I have a large form. The submit button doesn't work if the data to be posted back is too long.
1. How to send only MODIFIED fields back?
2. What's the max len of the data I can sent back using post method? Does it depend on browser?
sample code, whereby if I change a field value in a web form (from a drop-down list for example), the value shown in another field is automatically updated to show the needed value for that selected option?
View 1 Replies View RelatedHow do I change the background colour of an input box in a form as soon
as the value is changed? Also the background should revert back to it's
original colour if the user decides that they do not want to make any
changes and hence retype back the orginial value.
I do not want the background to change after the user has moved to the
next form field but as soon as the value has been changed.
I've have a function to take the value entered in a form text box, add 50 to it and put the result in another text box.
When I enter 650.5 I get 700.5 exactly how I'd expect. But when I enter -650.5 instead of getting -600.5 I get -650.050 as though it is failing to parse the float due to it being negative. My understanding of parseFloat was that it recognises negative numbers. Is there a nice simple way to get this to work?
I wish to send the javascript calculated value in a form from one page to another page form. I just need the one value sent. The value is "answer: in the code below. I would like to send it to a form page called "answer.html". I am not a computer person, and I am doing this in frontpage. I do not know how to write java or anything, I just copied this from a free script site and am trying to use it.
Here is the code I have.
<table cellspacing=0 width=427
height=1 bgcolor="#FFFFFF" style="border-collapse: collapse" cellpadding="0" border="0">
<tr><td width="634" nowrap height="1">
<script language="JavaScript">
function findcalculatorcalculate(form) {
a = form.debt.value - 0;
b = form.faith.value - 0;
d = a / b;
form.answer.value = Math.round (d);
} .....
I have say 12 pics on a page, in 3 rows of 4. The rows of pics are there so that a choice can be made from each row and I'm using a function <script>
var highlight_color = '#FF0033'; function toggle_highlight(id) { var images = document.getElementsByTagName('img'); for (var i = 0; i < images.length; i++) { var image = images[i]; image.style.borderColor = image.id == id ? highlight_color : 'white'; } } </script>
to toggle a border colour change so that you can see what was chosen from each row. The function I have used is fine in that it works, but I can only choose one picture and have the border changed, then if I click on another row the first border that changed obviously changes back and the new selection is highlighted. I don't really know where to go from here.
I need to get the invalid fields to change back to blue when they're validated upon submit or even clicking out of the field.I'm not good in writing javascript yet so please include all of the javascript and html with the edits highlighted in the code:
The page:
http://shoppingcartcash.com
The js:
http://shoppingcartcash.com/form.js
I recently updated from jQuery 1.4 (I think 1.4.4) to 1.5.1. Before the upgrade, when users pressed the browser's Back button, they would usually be taken back to a page with all their changes intact. If they had modified input values or clicked objects that caused other parts of the page to change, they would still see those changes. Back literally took them back to the exact thing they were looking at before. Under 1.5.1, Back takes them to the prior page as it was when it first loaded. What changed? Can I get the old behavior back?
View 2 Replies View RelatedSo I have a table. With jquery I change border properties of several td. If later on in the code those same td have their background color changed by jquery, their borders return back.
Even if nothing is changed, nevertheless after some time some of the borders would seemingly randomly suddenly show up. I am working on a maze so this really spoils the game.
Code:
if($("crush",xml).text()=='1'){
border1=$("border1",xml).text();
border2=$("border2",xml).text();
[Code].....
I have a input field array, and have associated a change JQuery event handler if the value of any of the fields in the array have changed. So:
PHP Code:
And..
PHP Code:
In the Javascript, how can I retrieve the name (or index to be more precise) of the field that has had its value changed?
I'm trying to highlight the row color when the input field is changed but get an error
Code:
<script type="text/javascript">
function toggle(trid){
[code]....
I've been trying to figure out how to echo back error messages from a PHP edit page, for example. Say if I am editing a grid and sending that info with json to a php page to update a database, if there is a validation or other problem, how do I echo that back on the page with the jquery? Do I put that in a div container too for best practice?
View 7 Replies View RelatedCan I send a key stroke to effectively click the back button?
View 5 Replies View RelatedI have to add some technique which will solve the following problem. A form is presented to the user in our web application. Say it has
4 text fields,
2 radio buttons (Yes / No)
1 checkbox
1 select list.
Now 2 textfields are pre-populated, one radio button (Yes) is pre-selected, checkbox is not checked, one option from select list is preselected.
Problem:
In 90% of the cases, all that the user needs to do is enter values in the 2 empty textfields and click Submit.
However, the user might change the values in the preselected controls, like check the checkbox, change radio selection from Yes to No, select a different option from the select list, change the default values from the prepopulated text fields.
Now in such a case where 'default' values are changed, I need to show a alert or a popup layer to the user when the submit button is clicked.
Showing a popup layer or an alert:
The popup layer/alert will be a confirmation popup which will say something like -
"You have changed the default values for:[all the fields which were changed by user]. This requires you to do [some task] once you submit the form.
If you do not wish to change these defaults, click Cancel.
To proceed with the changes, click OK and then Submit."
Clicking OK:
If user clicks OK, then all is well. User will click Submit to submit the form and do some task which is required when defaults are changed.
