I want to make few forms but 1 submit button. I want to do 1 page, 5 forms, 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
View 2 Replies
I want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
View 2 Replies View Relatedi've already create a form that will pop up an alert message if there is an empty input. it went great. but after i edit <form onSubmit="return formValidator()"> to <form onSubmit="return formValidator()" action="html_form_submit.asp" method="get"> i don't know why my submit button cannot send this form to html_form_action.asp.
<html><head>
<title>Kelab ICT OUM</title>
</head>
<body>
<script type="text/javascript">
function formValidator(){
var nama=document.getElementById("nama");
[Code]...
how do I hook a button click event so that my handler fires first but does not affect the firing of other clickhandlers for the same button?
What I want to do is hook all the form submit button click events. When a submit button is clicked, my handler will stuff some hidden fields into the form the button is contained within. Then the handler returns and the built in form submit button handler posts the form back to the server.
I'm trying to Submit two forms with one button and one by one. Submit one by one is working. But can't finger out how to submit both at the same time.
<script type="text/javascript">
function f1Submit() {
var n1 = document.f1.t1.value;
[code]....
I need to have two separate forms, each using a different PHP script that I cannot modify to process them. I need to have both of these forms share the same submit button. Here is a simplified version of the html. I will also need simple validation on these and know Ill have to do all this via jQuery's AJAX function.
View 7 Replies View RelatedIs it possible to have 2 seperate forms on a webpage sharing the same submit button, is there a way to share 1 submit button but make it if i type inside the form1 and press submit the form process page redirects it to guestlogin.php and if i type in form2 and press submit the form process page redirects it to memberlogin.php.
View 5 Replies View RelatedI need to submit two forms using a single submit button. What's ur suggestion. I found that JavaScript is the only way to go here, right?
View 1 Replies View RelatedI read an article on this forum that was about a counter that tracked button clicks. What we have is a very simple site that has a drop down box that links to several different forms that are filled out then submitted (to a server that accepts HTTP POSTs). What I'm looking to do is put a small chart on the main page with the drop down that shows how many times a specific form was submitted, in essence tracking the submit button clicks on those forms. To be exact we have six forms. Please correct me if im wrong and there is a better way to accomplish this but that was the only way I could think of. I do not have .asp or .php capabilities on the paticular site so sticking to a javascript would be best.
View 7 Replies View Related<?php
session_start();
if (empty($_SESSION['is_logged_in']))
{
header("Location:chatframe.php");
[Code]...
I have a form built and on the onclick event I validate all of the
fields and then if the form is ok, on the submit event I run a
javascript function to set a cookie and download a file from the
current window.
I have a cgi script provided by my web host to send the contents of the
form through email but they only show me how to use the cgi script to
send email through the submit event of the form.
ie. <form name="downloadform" method="post"
action="/cgi-bin/cgiemail/mailtemp.txt" onSubmit="return
Validate(this)">
Can I utilize the cgi script/link from my javascript function and still
send the contents of the form through the cgi email??
Can I send a key stroke to effectively click the back button?
View 5 Replies View Relatedi just leanerd the existence of the ajaxSubmit jQuery plugin,im wondering if there is a way to use the JSON both to send and retrieve the requests .I mean, no the plugin have the option 'dataType',that is used to specify the format that the server will send back, but i need to send the form as jquery to the server.For example, if my form looks like:
<form name="mytest" action="mypage.php" method="get">
<input type="text" name="firstone" id="firstone" value="here some
text!" />[code].....
I'm simply trying to get one form's submit button to submit another form.. Just can't seem to figure out why it does not work.. Could anybody take a look?Click Here
$(document).ready(function(){
$('#submit1').click(function(){
$('#form2').submit();
[code]....
I am trying to get a form to call a javascript function on submit to send an ajax request. The site sits on one server and the php target file on another. I get a status of 0. From what I read, this is because the php file sits on a different server. I do don't believe I can get around the files sitting on different servers.I can set the php file as the form action, but I do not want to redirect, just send a request to the other server to modify some values in a DB. If I can not send an ajax request between servers, I was thinking an alternative might be to set the php file as the form action, run the updates, and then have the page redirect me back. Is there a better way to get around this problem
View 1 Replies View RelatedI have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
I have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
I'm trying to get a form submit working for all browsers, and I am using document.forms['formname'].submit().
However, despite having 'formname' set on the forms in both the name and id properties, Safari 3 will not submit the form correctly; when I debug, $_POST is empty. IE, FF both work here fine. If I use document.forms[0].submit() it works correctly, but this code will be working in a dynamic site where I can never be sure at what index a given form will reside. I can make it work using document.getElementById('formname').submit(), but that does not work with js turned off, and I need this to work with js on/off.
This is a ? about Ajax, PHP and form processing. When I submit the form further below, nothing happens I didnt set the form-"action" to anything. I left it out, to make the form submit to the same page, so I can validate on the same page too (Which is not made yet, as youll see. The form does work fine when I used in a "normal php script", but when I include it using Ajax, the form doesnt submit after it has been sent to the page.
Anyone knows what is going on, and what I can do to make it work? I guess it must be the action attribute of the form which is wrong, but I dont understand that since i made the form submit to itself, by leaving out the action attribute entirely.
I have two links on a page, which calls a javascript function, opening a xmlhttprequest: I have only shown one of the forms, as they are almost similar, but there are two forms, in the real page, which displays depending on the link selected.
[Code]...
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I made some quiz using one HTML form (few question with few
radio-button each like potential answers) that have one Submit button.
I would like to simulate click on this button (e.g. named "Finish")
after some time, 10 minute or so, which be equal like click on submit
button and terminate quiz (open another page or so). I tried to solve
it by JavaScript but won't, always error, like can't detect button like
object. What to do? Listing is: Code:
