JQuery :: Storing Value Into Var For Ajax Call Results
Dec 25, 2011With storing values Ajax call results into Javascript:
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AJAX :: Call Based On Results Of A Previous Call
Dec 14, 2010The general framework is a simple user login function. The user name is selected and a password entered as usual. The function grabs the element values and passes them to a php page that queries the database. An AJAX call returns the password to the function and then I want the innerHTML to be a choice of two web pages, depending on success or failure of validation. There are existing AJAX functions available on the internet but they are overly complicated for what I think should be a simple, quick to load function.
Where I am stuck is that the standard procedure to make an AJAX call is the browser window event. How do you make the call from within the function? I have tried creating two new variables, "success" and "again" to replace xmlhttp, but still stumble on the event to assign a value. I left the blank password protection (if statement) with that variable to demonstrate what I mean.
I've put in my code below, which is in development and successfully alters the innerHTML text depending on user input but I can't figure out how to insert the relevant php page. I have '// out' the testing bits, but left them for info. (I have tried full 'scripting' as the innerHTML, but it's messy.)
JQuery :: .html() To Show Results From Ajax Call
Apr 18, 2011In the code below I am trying to show the echo statement from a php file. The ajax call works when I use the alert(), but I am trying to put it in a div tag but not working.
View 1 Replies View RelatedJQuery :: Retrieve Results From A Ajax Call ($.post)
Mar 25, 2010I am trying to use a $.post call in jQuery to check a user's credentials before submitting a form (so I can show errors without reloading the page), but I've run into a problem. I know why it is, because AJAX is not synchronous, but I just can't figure out how to do it.
In my code the script I'm making the call to returns "valid" or "invalid". If the return is "valid", I want to submit the form, if not, show an error message. Here is a simplified version:
$("#my_form").submit( function () {
some_value = "username"
$.post(script_location, {data : some_value}, function (data) {
response = data
[Code]...
This obviously does not work because code is executed quickly one after another and the variable "response" is not yet set when the execution gets to the if statement, since it is set sometime later, asynchronously.
I looked into using functions, callbacks, but nothing seems to work properly, I always run into the same issue. This is probably really simple, i just a complete dunce, please do let me know what is the standard way of doing this properly.
Ajax :: Displaying Results Of Call In A Pop Up Window?
Aug 4, 2010I've got a page that lists a bunch of info in a large table. In each row is a link, and when that link is clicked on, an ajax call fires that returns detailed info on the item in that row. I usually display the html just to the right of the table, but the table has gotten too large. I need to display the info in a pop up now. The only thing is, how do I get the results of my ajax call into a pop up window? I've been having an awful time getting this to work.
I'm using JQuery to make the ajax call, what can I put in my success of complete event to create the pop up using the data the ajax call returns?
JQuery :: Getting Null Results After Function Call
Apr 15, 2010I'm using JSON/jQuery to pre populate a drop down menu. What I want to do, is once I select a plan from the drop down menu and click submit (go button), to get the details about the plan. The drop down menu get's pre populated, but I don't get anything after clicking go. I check the functions and it seems that in the DoPlanSearch() I get the alerts showing the newly constructed URL that gets me the correct JSON. But not sure what happens once the data is processed after that. I say this, because my alert statement in the DoPlanSearchCompleted(data) gets me NULL data.
I'm just getting started with this, I'm not exactly sure what's the best approach. Also, I'm not sure the way .JSON files is setup here works, it does on my Dev server though.
Code has line: function DoPlanSearchCompleted(data)
It should read function UserPlanSearchCompleted(data). The same problem though exists.
Ajax :: Storing Values In Array From Php
Dec 7, 2009Problem with storing values in Array from php to AJAX index.php [code]What is the problem? What should I do to get the desired result?
View 1 Replies View RelatedJQuery :: Getting No Results Using $.ajax In IE 7 - 8 Or 9 ?
Mar 2, 2011I am building an app in Facebook and would like to pull in some Causes stats. In order to do this I am using jQuery and the ajax call. I am also using YQL.
Here is what I have:
As you know this is getting pulled in through an iFrame. This is working just fine in Chrome and FF.
Variable Set Inside Results Is Not Defined For Use Outside JSON Call
Nov 7, 2011I've got this:
Code:
var noteCount = "";
jsonRequest('media.getFiles', params,
function(result) { noteCount = result['totalCount']},
function(exception) { noteCount = "0"},
true
);
The console returns results['totalCount'] with a value of 2 (that's correct).
When I call noteCount for display, it shows nothing. Neither the var set by result or exception.
JQuery :: Ajax Load Results Display Error In IE8?
