Ajax :: Script To Get Results From Database Returns Undefined
Aug 15, 2009
I'm new to ajax. I've made a script that should return results from database but it keeps telling me just undefined. Code what I have:
Code:
var ajax = null;
function showRes(wut) {
if(wut.length == 0) {
document.getElementById("results").innerHTML = "";
return;
} if(window.XMLHttpRequest) {
// IE7+, ff, chrome, opera, safari
ajax = new XMLHttpRequest();
}else if(window.ActiveXObject) {
// retards
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} else {
alert("Your "browser" does not support AJAX!");
return;
} var url = "search.php?q=" + wut;
url = url + "&sid=" + Math.random();
ajax.open("GET", url, true);
ajax.send(null);
document.getElementById("results").innerHTML = ajax.reponseText;
}
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Jun 22, 2011
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
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Dec 11, 2009
I have a homework assignment which is pretty simple. It is a grade calculator that uses arrays to gather the grades from the user. This is what I have for the problematic section:
var homework = new Array(2);/* The grades entered by the user for Homework 1, 2, and 3 */
var project = new Array (3);/* The grades entered by the user for Project 1, 2, 3, and 4 */
[Code].....
My problem is the document.write portion of the code, where it is supposed to return either homework[0], project [0], or exam[0], it instead returns undefined. There is no problem with any other subscript. And yes, it does successfully prompt me for each of the [0] subscripts in the first part of the code. Am I just missing something that is right in front of my face? Does all arrays not start with the [0] subscript?
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Jun 11, 2009
Today I've tried to create simple hover effect on a <div>: if the cursor is over the box, the background-image css property of the div is modified. On the HTML side, a <div> with an id:
<div id="round">Blah blah
</div>
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Dec 12, 2011
Suppose we have following javascript codes: Case 1.
var foo = function (){
var x = "hello";
var bar = function () {
alert(x);
} return bar;
} var bar_ref= foo();
document.write(bar_ref()); // it pops up "hello" and print-outs "undefined".
If we modified above code slightly, shown as follow: Case 2.
var foo = function (){
var x = "hello";
var bar = function () {
alert(x);
} return bar();
} var bar_ref= foo();
document.write(bar_ref()); // it only pops up "hello".
As you can see, Case 2 modified the return value from "return bar" to "return bar()," which won't cause the "undefined" output. To me, it looks like when the JS interpreter executes the line "bar_ref();" it triggers the execution of function "foo", besides both "return bar" and "return bar()" do the same job which is to execute function body of "bar".
The only difference is that after the execution of function bar, its function body does not exist anymore, so when the interpreter executes the line "return bar;" it follows the function identifier "bar" and ends up with "undefined". This is why the Case 1 gives us "undefined", but I am not quite clear about why the Case 2 can trace down to the function body of "bar". Do you have any ideas about such difference outputs?
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Aug 27, 2009
Shouldn't history.previous return an url address of previously visited web site???
I used this code in my web page: <body onload="alert(history.previous+''+window.history.next)">
then I visited some web sites and went back, but the code always returns undefined, although there are URLs of the previous and next pages visited .
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Jun 29, 2010
If you call the below code, it will incorrectly print "true, false" when it should be "true, true". WHy is that? How do I fix this?
Code: isCapitalLetter = /[A-Z]/g;
//Incorrectly alerts "true,true"
alert( isCapitalLetter.test( "lineHeight" ) + "," + isCapitalLetter.test( "lineHeight" ) );
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Feb 25, 2010
I'm doing something with grails + jquery. My controller send a rendered json (which I know is sending correctly) but when the object "arrives" in the callback method it comes undefined. I can see it lenght, but not it's content.
[Code]...
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May 18, 2009
I have to use scrollTop and scrollHeight properties, but on jQuery object it returns `undefined`.
Is there any method to get this property from jq object?
It doesn't matter, but my object looks like this:
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Feb 13, 2009
I am trying to access the width variable from my main page. Within the imageinfo.js script functions I can alert() the width value which returns 1024. But I can't seem to pass this variable to my main page or access it directly so that I can use document.write() to write the variable on the page. Whenever I try to call the 'width' variable directly from the main page I get undefined. How can I access this variable? However, with the test code below, I was able to get ducument.write() to write the 'width' variable on the page but now the page doesn't stop loading - there's an endless loop in the code...
Code:
BinaryAjax(url,function(http) {findEXIFinJPEG(http.binaryResponse);test(width)},null,useRange ? [0, Range] : null);
Main page
Code:
<html>
<head>
<script>
function test(width){
document.write('Image Width = ' + width)
} </script>
<script type="text/javascript" src="binaryajax.js"></script>
<script type="text/javascript" src="imageinfo.js"></script>
</head>
<body>
<script type="text/javascript">readFileData('image.jpg')</script>
</body>
</html>
Imageinfo script - This script uses the binaryajax script found below.
Code:
/*
* ImageInfo 0.1.2 - A JavaScript library for reading image metadata.
* Copyright (c) 2008 Jacob Seidelin
*/ .....
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Nov 22, 2011
I am trying to make a function that will return part of some xml data, but It keeps returning "Undefined" here is the function, with the call:
Code:
function getUserInfo(u, t) {
$.ajax({
type: 'GET',
[code]....
