JQuery :: Highlight Submit Button If Form Was Changed?
May 10, 2011I want to highlight the submit button (change css class) as soon as the form was changed. How would you do this?
View 3 RepliesI want to highlight the submit button (change css class) as soon as the form was changed. How would you do this?
View 3 RepliesI'm trying to highlight the row color when the input field is changed but get an error
Code:
<script type="text/javascript">
function toggle(trid){
[code]....
I have say 12 pics on a page, in 3 rows of 4. The rows of pics are there so that a choice can be made from each row and I'm using a function <script>
var highlight_color = '#FF0033'; function toggle_highlight(id) { var images = document.getElementsByTagName('img'); for (var i = 0; i < images.length; i++) { var image = images[i]; image.style.borderColor = image.id == id ? highlight_color : 'white'; } } </script>
to toggle a border colour change so that you can see what was chosen from each row. The function I have used is fine in that it works, but I can only choose one picture and have the border changed, then if I click on another row the first border that changed obviously changes back and the new selection is highlighted. I don't really know where to go from here.
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedThe following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
$(document).ready(function(){
$("#myForm").validate();
});
[code]....
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I have my form working great as long as my submit button is contained within the form tags. But the design calls for the submit button to be outside of the form. Sample code and diagrams are below.
<form>
my form here
</form>
<div> </div>
<div> Submit button </div>
[Code].....
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
We have a requirement for this now, where We have 2 forms on the same page and each form has a different action url it will post to.But we will display only one submit button.This single submit button will first submit 1 form and if that form "submit" succeeds, It will then submit the 2nd form.If this sequential submit is not possible, we might be able to live with parallel submission of both the forms.Is there a sample/code snippet/ instructions/ something out there to give me an idea on how to proceed?
View 4 Replies View RelatedEverywhere proposed solution
$('form').submit(function() {
$(":submit").attr("disabled", "disabled");
});
doesn't work for me, because in that case the button name and value won't be included in the request to the server (because the button is disabled), and I've got a situation where I need to know which button was clicked to submit the form.Is there any way to disable the submit button AFTER the form submission, so it would be included in the request?
Tested it in Opera, FF 3.5 - there, the result shows that the submit button was sent too. however, in Chrome, it is not sent. It even works in IE8 (sic), didn't test lower versions. Might be a Chrome bug, but since jQ should be cross-browser and work the same everywhere, then Chrome could do with a workaround or smth.
View 1 Replies View RelatedI've attached a text file that includes a form and its associated jQuery code.Before I removed the action and post from the form (as commented in the code), the form worked fine using either submit button. But now the page only refreshes - the alert in the jQuery click event doesn't fire.
____________________________________
f u cn rd ths u cn gt a gd jb n prgrmmng
Attachments
test.txt
Size : 3.31 KB
Download : 285
I'm having an issue where when I click a button it changes the class of that button
$(this).addClass('not_selected').removeClass('selected');
And then I want to make it so that button acts diffrently once it has been pushed
$('.selected').hover(function(){.....
The button is changing class fine I have checked it in firebug but I want it to then instantly respond to other jquery functions as if it has the new class?
how do I hook a button click event so that my handler fires first but does not affect the firing of other clickhandlers for the same button?
What I want to do is hook all the form submit button click events. When a submit button is clicked, my handler will stuff some hidden fields into the form the button is contained within. Then the handler returns and the built in form submit button handler posts the form back to the server.
Need the three "Options" to be hyperlinks that submit the "choice" form. When submitted, I would like the value to be the text of the option selected (i.e. value=Option1, Option2 orOption3) and all three to have the same name. (i.e. name = Options) How do I make the 3 options inputs and submit on click?
<form action="cgi.exe" method=POST name="choice"> <tbody> <tr> <td>Option1</td>
<td>Option2</td>
<td>Option3</td>
[code]....
This is my form, When user click the <b>YES and checked the check </b>box then only I want to enable the Prepay by Card button. For this situation, what is the jquery snippet. I have tried somthing like:
$("#SubmitCard").attr("disabled", "disabled");
But the thing is, I want to put the and Condition match. For this situation, I don't know how to write the jquery snippet
<table style="border: 0px solid rgb(0, 0, 0);
width: 485px; height: 45px;"><tbody>
<tr style="width: 20px; height: 5px;">
<td width="78">Pay by Card </td>
<td width="78"><b><span style="cursor: pointer;" id="yes">Yes</span></b></td>
<td style="cursor: pointer;" width="315"><span id="no" style="cursor: pointer;">No</span></td>
</tr> .....
I am pretty comfortable with jQuery and the validation plugin as well.
I am having an issue where:
User clicks a button it opens a lightbox (I am using Fancybox) - a form appears inside the modal. The data is submitted via AJAX and I am trying to validate the form before the form within the lightbox is submitted.
My button with the click handler right now does a GET to a server to send the data. Along with some other JavaScript. What is the best way for me to validate my form within a lightbox, and submit after it validates. Sending AJAX.
I have a form with multiple submit buttons.
<form action="" id="myForm" method="post">
<fieldset>
<!-- various input fields -->
<button type="submit" name="Exit">Exit</button>
<button type="submit" name="SaveExit">Save & Exit</button>
<button type="submit" name="Save">Save</button>
</fieldset>
</form>
When the SaveExit or Save buttons are clicked, the form is to be validated. When the Exit button is clicked, the form is NOT to be validated. How can I do this with the Validate Plugin 1.7 from [URL]. Is this possible?
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
[Code]...
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
The form processor I'm using can take a few seconds to complete (and either take me to the thank-you page or back to the form with error messages). I'd like to change the "submit" button to a loading GIF. I'm using the following code but realize that the form (using ajaxSubmit) doesn't actually submit when I do this.
function pleaseWait() {
var x = document.getElementById("submitdiv");
x.innerHTML = "Please Wait... <img src='/images/ajax-loader.gif' />";
}
[Code].....
How do I disable the submit button if all required fields in a form are not filled in? Say I have a form with Name, Age,message, and email. Name, message and email must be filled in or else the submit button will not show or will be disabled and then enabled once filled. If the fields are filled in then the submit button will show. If the fields are filled in but then one is deleted then the submit button will hide. Ideally if I can have it disabled that will work, if not I will settle on hide at this point.
View 1 Replies View RelatedI recently updated from jQuery 1.4 (I think 1.4.4) to 1.5.1. Before the upgrade, when users pressed the browser's Back button, they would usually be taken back to a page with all their changes intact. If they had modified input values or clicked objects that caused other parts of the page to change, they would still see those changes. Back literally took them back to the exact thing they were looking at before. Under 1.5.1, Back takes them to the prior page as it was when it first loaded. What changed? Can I get the old behavior back?
View 2 Replies View Related