message box with the results. I had it working but now can't seem to get it to work anymore.
Here is my code: <html> <head> <script language="JavaScript" type="text/javascript"> function calculate() { var iq=0 var days = document.IQtest.Q1[3].checked var time = document.IQtest.Q2[1].checked var sleep = document.IQtest.Q3.value var number = document.IQtest.Q4.value .....
Also, before when I had it working I couldn't get it to tell me that I had got the textbox questions correctly even when I had.
There are 3 buttons on a web page. On clicking each button a same popup window (say window1) opens up. Now there is another button on this popup window (window1), which further opens up to another popup window (say window2). On selecting some value from the 'window2', that value is passed onto the 'window1'. There is a 'Find' link on a 'window1', which calls a javascript function 'clicked()':
There are 3 buttons on a web page. On clicking each button a same popup window (say window1) opens up. Now there is another button on this popup window (window1), which further opens up to another popup window (say window2). On selecting some value from the 'window2', that value is passed onto the 'window1'. There is a 'Find' link on a 'window1', which calls a javascript function 'clicked()':
<head> <% Dim command command = Request.Form("hid");
[code]....
This full code works fine on my machine. But this code does not work properly when run on the client-side!, although the same server and the same deployed application is being accessed. There is no particular sequence/scenario but for eg.When say button1 clicked->window1 opens->window2 is opened->value selected->returned to window1->Clicked on Find-> clicked on Ok->returned on the main page.Then repeated the same scenario for say 3rd button. (Till now 'Find' link works fine).Now repeated the same scenario for 2nd button and here 'after' message is obtained but 'inside Find' is not printed!
I'm using inArray() to check an XML tag against an array called status[]. If the result != -1, then do one set of instructions, else, the item is 'available' so do another set of instructions. Each entry of my XML document has a <status> tag, which will contain one of 3 values, or a 4th option 'available'. I have an array setup called status['sold', 'pending', 'reduced']. If the <status>.text() is one of these 3 values, then we'll get the array position, if it's 'available' we should get -1.
When I run this in Firefox (3.6) & IE (8.0 or Comp Mode) it works fine. However, when I run this in Safari (4 or 5) & Chrome, it returns the value -1 for each of the entries. The 3rd, 5th, & 7th entries are all set to <status> 'sold' and inArray() should be returning a 0.
I have the following code and on it's own works fine, but I need to have it in a PHP while loop as there may be hundreds of records. This does not work, meaning it does not submit the form.
I am opening a new window using window.open. I need the new window to open on top of the parent everytime. I cannot use onBlur b/c the user will need to click back to the parent for information. I just need it to open on top everytime. I am using this line in the body <body onload="window.focus()" bgColor="#0077d6" ms_positioning="GridLayout">
The window.focus doesn't work everytime. I can open it and it may work. I will completely close the app, start it again and it will not work, but the next time it might. It is inconsistent. How do I get it to not give focus back to the parent after it opens? How can I get the parent to relinquish focus?
I've tried triggerHandler() and trigger() both, and the command runs fine if called from another event handler—the click event for that <a> works as desired.Console shows no errors, and as I said the other lines in (document).ready work fine, it's just this one thing that doesn't seem to run.
why would this command not process on (document).ready?
I'm not a JS person, so hopefully this'll be nice an easy .
The follwoing bit of code:
Code: <script language="javascript"> // if form exists , set cursor in first input field function focusonform() { if (document.forms[0]) { document.forms[0].elements[0].focus(); } else {window.focus();} } </script>
This appears to work fine on a page with no forms using Mozilla 1.0, IE6 on win2000. But NOT on IE6 on XP - I get the following message:
A Runtime Error has occured. Do you wish to Debug? Line: 70 Error: 'document.forms.0.elements.0'
I have some code on a page that will enable/disable a text box if a checkbox has been checked/unchecked and it seems to be working fine unless there is only one checkbox and one text box.
Here is the javascript:
function EnableCustLoyaltyNotes(x,y) { if (document.frmCustLoyalty.VoidLineID[x].checked || document.frmCustLoyalty.UnVoidLineID[x].checked) { document.frmCustLoyalty.Notes[y].disabled = false; } else { document.frmCustLoyalty.Notes[y].disabled = true; }}
A straight forward problem I think but my knowledge of JavaScript lets me down.
I am taking in a lot of input using a form. After preparing an email (FormMail.pl) I then use 'document.write' to create a new page with all the users details nicely formatted. This includes checking radio buttons, checkboxes etc.
Problem is as soon as I use the first 'document.write', the form and all its contents are undefined. I have moved some of them to variables for the time being but this is cumbersome.
I have a problem to access a hidden field by javascript. The name of the field has a dot in it. That's the problem. But I need that dot because it is a "Stuts Property".
I've been tryin to figure out why I am getting this error for some time now. Any ideas?
<script language="Javascript">
<!-- var lead_id = "<?php echo $LeadID; ?>"
if (lead_id > "") { var state = "<?php echo $row['State']; ?>"; var confirmer = "<?php echo $row['Confirmer']; ?>"; var day = "<?php echo $row['ApptDay']; ?>";
if (state == "MD") { alert("hi"); document.forms['form1'].state.options[0].selected = true; }}
//--> </script>
state is equal to MD so I am getting the alert "hi", but it breaks right there and gives me this error. document.forms.form1 has no properties heres my form tag:
This works in FF and IE9 but not in Safari (nor in Chrome), In Safari I see the portrait just fine but the cursor doesnt change when overing the image and clicking on it doesnt activate the link. What is the correct way to write this line?
I have tried this and it also doesnt work in Safari and Chrome:
I have a simple three-field form in a UI Dialog that, prior to POSTing, I need to validate using the jQuery Validation plugin.Currently, if the user clicks the form's Submit button (the form's action for the PHP form handling is the page with the link that opens the Dialog in the first place) with a field not properly filled out, the Dialog just closes.Clicking again on the link that opens the Dialog form will show the form with the error message(s) that the Validator generated on the previous click of the submit button.How can I keep the Dialog open and prevent a POST until the form validates?
I need to have two separate forms, each using a different PHP script that I cannot modify to process them. I need to have both of these forms share the same submit button. Here is a simplified version of the html. I will also need simple validation on these and know Ill have to do all this via jQuery's AJAX function.