Jan 13, 2010We're using jQuery ajax quite a bit without issue. Today, however, we ran into an issue where the results of a query are not displayed.fyi... the following works fine in firefox. scenario:
1. load ajax "$("#location").load( url... )" used to retrieve results
2. using fiddler, we can see the results are returned as expected
3. results not displayed. look at the updated dom in IE8 with dev tools and the results are not put into the display area Additional info...
a. using $("#location").load( url, function(data) { alert(data); }); the alert shows the results are returned via the function call as well.
b. the #location is an empty div.. e.g. <div id="location"></div>
c. if we put some text in the div, it will be removed, by the call, but the results still will not display
d. we have removed all .show(), .hide() options
e. if we remove the ajax call and just do a $("#location").text("blah blah blah..."); the results are displayed
f. we have tried both 1.3.2 and 1.4.a1 again, every variation works just fine in firefox.t
JQuery :: Associate AJAX Results With Initial Data?
Sep 12, 2010This is tough to explain which makes it impossible to search on. I'm guessing this is very basic.
I have an array of objects with variables and ids.
[
{
id: "totalCountOfPeopleToSite",
action: "add",
[Code].....
I loop through this array and create an AJAX request to Google Analytics who returns the data I requested (or an error).
When the data comes back, I want to re-associate it with the object used to make it (as you can see, there might need to be an action performed on it and it should be stored with its ID so I can use it later).
I feel like I've read about a built-in way to pass along arbitrary information (in this case just getting an AJAX request with my made up "id" would be enough), but I can't find it anywhere, and I'm not explaining myself well enough to the Google to get results back.
JQuery :: Return Query Results From .ajax POST
Aug 24, 2009Is it possible to return Query results from a jquery $.ajax POST call?It seems as though it will only return one value. What am I missing? [code]
View 1 Replies View RelatedJQuery :: Using Ajax To Retrieve And Update A HTML Input Field With JSON Results From URL
Jan 1, 2012so, the pseudo code: - on change of input contents, check to see if two input fields are set - if set, update a third field with "loading..." text and a loading gif - use ajax to send data to a url, and get a calculated json response - update the third field with the calculated response
I know I'm getting the correct response, according to firebug: {"pace":"10:00"}
the code:
$('#run_distance').change(function() {
if ($(this).val() != '' && $('#run_time').val() != '')
{
$('#run_pace').val('Calculating Pace…');
[Code].....
how to update the #run_pace input field with the json response.
AJAX :: <div> Tag That Contains A Table Of Results Returned
Jan 9, 2009I have a <div> tag that contains a table of results returned using AJAX. I have an onmouseover on the div so that when the user is viewing the results the div stays visible. An onmouseout is also declared so that when the user goes off of the div, it will disappear after a few seconds. When the user clicks on an entry I perform some logic and close the div.
However the problem occurs when my AJAX returns too many results to display in the set size of my div. When this occurs my div becomes scrollable. When the user is interacting with the scrollable, it seems to fire the onmouseout event because the div disappears.
Ajax :: Function Only Brings Back Results Once?
May 1, 2010I'm calling a ajax function that brings back the results, it works fine the first time i call the ajax function but if i call it again nothing get's updated.here is ajax function in search.php (This is just an example - to keep it simple i'm only passing a random number)
Code:
function searchUsers() {
var iamt = document.getElementById('sGender').value;
[code]....
AJAX :: Response - Display The Results As Html?
Dec 9, 2010I'm using BBC's glow to make an ajax post, its works fine, but I'm having trouble displaying the results, if I use:
It displays the results in a div with all the html escaped.
Does anyone know how I can display the results as html?
Code:
Ajax :: Form Retrieves Results From A Mysql Database
Jun 22, 2011This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
View 15 Replies View RelatedAjax :: Script To Get Results From Database Returns Undefined
Aug 15, 2009I'm new to ajax. I've made a script that should return results from database but it keeps telling me just undefined. Code what I have:
Code:
var ajax = null;
function showRes(wut) {
if(wut.length == 0) {
document.getElementById("results").innerHTML = "";
return;
} if(window.XMLHttpRequest) {
// IE7+, ff, chrome, opera, safari
ajax = new XMLHttpRequest();
}else if(window.ActiveXObject) {
// retards
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} else {
alert("Your "browser" does not support AJAX!");
return;
} var url = "search.php?q=" + wut;
url = url + "&sid=" + Math.random();
ajax.open("GET", url, true);
ajax.send(null);
document.getElementById("results").innerHTML = ajax.reponseText;
}
JQuery :: Call Web Service With Ajax
Mar 16, 2011I wrote the following code with Dreamweaver:
If I run it in Dreamweaver It works and the alert success is raised, but If I run this code into Safari or Chrome the Error alert is always raised.
