I am building an app in Facebook and would like to pull in some Causes stats. In order to do this I am using jQuery and the ajax call. I am also using YQL.
Here is what I have:
As you know this is getting pulled in through an iFrame. This is working just fine in Chrome and FF.
With storing values Ajax call results into Javascript:
View 1 Replies View RelatedWe're using jQuery ajax quite a bit without issue. Today, however, we ran into an issue where the results of a query are not displayed.fyi... the following works fine in firefox. scenario:
1. load ajax "$("#location").load( url... )" used to retrieve results
2. using fiddler, we can see the results are returned as expected
3. results not displayed. look at the updated dom in IE8 with dev tools and the results are not put into the display area Additional info...
a. using $("#location").load( url, function(data) { alert(data); }); the alert shows the results are returned via the function call as well.
b. the #location is an empty div.. e.g. <div id="location"></div>
c. if we put some text in the div, it will be removed, by the call, but the results still will not display
d. we have removed all .show(), .hide() options
e. if we remove the ajax call and just do a $("#location").text("blah blah blah..."); the results are displayed
f. we have tried both 1.3.2 and 1.4.a1 again, every variation works just fine in firefox.t
This is tough to explain which makes it impossible to search on. I'm guessing this is very basic.
I have an array of objects with variables and ids.
[
{
id: "totalCountOfPeopleToSite",
action: "add",
[Code].....
I loop through this array and create an AJAX request to Google Analytics who returns the data I requested (or an error).
When the data comes back, I want to re-associate it with the object used to make it (as you can see, there might need to be an action performed on it and it should be stored with its ID so I can use it later).
I feel like I've read about a built-in way to pass along arbitrary information (in this case just getting an AJAX request with my made up "id" would be enough), but I can't find it anywhere, and I'm not explaining myself well enough to the Google to get results back.
In the code below I am trying to show the echo statement from a php file. The ajax call works when I use the alert(), but I am trying to put it in a div tag but not working.
View 1 Replies View RelatedIs it possible to return Query results from a jquery $.ajax POST call?It seems as though it will only return one value. What am I missing? [code]
View 1 Replies View RelatedI am trying to use a $.post call in jQuery to check a user's credentials before submitting a form (so I can show errors without reloading the page), but I've run into a problem. I know why it is, because AJAX is not synchronous, but I just can't figure out how to do it.
In my code the script I'm making the call to returns "valid" or "invalid". If the return is "valid", I want to submit the form, if not, show an error message. Here is a simplified version:
$("#my_form").submit( function () {
some_value = "username"
$.post(script_location, {data : some_value}, function (data) {
response = data
[Code]...
This obviously does not work because code is executed quickly one after another and the variable "response" is not yet set when the execution gets to the if statement, since it is set sometime later, asynchronously.
I looked into using functions, callbacks, but nothing seems to work properly, I always run into the same issue. This is probably really simple, i just a complete dunce, please do let me know what is the standard way of doing this properly.
so, the pseudo code: - on change of input contents, check to see if two input fields are set - if set, update a third field with "loading..." text and a loading gif - use ajax to send data to a url, and get a calculated json response - update the third field with the calculated response
I know I'm getting the correct response, according to firebug: {"pace":"10:00"}
the code:
$('#run_distance').change(function() {
if ($(this).val() != '' && $('#run_time').val() != '')
{
$('#run_pace').val('Calculating Pace…');
[Code].....
how to update the #run_pace input field with the json response.
I have a <div> tag that contains a table of results returned using AJAX. I have an onmouseover on the div so that when the user is viewing the results the div stays visible. An onmouseout is also declared so that when the user goes off of the div, it will disappear after a few seconds. When the user clicks on an entry I perform some logic and close the div.
However the problem occurs when my AJAX returns too many results to display in the set size of my div. When this occurs my div becomes scrollable. When the user is interacting with the scrollable, it seems to fire the onmouseout event because the div disappears.
I'm calling a ajax function that brings back the results, it works fine the first time i call the ajax function but if i call it again nothing get's updated.here is ajax function in search.php (This is just an example - to keep it simple i'm only passing a random number)
Code:
function searchUsers() {
var iamt = document.getElementById('sGender').value;
[code]....
I'm using BBC's glow to make an ajax post, its works fine, but I'm having trouble displaying the results, if I use:
It displays the results in a div with all the html escaped.
Does anyone know how I can display the results as html?
Code:
I've got a page that lists a bunch of info in a large table. In each row is a link, and when that link is clicked on, an ajax call fires that returns detailed info on the item in that row. I usually display the html just to the right of the table, but the table has gotten too large. I need to display the info in a pop up now. The only thing is, how do I get the results of my ajax call into a pop up window? I've been having an awful time getting this to work.
I'm using JQuery to make the ajax call, what can I put in my success of complete event to create the pop up using the data the ajax call returns?
