This is a ? about Ajax, PHP and form processing. When I submit the form further below, nothing happens I didnt set the form-"action" to anything. I left it out, to make the form submit to the same page, so I can validate on the same page too (Which is not made yet, as youll see. The form does work fine when I used in a "normal php script", but when I include it using Ajax, the form doesnt submit after it has been sent to the page.
Anyone knows what is going on, and what I can do to make it work? I guess it must be the action attribute of the form which is wrong, but I dont understand that since i made the form submit to itself, by leaving out the action attribute entirely.
I have two links on a page, which calls a javascript function, opening a xmlhttprequest: I have only shown one of the forms, as they are almost similar, but there are two forms, in the real page, which displays depending on the link selected.
I want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
I am working on a project that relies heavily on AJAX calls, they are done in dozens of places. There are a number of places where I would want to prevent the user from submitting information multiple times (form submissions etc ). I am trying to think of the best way to accomplish this.
I could simply disable the element that starts the AJAX call upon the first click and re-enable it upon completion of the call. I have also seen examples of developers using a class to handle ajax calls that store an identifier for the call and if it is in progress any new calls with the same identifier will be ignored.
sending a form from a page to greybox. Currently the script doesnt seem to be sending the form. With the current code, the greybox pops-up for a second with no content then disappears. Here are my scripts:
<code removed at poster's request>
Here is the lightbox I am using: http:[url]....Would it be easier to switch to a different lightbox?
I'm simply trying to get one form's submit button to submit another form.. Just can't seem to figure out why it does not work.. Could anybody take a look?Click Here
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){ var allOk = true; $(this).find("*[validation]").each(function(){[code]....
I have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
I'm trying to get a form submit working for all browsers, and I am using document.forms['formname'].submit(). However, despite having 'formname' set on the forms in both the name and id properties, Safari 3 will not submit the form correctly; when I debug, $_POST is empty. IE, FF both work here fine. If I use document.forms[0].submit() it works correctly, but this code will be working in a dynamic site where I can never be sure at what index a given form will reside. I can make it work using document.getElementById('formname').submit(), but that does not work with js turned off, and I need this to work with js on/off.
I want to make few forms but 1 submit button. I want to do 1 page, 5 forms, 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I'm having trouble submitting a form using a link. I have a table that lists a bunch of data, and I want to allow users to edit the data directly in the table. The user can click the "EDIT" link, which makes jQuery replace the appropriate <td> html with <input> elements. Then, when the user clicks the "SAVE" link, it should submit the form, but it doesn't.
I've literally tried everything. Read 26 tutorials, interchanged code, etc. My validation functions all work. My AJAX functions work (tested manually using servlet URL's). The second servlet validates the reCaptcha form that's generated on my webpage. After the form is validated, even if everything's correct, nothing happens upon clicking submit. I even have an alert pop up if with the captcha result, just for middle-layer debugging purposes.
I want to do all of my validation clientside; none serverside. However, going to be tough if I can't get my god damn form to submit. I've been puzzled by this for close to 36 hours straight. I can't see, and I'm going to get some rest and hope that there is some useful insight on my problem when I return.
have the follow jwplayer i've got a link that loads the video into the player fine but now i am trying to add another one that load with the hd optionhere the single one works fine
I want to use a text link to submit a form and get the POST values instead of an ugly submit button which is difficult to style. I thought it would be simple but I can't do it - whats the problem with this .js?
<a href="#" onclick="document['form1'].submit(); return false" >search</a> have written the follwoing script for making a textlink to submit a formit works fine. with this i want to pass a flag or a value and retrived at the serverside
within this page that has been created, there is an AJAX tree folder which calls another page to be loaded into a DIV by AJAX again. Code:
[Code]...
I don't know why it doesn't work because the page has been loaded with the JS file, but as soon as the link is added afterwards it doesn't work. I take it this is because it doesn't know where to find the JS, but how can I overcome this?
and to be honest, not a whiz with javascript either).i am trying to submit a form through a link. the form is generated through my shopping cart. the form has a submit buttion with an onsubmit="return check_add_to_cart(this, false)" attribute for validation. the function resides in an externally linked .js file. that all works fine.what i want to do is on the same page have a link that triggers the form submission. I am using this code:
I am using a script so that a url selected from a dropdown is given control using the window.location method. This depends on the onsbumit definition attached to the action statement. All that works well. However, I have other checkboxes etc. on the form, and their values are no longer submitted when I used this onsubmit function. Is there a way I can get them to work... Here is the script and the form:
I am currently using jquery .post ajax code to submit a form.
The problem is that when I click on submit it takes me to the php file page. Which is blank.
I don't want this... this functions just like if I made the form in html meaning when submit it takes you to the .php file well opens it in a page.
I want to use ajax that when you click submit it submits the form and then shows a message on screen.
When I click the submit button my message gets shown on the screen saying it submittedsuccessful then with at least 2 seconds it sends the user to the php file meaning opens the page up in the browser not a new tab or new window but sends the user to the php file. Which I don't want it to happen. So the page is blank.
I used the .post and serialized the form. Is this the right thing to do?
I don't want to send the user to the php file. Just use ajax and check if it updated the database and if so send either 1 or 0 depending if it went threw then the form page willreceivethat data and then fade in a message saying either error or success depending what went on.
I would like to know how you can use jquery ajax to submit a form without refreshing the page. I do know about the serialization function but would like to see an example of what is submit().
I currently tried to get my form working but but can't get it to work meaning to submit something from the form.
I have a general idea of how this works but i need further explanation. I have a form that needs to post into one list and then post into another list as well.Here is the ajax code and html code:
