I have a page with a form on it. I also have as part of the page some form validation using javascript. However, and this is rather frustrating, the form is being sent even when the validation is failing. If the form fails validation it shouldn't be sent.
The code is:
I have a simple three-field form in a UI Dialog that, prior to POSTing, I need to validate using the jQuery Validation plugin.Currently, if the user clicks the form's Submit button (the form's action for the PHP form handling is the page with the link that opens the Dialog in the first place) with a field not properly filled out, the Dialog just closes.Clicking again on the link that opens the Dialog form will show the form with the error message(s) that the Validator generated on the previous click of the submit button.How can I keep the Dialog open and prevent a POST until the form validates?
View 1 Replies View RelatedI have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
$(document).ready(function(){
$("#myForm").validate();
});
[code]....
I am unable to submit the form after validation. I have tried various ways to submit but my form action is not honored. [URL]...
View 1 Replies View RelatedI have this create user form, and I'm checking if the email hasn't been used already. This works... But what my problem is, that if the email has not been used before, it will not send the form, while I return true.
I've tried to use $(this).submit, but that will just make it loop and never stop.
So basically: ifdata.is_dublicate = true show error else data.is_dublicate = false submit the form
$("#add_user").submit( function(){
var error = $('#dublicate');
$.post(domain.com/check_dublicate_email', {email: $("#email").val()},
[Code].....
This is my first post, and I'm only just learning jqury/JavaScript.
i have a form I'd like to send via POST method to a second php page, i have all the validation etc working fine, I'm struggling with the on Submit handler.. once the form is validated...
can anyone please tell/direct me how i can post this form to a php page that will do the data insertion?[code]...
I'm working on a little project where they have a slider form and I need to piggyback a tiny line of code into the validation function for the form.
What I need to happen is when the user has filled in all the fields and clicks the submit button AND the data validates THEN a class is added to the body tag. My jQuery knowledge is very minimal - I added the code to where I 'thought' its supposed to go but it didnt seem to work.
jQuery(document).ready(function() {
jQuery('#scroller').css('overflow','hidden');
// Set up the scrollable registration
var wizard = jQuery('#scroller').scrollable();
[Code]....
I am trying to validate a form with a couple of elements being required if a checkbox is NOT checked. Now if I submit the form the rules fire - and then I check the checkbox on - the validation rules have already fired - and even though the checkbox is now checked - the validation rules still apply and the form will not submit until I enter the fields.What I was hoping was that the checkbox could toggle the rules on or off.
var validator = $(".cmxform").validate({
rules: {
txtAddress1: {
[code]....
Have made a contact form for a website that uses javascript to validate it then once validated prompts the user if the details are correct. Currently its working in chrome and ie but not in firefox. Code is in post #3.
View 5 Replies View RelatedI am trying to get a form to work with validating a checkbox. It
validates the checkbox ok, but it always redirects, even if the box
isn't checked...it does alert, but I was hoping that it would stay on
the current page and not redirect unless the box IS checked. I really
can't see what I did wrong. Code:
I have a form with a username field and password field, and a login button in the form of an image. I would like to have the login button image change its state to the hover style in the CSSwhen both username and password fields have been validated/filled out.[code]...
View 1 Replies View RelatedI have a very simple form for username and password and am trying to implement validation as per the code below. When executed the folloiwing happens:
Here is the code I have written:
Any idea why it wont focus back to #username? I have tried replacing $(this).focus() with $("#username").focus() but that does not work either.
I have a form built and on the onclick event I validate all of the
fields and then if the form is ok, on the submit event I run a
javascript function to set a cookie and download a file from the
current window.
I have a cgi script provided by my web host to send the contents of the
form through email but they only show me how to use the cgi script to
send email through the submit event of the form.
ie. <form name="downloadform" method="post"
action="/cgi-bin/cgiemail/mailtemp.txt" onSubmit="return
Validate(this)">
Can I utilize the cgi script/link from my javascript function and still
send the contents of the form through the cgi email??
I've been struggling trying to get a small order form to work the way I want it to. Here is a link to the live page: [URL] And here is the code in question:
[Code]...
I have two questions...
Question 1 How can I make this piece of script act a little smarter. Look at the order form, I'm catering for up to 4 people and providing lunch for them. If they select 3 people and the spaghetti bol for lunch, it's only adding $10 where it should be adding $30. Obviously this is simple multiplication but since the values in my form are prices it makes it a little tricky. I'm guessing an onselect on the first part of the form which changes the pricing of the other items would be the way to go, but how do I do this?
Question 2 The "Total Price" is placed before the <form> tag by the script. This is ok but it's not where I want it. How can I position this text elsewhere in the document?
How does one cause a form element to appear ONLY if a certain form selection is made before it?
That is for example say there is a form element of type Radio called "format" so only if they select format value = normal then the form input fields called URL and Name are to appear as the next choices otherwise form input field Group and checklist Places are to appear as the next choices.