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
View 15 Replies View RelatedI'm new to ajax. I've made a script that should return results from database but it keeps telling me just undefined. Code what I have:
Code:
var ajax = null;
function showRes(wut) {
if(wut.length == 0) {
document.getElementById("results").innerHTML = "";
return;
} if(window.XMLHttpRequest) {
// IE7+, ff, chrome, opera, safari
ajax = new XMLHttpRequest();
}else if(window.ActiveXObject) {
// retards
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} else {
alert("Your "browser" does not support AJAX!");
return;
} var url = "search.php?q=" + wut;
url = url + "&sid=" + Math.random();
ajax.open("GET", url, true);
ajax.send(null);
document.getElementById("results").innerHTML = ajax.reponseText;
}
I have an AJAX script which is used for a "live search" type function.When a user begins to type their search, after 3 characters, my AJAX script jumps into action and shows them a list of possible results.I has worked fine for months, and now suddenly I have found that it is causing a javascript error.I have traced the error down to the "open" call... ie: this.xmlHttp.open("GET", url, true);Like I said, this has worked for ages and I haven't changed these files since I got them working.
View 1 Replies View RelatedI have a table that has parts with multiple characteristics. Part Number, Height, Width, Capacity, Price, Etc. I would like to have a drop downs for all of these values, when a user selects one of these values it will filter the results into a list. Ex. user selects a part that has a Height of 6 and width of 10 it will only list those parts. As I said earlier, I have a script that will give me all the parts, however I am not able to make the onchange list parts with multiple values.
View 9 Replies View RelatedThe general framework is a simple user login function. The user name is selected and a password entered as usual. The function grabs the element values and passes them to a php page that queries the database. An AJAX call returns the password to the function and then I want the innerHTML to be a choice of two web pages, depending on success or failure of validation. There are existing AJAX functions available on the internet but they are overly complicated for what I think should be a simple, quick to load function.
Where I am stuck is that the standard procedure to make an AJAX call is the browser window event. How do you make the call from within the function? I have tried creating two new variables, "success" and "again" to replace xmlhttp, but still stumble on the event to assign a value. I left the blank password protection (if statement) with that variable to demonstrate what I mean.
I've put in my code below, which is in development and successfully alters the innerHTML text depending on user input but I can't figure out how to insert the relevant php page. I have '// out' the testing bits, but left them for info. (I have tried full 'scripting' as the innerHTML, but it's messy.)
I am having difficulty displaying a specific key from a json file. I am trying to parse the following json file using query:
[URL]
I am using this type of function to parse the data:
$.each(json.route,function(i,route){
<!--add a paragraph tag to the results div and enter the speficied key-->
$("#results").append('<p>Result: '+ route +'</p>');
Using this I am able to print all the keys from the route but I am not able to print a specific key.
What I want to do is just get the results for the key "fuelUsed" using this method:
$("#results").append('<p>Result: '+ route.fuelUsed+'</p>');
But I never get back any data that way. Am I not specifying my key correctly?
I'm a newbie when it comes to PHP & JQuery. I have a small issue and was wondering if someone could help me out.
I have a PHP page which takes in the 'source' and 'destination' from the user and results the distance in a new window.
I just want the distance displayed within the same window. I have absolutely NO clue how to use Jquery or what the syntax is.[code]...
I am pulling in an XML doc, storing it in a global var and through out the app I am transversing it to grab certain info. Up till 1.2.6 it's been working fine, but when I upgraded 1.3.2 I get bad results.
Here are my two test pages:
[URL]
My guess is the it has something to do with Sizzle but I can't place exactly where the issue may be happening.
Im working on a store locator and I was wondering if its possible for jquery to limit the results show in the sidebar and add a "more results" option. Right now the sidebar is one large div with overflow hidden so it doesnt show too many results.
View 42 Replies View RelatedI'm currently building a web application based off posted Tweets. As of now, I'm able to pull the first 25 tweets that contain a searched keyword, however I would like the option to 'Show More Results' at the bottom of the page, so users can view more results if they would like. I've found a tutorial, but am still confused as to how to accomplish this.
View 5 Replies View RelatedHave website [URL] and from this there is no datepicker on this page but when values submitted for location and date which is pu_day, pu_month , db_day, db_month , this seems to work fine as results derived from an XML which requires the date in format above to enable the request to be carried out. However on datepicker on www.wheels4rent/index-7.html i have datepicker on page but no results are displayed as it does not see the pu_day and pu_month and also the return dates.
View 3 Replies View RelatedI am working on some travel related site, User can modify his/her search by criteria in the left bar.
View 2 Replies View RelatedI'm using JSON/jQuery to pre populate a drop down menu. What I want to do, is once I select a plan from the drop down menu and click submit (go button), to get the details about the plan. The drop down menu get's pre populated, but I don't get anything after clicking go. I check the functions and it seems that in the DoPlanSearch() I get the alerts showing the newly constructed URL that gets me the correct JSON. But not sure what happens once the data is processed after that. I say this, because my alert statement in the DoPlanSearchCompleted(data) gets me NULL data.
I'm just getting started with this, I'm not exactly sure what's the best approach. Also, I'm not sure the way .JSON files is setup here works, it does on my Dev server though.
Code has line: function DoPlanSearchCompleted(data)
It should read function UserPlanSearchCompleted(data). The same problem though exists.
I need to change the value of the input box coming from a query result.
M_ACCOUNT_NAME=rsQuery("ACCOUNTNAME")
Here's where I am having problems:
$(document).ready(function() { $('input:text[name=txtAcctName]').val(M_ACCOUNT_NAME);
});
The input box does not display the content of the M_ACCOUNT_NAME. I alreadytested M_ACCOUNT_NAME with simple response.write and it has content. I also tested that I am accessing the right element by substituting val(M_ACCOUNT_NAME) with val('HELLO'). HELLO is displaying correctly.
