I have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
$(document).ready(function(){
$("#myForm").validate();
});
[code]....
This is my form, When user click the <b>YES and checked the check </b>box then only I want to enable the Prepay by Card button. For this situation, what is the jquery snippet. I have tried somthing like:
$("#SubmitCard").attr("disabled", "disabled");
But the thing is, I want to put the and Condition match. For this situation, I don't know how to write the jquery snippet
<table style="border: 0px solid rgb(0, 0, 0);
width: 485px; height: 45px;"><tbody>
<tr style="width: 20px; height: 5px;">
<td width="78">Pay by Card </td>
<td width="78"><b><span style="cursor: pointer;" id="yes">Yes</span></b></td>
<td style="cursor: pointer;" width="315"><span id="no" style="cursor: pointer;">No</span></td>
</tr> .....
I am unable to submit the form after validation. I have tried various ways to submit but my form action is not honored. [URL]...
View 1 Replies View RelatedI have this create user form, and I'm checking if the email hasn't been used already. This works... But what my problem is, that if the email has not been used before, it will not send the form, while I return true.
I've tried to use $(this).submit, but that will just make it loop and never stop.
So basically: ifdata.is_dublicate = true show error else data.is_dublicate = false submit the form
$("#add_user").submit( function(){
var error = $('#dublicate');
$.post(domain.com/check_dublicate_email', {email: $("#email").val()},
[Code].....
I have a simple three-field form in a UI Dialog that, prior to POSTing, I need to validate using the jQuery Validation plugin.Currently, if the user clicks the form's Submit button (the form's action for the PHP form handling is the page with the link that opens the Dialog in the first place) with a field not properly filled out, the Dialog just closes.Clicking again on the link that opens the Dialog form will show the form with the error message(s) that the Validator generated on the previous click of the submit button.How can I keep the Dialog open and prevent a POST until the form validates?
View 1 Replies View RelatedWhat I want to do is: disable the submit button while not all form fields are filled out and eneble it when the form fields are filled out. Disabling works, the enabling doesn't, at least not 'automaticly'. All of the code is in the $(document).ready(function(){}
I have this code:
checkAll();
function checkAll()
{
[Code]....
I have my form working great as long as my submit button is contained within the form tags. But the design calls for the submit button to be outside of the form. Sample code and diagrams are below.
<form>
my form here
</form>
<div> </div>
<div> Submit button </div>
[Code].....
I have a message system that I want to prevent double posting. So when a user sends a message i would like to disable the button. But its done using AJAX and will load without much time. But enough to cause double clicking. So now the button needs to be enabled once Text is put in the Form Field.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
This is my first post, and I'm only just learning jqury/JavaScript.
i have a form I'd like to send via POST method to a second php page, i have all the validation etc working fine, I'm struggling with the on Submit handler.. once the form is validated...
can anyone please tell/direct me how i can post this form to a php page that will do the data insertion?[code]...
I'm working on a little project where they have a slider form and I need to piggyback a tiny line of code into the validation function for the form.
What I need to happen is when the user has filled in all the fields and clicks the submit button AND the data validates THEN a class is added to the body tag. My jQuery knowledge is very minimal - I added the code to where I 'thought' its supposed to go but it didnt seem to work.
jQuery(document).ready(function() {
jQuery('#scroller').css('overflow','hidden');
// Set up the scrollable registration
var wizard = jQuery('#scroller').scrollable();
[Code]....
I am trying to validate a form with a couple of elements being required if a checkbox is NOT checked. Now if I submit the form the rules fire - and then I check the checkbox on - the validation rules have already fired - and even though the checkbox is now checked - the validation rules still apply and the form will not submit until I enter the fields.What I was hoping was that the checkbox could toggle the rules on or off.
var validator = $(".cmxform").validate({
rules: {
txtAddress1: {
[code]....
I have a page with a form on it. I also have as part of the page some form validation using javascript. However, and this is rather frustrating, the form is being sent even when the validation is failing. If the form fails validation it shouldn't be sent.
The code is:
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedThe following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
We have a requirement for this now, where We have 2 forms on the same page and each form has a different action url it will post to.But we will display only one submit button.This single submit button will first submit 1 form and if that form "submit" succeeds, It will then submit the 2nd form.If this sequential submit is not possible, we might be able to live with parallel submission of both the forms.Is there a sample/code snippet/ instructions/ something out there to give me an idea on how to proceed?
View 4 Replies View RelatedI want to highlight the submit button (change css class) as soon as the form was changed. How would you do this?
View 3 Replies View RelatedEverywhere proposed solution
$('form').submit(function() {
$(":submit").attr("disabled", "disabled");
});
doesn't work for me, because in that case the button name and value won't be included in the request to the server (because the button is disabled), and I've got a situation where I need to know which button was clicked to submit the form.Is there any way to disable the submit button AFTER the form submission, so it would be included in the request?
Tested it in Opera, FF 3.5 - there, the result shows that the submit button was sent too. however, in Chrome, it is not sent. It even works in IE8 (sic), didn't test lower versions. Might be a Chrome bug, but since jQ should be cross-browser and work the same everywhere, then Chrome could do with a workaround or smth.
View 1 Replies View RelatedI've attached a text file that includes a form and its associated jQuery code.Before I removed the action and post from the form (as commented in the code), the form worked fine using either submit button. But now the page only refreshes - the alert in the jQuery click event doesn't fire.
____________________________________
f u cn rd ths u cn gt a gd jb n prgrmmng
Attachments
test.txt
Size : 3.31 KB
Download : 285
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
how do I hook a button click event so that my handler fires first but does not affect the firing of other clickhandlers for the same button?
What I want to do is hook all the form submit button click events. When a submit button is clicked, my handler will stuff some hidden fields into the form the button is contained within. Then the handler returns and the built in form submit button handler posts the form back to the server.
Need the three "Options" to be hyperlinks that submit the "choice" form. When submitted, I would like the value to be the text of the option selected (i.e. value=Option1, Option2 orOption3) and all three to have the same name. (i.e. name = Options) How do I make the 3 options inputs and submit on click?
<form action="cgi.exe" method=POST name="choice"> <tbody> <tr> <td>Option1</td>
<td>Option2</td>
<td>Option3</td>
[code]....
