JQuery :: Get A Link To Submit Form With Other Script Attached?
Jul 13, 2009
and to be honest, not a whiz with javascript either).i am trying to submit a form through a link. the form is generated through my shopping cart. the form has a submit buttion with an onsubmit="return check_add_to_cart(this, false)" attribute for validation. the function resides in an externally linked .js file. that all works fine.what i want to do is on the same page have a link that triggers the form submission. I am using this code:
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
I'm having trouble submitting a form using a link. I have a table that lists a bunch of data, and I want to allow users to edit the data directly in the table. The user can click the "EDIT" link, which makes jQuery replace the appropriate <td> html with <input> elements. Then, when the user clicks the "SAVE" link, it should submit the form, but it doesn't.
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I want to use a text link to submit a form and get the POST values instead of an ugly submit button which is difficult to style. I thought it would be simple but I can't do it - whats the problem with this .js?
I want to 'style' all links on my site with a variable for random colors. I got the variable for the random colors up and running but i can't figure out how to implement the variable to the css.
<a href="#" onclick="document['form1'].submit(); return false" >search</a> have written the follwoing script for making a textlink to submit a formit works fine. with this i want to pass a flag or a value and retrived at the serverside
I am using a script so that a url selected from a dropdown is given control using the window.location method. This depends on the onsbumit definition attached to the action statement. All that works well. However, I have other checkboxes etc. on the form, and their values are no longer submitted when I used this onsubmit function. Is there a way I can get them to work... Here is the script and the form:
This is a ? about Ajax, PHP and form processing. When I submit the form further below, nothing happens I didnt set the form-"action" to anything. I left it out, to make the form submit to the same page, so I can validate on the same page too (Which is not made yet, as youll see. The form does work fine when I used in a "normal php script", but when I include it using Ajax, the form doesnt submit after it has been sent to the page.
Anyone knows what is going on, and what I can do to make it work? I guess it must be the action attribute of the form which is wrong, but I dont understand that since i made the form submit to itself, by leaving out the action attribute entirely.
I have two links on a page, which calls a javascript function, opening a xmlhttprequest: I have only shown one of the forms, as they are almost similar, but there are two forms, in the real page, which displays depending on the link selected.
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() { $("#ARTransferForm").submit(function() { var msgsCount = 0;[code]....
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I am trying to get the plugin working so I can submit from a link (using meta plugin) but it don't seem to be working $(document).ready( $("#submitregister").click( function() { $("#com-createForm").validate({ meta: "rules" } ); }););
This works from a submit button : $(document).ready(function(){ $("#com-createForm").validate({ meta: "rules" } ); });
Is there a way to validate a form using a link and NOT a submit button? I have a link on my form that I'm using as a submit button to do some ajax posting. However, I need to validate some of the input fields before the data is sent to the database.
I have a requirement that when a particular link is clicked, it submits back to the server. This is the same as clicking on a submit button. But the submit button is a link.
I have been trying to use jquery function .html() but I noticed that it clears all events that are attached to the selectors. Is there a way around this issue? I want to change the content and keep the events.
I am aware of live and delegate functions but I am making changes to an external page so I do not have control over attaching events or knowing what they are at the first place.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
Is it possible to read a web page on some web site that contains a form. Then identify the fields in the forms. Then fills the fields with my data. and then submits the form as it submitted normally. I need to do this to automate for my final proyect , i need to fill many web pages remotly
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
I have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
I'm trying to get an upload popup working with the jQuery form plugin[URL].. When I click a link I load a form html from the server and add it to a container div by setting the div's html attribute. I then attach a submit handler to the form so I can call the ajaxSubmit function of the form plugin.
Malsup's most excellent and comprehensive Form plugin has me completely stuck on just one thing.Take a look at this: http:[url]....At the bottom are a variety of submit buttons, and when you click one, it knows which one has been clicked.And I've been through the js and the source and the examples and I can't figure out how the bleep it's done!I'll tell you why I'm asking, then perhaps you can probably tell me I'm doing it wrong anyway!Let's say a blind person logs in, and want to edit their presets.I don't want the form to be too complex or clever or ajaxy, as screenreaders don't like that, so it just iterates through as many presets as they have, and populates a form with edit boxes.But there's no point "pushing back" 29 unchanged items just to edit one row.
So my idea was I'd just "fieldSerialize()" the details of the row that was currently being edited and submit that to my little php routine that updates the db. Then they can do a refresh just to hear the list again.The js looks like:
$(document).ready(function() { $('#myForm').ajaxForm(function() { var queryString = $('#myForm').formSerialize(); [code]....
All works fine like that. But if I change line 3 to: var queryString = $('#myForm :button').fieldSerialize(); it doesn't work. I've also tried:
Maybe I should just generate as many separate forms as there are presets, but then I'm going to need as many ready(function)'s as there are rows, which is going to be very messy.
I have a php form and it has 3 submit buttons namely "delete" , "update_quantity" and "place_order".They all work fine but I want to build in a check for each one just in case the user click one of the buttons by mistake.So Each one must have a different message like for delete it must be, "Are you sure you want to delete Record nr ......" OK or Cancle. And for update " Are you sure you want to update Quantity to....." OK or Cancle.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code: What I've tried so far is like this: savedSubmit = document.inputs.submit; document.inputs.submit = None; then later: document.inputs.submit = savedSubmit;