Clicking Cancel:
If user clicks Cancel then the defaults should be restored. User is now free to click Submit. Code:
are there any callbacks for me to hook into in order to send the "focus ();" back to my input box when someone selects or clicks and autocomplete item?
View 1 Replies View RelatedA page I'm working on lets users open a new window, which in turn lets them send data back to the parent page to create new table rows, cells, links, etc. One of the links created is "delete", so it should delete the row that the delete link belongs to when clicked on. I can do this no problem in ff using the setAttribute('onclick',onClickEvent), but can't do this in IE. I'll show some code to make this easier to understand....
[Code]....
How do you detect that a form element has been changed? This thread:
http://groups.google.com/group/comp...25a82c9be127790
suggests that you attach onChange event handlers to every form element,
and when the handler fires you update a global 'isChanged' variable.
This technique seems to be a bit messy to me (I have many form
elements), I was thinking about storing the original form object in a
javascript variable when the body loads (in the bodie's onLoad event
handler), and upons submission, doing a javascript equality comparison
with the current form object. If nothing has changed, then the two
objects should be equal, right?
if(oldObject == document.getElementById('form'))
{
alert('has changed!');
}
Would this work?
I have a form with many fields... the fields are getting values from a
database.
I've tried onunload to just submit the form regardless of changes or
not but onunload and submit isn't working for me. Now I need some
type of event that will fire when a user tries to navigate from a page
to check to see if anything has changed and if so prompt them
(confirmation) to take action or not.
I know that the reset button only takes away anything that was added
to fields after the load so there must be some way to use the logic of
reset to simply check to see if fields have changed, right?
I have a web form with several fields. If I copy & paste from a RTF document into a field, the javascript validation and field length are bypassed and cause the form to fail.
View 3 Replies View RelatedI want to highlight the submit button (change css class) as soon as the form was changed. How would you do this?
View 3 Replies View RelatedI am trying to validate a form with a couple of elements being required if a checkbox is NOT checked. Now if I submit the form the rules fire - and then I check the checkbox on - the validation rules have already fired - and even though the checkbox is now checked - the validation rules still apply and the form will not submit until I enter the fields.What I was hoping was that the checkbox could toggle the rules on or off.
var validator = $(".cmxform").validate({
rules: {
txtAddress1: {
[code]....
I have a form built and on the onclick event I validate all of the
fields and then if the form is ok, on the submit event I run a
javascript function to set a cookie and download a file from the
current window.
I have a cgi script provided by my web host to send the contents of the
form through email but they only show me how to use the cgi script to
send email through the submit event of the form.
ie. <form name="downloadform" method="post"
action="/cgi-bin/cgiemail/mailtemp.txt" onSubmit="return
Validate(this)">
Can I utilize the cgi script/link from my javascript function and still
send the contents of the form through the cgi email??
What I have right now:Endless loop of Rows/records.Each one has a checkbox and a submit button.� I tried to make the checkbox pick up updating `long_desc`� The submit button currently just marks the job completed in the DB. (0=Incompleted 1=Completed)Submit button works with updating the row, right now... but instead of the submit button doing that, I want to have 2 checkboxes. One that knows to update the text field, and one that knows to update the status of the job, submit button to initialize it.I have some Javascript in already to separate the forms I have, and assign ID's to each Submit button on the page, but I really am stuck right now.
View 1 Replies View RelatedI have a form with some text fields that are disabled UNLESS a checkbox is checked. Initially the text fields are disabled and the checkbox is unchecked.
The code is something like this:
Code:
function disableTextbox() {
if (chk.checked) {
txt.disabled = false;
} else {
txt.disabled = true;
}
}
<form action=something.cfm>
<input type=checkbox name=chk onclick=disableTextbox();>
<input type=text name=txt disabled>
<input type=submit>
</form>
When the form is submitted, some validation is performed. If anything fails, I display an error message and show a link to go back (history.back).
The problem that I am having is that when you click on the link to go back, the checkbox on the form is checked, but the text fields are disabled.
You have to re-click the checkbox to update the text field.
i think this will help people a lot, cuz i couldn't find any simple answer by googling 3 hours...i need a very very simple jquery form field reset.here is the picture what i need:
HTML Code:
<script type='text/javascript' src='http://code.jquery.com/jquery-1.6.4.min.js'></script>
<script>
[code]....
Here is the issue I am having: In my project, I have a index.php page with a sidebar menu and a div id called œcontent.The user can select different menu items and perform searches from the database and make updates to their account. Im using ajax to load all of the menu items and all of the forms into the div id "content" on the index page. The Forms all load into the target div as they are suppose to with ajax.
However, on the mysettings page I have two forms and two different buttons, one called save and the other called update. When a user wants to edit their account information and makes changes to their account they clicks on either button and the form processes the information and updates or inserts data into the database correctly but the problem is that after that the form or page does not display the form back in the div id "content" like how it was loaded originally in the index.php page. The problem is that it reloads or refreshes the form page without the index.php page being involved. That is does not get reloaded or updated inside the index.php page content div again.
What I would like do is have all of my forms process whatever is submitted on the page and display the results back inside the same content div on the index.php page again. I know I am missing something because all of my forms are doing the same thing. I am hoping someone can help me out. I would be very grateful for example code that I can learn from since I am still relatively new to web development. I am posting some sample code below.
[Code]...