JQuery :: How To Get UI Widgets Via Ajax Call
May 10, 2011My goal is to get some HTML content including some UI widgets and other stuff via an ajax call. To clarify my goal and the strange behavior, I attached some HTML files, that you can run for yourself. Open the index.html will show you some UI widgets, which are pulled from the ajax.html via ajax. When you scroll to the bottom you can see the same content inserted a second time. But this time, the widgets are not "rendered". It looks if the "button()" calls etc. are not executed.
The only difference is the way I insert the result of the ajax call. The first time I insert the hole content received by the ajax call, the second time I only insert the content of a special div. The goal in this is to get various chunks of content with one ajax request and replace "div#one" and "div#two" with different parts of my site. Which is not working. Is it generally okay to receive html content which has some script parts to be executed via ajax and what is wrong with my second approach?
JQuery :: Cannot Return Value After Ajax Call
Aug 9, 2009I'm currently using the dialog functionality (modal form) from UI library to submit data to the database. All the validation checks have been running ok until one of the validation checks requires a ajax call to check if a username exist in the database. I'm fairly new to both javascript and jquery so this could be a fairly basic blunder. Initially, i thought it was an synchronicity problem, but I changed the $.ajax async option to true but still no joy, so maybe it something to do with scope etc?
Here's the code:
function checkIfUsername(){
$.ajax({
type: "POST",
url: ""+CI_ROOT+"index.php/admin/check_if_username",
data: ({username: username.val()}),
async: false,
dataType: "json",
success: function(data){
returnUsernameBool(username, data);
}});
}function returnUsernameBool(o, data){
if(data.bool == true){
o.addClass('ui-state-error');
updateTips("Your username must be unique");
alert('false'); //this works
return false; //still can't return bool
}else{
alert('true'); //this works
return true; //still can't return bool
}}
bValid = bValid && checkIfUsername(username);
alert(bValid); //still gives undefined
JQuery :: Use Attr In An Tab AJAX Call?
Sep 6, 2009I am trying to set an html attribute after an AJAX call. Works great on the initial tab I can't get it to work on the rest [code]...
View 1 Replies View RelatedJQuery :: Return Value From .ajax Call
Jan 25, 2011Is it possible to get a return value from a page call within an ajax call? For example,
$("#new_request").click(function(e){
$.ajax({
url:"_insert_new_request.php",
type:"GET",
[Code]....
Here I make an ajax call from a click on a div. I then call "_insert_new_request.php" page, with a param of "partner_id_link".
Can I return a value from the "_insert_new_request.php"? and how?
JQuery :: Using AJAX To Call PHP Script?
Jul 6, 2010I am planning to use an AJAX call to a PHP script that accesses a REST servlet. My php script would be very simple; something like:
[Code]..
I'm an experienced programmer, but I'm fairly new to web development, so I am having trouble interpreting this error. What have I done wrong? Is this the proper way to call a PHP script with AJAX?
JQuery :: Accessing A List After AJAX Call
Apr 9, 2011I have a page that creates one unordered list from the contents of another list. The second list is created from a database query and is hidden on the page. I have written a JQuery function shown below that does an AJAX call which causes the hidden list to be created and that is working perfectly. The problem is that when the code following the AJAX call is executed it doesn't see the hidden list. The alert message displays 0 the first time. clicking on the Load button a second time results in the first list being displayed. If I click on the Load button a third time, the previously loaded list is displayed; click on a fourth time and the new list is displayed.
In other words, it takes two cycles to display the correct list. I am at a loss as to what might be the problem. Other than this issue the code does what I need it to do.
$(function() {
JQuery :: Ajax Call - 403 Forbidden If URL In Content
Oct 15, 2010Strange behaviour: User enters text into textarea - text includes URL with protocol e.g. [URL]. JSON call fails with 403 forbidden. It seems the the serialised content is being interpreted as a cross domain call (my guess). Any other text works - Even if the user enters "http://www.u", but as soon as the input qualifies as a url, I get a 403.
The code extract:
var formText = $("#contributioncontrol").serialize();
$.getJSON('[URL]',formText, function(response) {
if (response.ERROR != true) {
var output = response.HTML;
$(output).hide().prependTo("#results").fadeIn("slow");}
}
If the user enters http://www.url.com in the textarea on the form then The request looks like this: [URL]. The '/' chars in the line above are replaced by% 3 A % 2 F % 2 F (without spaces - Don't know how to stop browser interpreting the encoded stuff).
And the response like this:
<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>403 Forbidden</title>
</head><body>
<h1>Forbidden</h1>
<p>You don't have permission to access /API/createcontribution.php on this server.</p>
<p>Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request.</p>
<hr>
<address>Apache mod_fcgid/2.3.5 mod_auth_passthrough/2.1 mod_bwlimited/1.4 FrontPage/5.0.2.2635 Server at www.mysite.com Port 80</address>
</body></html>