How would I put this together so,
<input name="input1" type="text">
<input name="input2" value="whatever is typed into input1" type="text">
I would like to be able to type something in input1, and see it type
into input2
I am having a problem with the submit() method that is driving me nuts. I'm using document.form.submit() with large text fields (approx. 2000 characters) and am getting a "Invalid Syntax" error. If I do the same thing with a text field of under 1500 characters, it works fine.
Is there some size limit here that I don't know about?
I've have a function to take the value entered in a form text box, add 50 to it and put the result in another text box.
When I enter 650.5 I get 700.5 exactly how I'd expect. But when I enter -650.5 instead of getting -600.5 I get -650.050 as though it is failing to parse the float due to it being negative. My understanding of parseFloat was that it recognises negative numbers. Is there a nice simple way to get this to work?
Is it possible to read a web page on some web site that contains a form. Then identify the fields in the forms. Then fills the fields with my data. and then submits the form as it submitted normally. I need to do this to automate for my final proyect , i need to fill many web pages remotly
View 2 Replies View RelatedI would like to have a main form (written in PHP) that has a "lookup" button next to a text field. When the user clicks "lookup", it should open a new window that lets them search (child.page1). When they enter a name or DOB into the search form, it submits the form through PHP (via POST), to a results page (child.page2). This displays all persons in the database which have a name or DOB == to the search term(s), with a checkbox next to each match. They click the checkbox (or alternenatively, a link), and return the checkbox value to the main window.
I have everything working right now, except that (child.page2) doesn't recognize the main window. If the data is entered on (child.page1), it works fine. I'm not very familiar with javascript.. is this even possible? I've considered using frames, to keep the parent-child relationship evident to the computer, but figured I'd check to see if there's an easier way.
I need to pass user input from a form to one database field. I'm relatively new to JS but the idea I had was to have several form elements and use JS to collect the users input and send all the values through a hidden element. What's happening is the variable names are being sent rather than the values. The code below is only passing to the next page. Limitations: I am editing an intranet site built by a 3rd party so a lot of the files we've been given are encrypted. I cannot change the method to post.
[Code]....
Here is the issue I am having: In my project, I have a index.php page with a sidebar menu and a div id called œcontent.The user can select different menu items and perform searches from the database and make updates to their account. Im using ajax to load all of the menu items and all of the forms into the div id "content" on the index page. The Forms all load into the target div as they are suppose to with ajax.
However, on the mysettings page I have two forms and two different buttons, one called save and the other called update. When a user wants to edit their account information and makes changes to their account they clicks on either button and the form processes the information and updates or inserts data into the database correctly but the problem is that after that the form or page does not display the form back in the div id "content" like how it was loaded originally in the index.php page. The problem is that it reloads or refreshes the form page without the index.php page being involved. That is does not get reloaded or updated inside the index.php page content div again.
What I would like do is have all of my forms process whatever is submitted on the page and display the results back inside the same content div on the index.php page again. I know I am missing something because all of my forms are doing the same thing. I am hoping someone can help me out. I would be very grateful for example code that I can learn from since I am still relatively new to web development. I am posting some sample code below.
[Code]...
Having a few problems with a form validation script. Its supposed to stop sending the form if key fields are missing, but it just sends them anyway!
Below is the code i use in the header to check for blank fields:
Code:
And now the code i use to action it:
Code:
From what i can see the fields match, it all links up correctly but still it will allow blank forms to be sent.
I've put together what I think is an illustration of my problem at [URL] Quite simply, I need to be able to access the elements of the form without referring to them by ID as the whole form is intended to be cloned. I intended to do this using parentNode and childNodes[] together with the 'this' keyword. My understanding of 'this' in this context is that it should refer to the HTML element calling the function, i.e. one of the radio button inputs. However this gives the error "Error: this.parentNode is undefined"
View 1 Replies View RelatedWe're using Malsup's form plugin v2.82 and jQuery core 1.6.2. We're having issues in IE7 where, on a form with file upload, form fields are being dropped before the form is submitted to the server.We tracked it down to the `fileUpload` function, specifically line 196 where each field in the form data has `.attr('disabled',false)` run against it. If we change this to`.prop('disabled',false)` it all works fine.I don't see a clearly marked place to submit bug reports for the form plugin, and wanted to verify that others see this as well,
View 6 Replies View RelatedI'm having troubles with an existing J2EE application (which uses Dojo) and in which I'm gradually introducing jQuery. The specific issue is with the malsup Form plugin and the JSON returned from a form submission: the error callback is always called, regardless of what happens on the server side, and the error is always "parsererror". I'm using jQuery 1.4.2 and the 2.45 version of the malsup Form plugin.
For example, given the following code:
$(document).ready(function() {
var options = {
dataType: 'json',[code]....
the server receives the submission and handles it without errors, then in the browser I always get the same alert from the processAddressEditSubmitError() function, with an "Invalid JSON" message:
pStatus=parsererror
pErrorText=Invalid JSON: {"nickname":"trytrez","success":"success"}
However, the JSON looks OK for me (and http:[url]...agrees that it is valid).