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Mar 27, 2011
When I run the following code, the .Length function returns "undefined."
var strTest = 'test';
alert(strTest.Length);
Using the typeof function, I know that JS is treating the variable as a string.
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Jul 27, 2011
Here is a code I use to calculate distance b//w 2 places using google api. It works perfectly and shows the results in the html but when I add a return statement at the end of the function showlocation() it returns undefined.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "[URL]">
<html xmlns="[URL]">
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
<meta name="robots" content="noindex,follow" />
<title>Calculate driving distance with Google Maps API</title>
<script src="[URL]" type="text/javascript"></script>
<!-- According to the Google Maps API Terms of Service you are required display a Google map when using the Google Maps API. see: [URL] -->
<script type="text/javascript">
var geocoder, location1,addr1,addr2, location2, result1,gDir;
function coolAl(add1,add2) {
addr1=add1;
addr2=add2;
var result= return initialize();
showLocation();
alert(result);
} function initialize() {
geocoder = new GClientGeocoder();
gDir = new GDirections();
GEvent.addListener(gDir, "load", function() {
var drivingDistanceMiles = gDir.getDistance().meters / 1609.344;
var drivingDistanceKilometers = gDir.getDistance().meters / 1000;
result1=location1.address + ' (' + location1.lat + ':' + location1.lon + ')/' + location2.address + ' (' + location2.lat + ':' + location2.lon + ')/' + drivingDistanceKilometers + ' kilometers';
document.body.innerHTML=result1;
return drivingDistanceKilometers;
});
} function showLocation() {
geocoder.getLocations(addr1, function (response) {
if (!response || response.Status.code != 200) {
alert("Sorry, we were unable to geocode the first address");
} else {
location1 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address};
geocoder.getLocations(addr2, function (response) {
if (!response || response.Status.code != 200) {
alert("Sorry, we were unable to geocode the second address");
} else {
location2 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address};
gDir.load('from: ' + location1.address + ' to: ' + location2.address);
}});}});}
</script></head>
<body onload="coolAl('pune','mumbai')">
</html>
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Jan 27, 2009
Here's the problem: I have several hidden divs containing information. When you click on a link, javascript executes which is supposed to move the appropriate info from one of the hidden divs into the visible 'body' div. The javascript isn't working, though, and I'm getting 'undefined' instead
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Oct 5, 2010
I want to sort the database search results in php. Basically, the results are returned on a php page and need to be sorted either by columns. I managed to display the results on the page witht he code below and it works, but now i need to add the sorting bit, but i am stuck with it. I dont want to fetch the data from the database again but just to manipulate the existing entries. how can this be achieved in php?
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Mar 29, 2010
I'm getting this error when trying to simple traversing.
results.push.apply( results, checkSet ); jquery-1.4.2.js (line 2743)
I read that it might have something to do with arrays?
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Jun 8, 2010
I am currently trying to create a live search box that as I type it will start displaying results that match.but it retrieves its data from an XML file, I need mine to retrieve from a column called FirstName within a table of an Access database.
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Feb 12, 2010
I have a listings page which displays results using images and text which are stored in a MySQL database, all is working fine. The images are pulled into the page from the database and each listing can have up to a maximum of 10 images. Some will have all 10, some probably one or two, so the page is coded such that if there's an image in the field, it displays a thumbnail, if there isn't then it shoves a " " in instead.
The results page has one main photo (image 1) and then a series of thumbnails (images 2-10) below it and I need to be able to set this up so that when someone clicks on image 2 it shows the full-size version of that image in the div where image1 sits, and the same for however many remaining images there are.
So my question is, how easy it is to do this with javascript and does anyone have any idea how to code it?
The main photo sits in a div whose id is "mainphoto" the remainder all sit in a div whose id is "thumbpix".
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May 13, 2011
Since upgrading from 1.4.x to 1.6.1 all the code that selects the contents of an XML attribute by the name of 'value' has stopped working. Upon investigation, any time you do
$(someXMLObject).attr("value")
now always returns 'undefined'. This worked fine in previous versions and currently is preventing us from upgrading. I know the obvious solution would be to change the attribute name from 'value' to something else, but this would require some real effort on our part as a lot of our front end code is assuming an attribute of 'value' be passed in.
My question is, is this bug likely to be fixed in a forthcoming release of JQuery or should we implement the necessary workarounds on the assumption that this isn't being worked on?
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Nov 14, 2011
Have searched this forum thoroughly as well as googled it, but no luck in understanding why the following simple code does not work:
Code:
function changeSelect(){
var id = $(this).attr("id");
[code].....
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Jan 3, 2011
I'm building an application that uses calendars extensively, I have single calendars returning nicely but I working on a section that can return multiple calendars (eg. yearly overview) between certain date range ranges. It's working fine but the calendars are appended to the div when the server responds and not in the sequence they are called.
Here's the code I'm using:
Code:
function displayMultiCalendars(date1,date2,a)
{
$.get("<?=base_url();?>cal_center/get_date_range_total/"+date1+"/"+date2, function(data) {
[code].....
So, is there any way of making sure that they return in sequence? I'm sure there's another/better way of looping but I'm not the best with the js/jquery.
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Jul 28, 2011
I'm trying to use $.ajax to make a JSONP call, but the callback function is never executed.I have debugging code in my server that acknowledges that a request is received, but that never runs.The same URL works fine if I paste it into the address bar of my browser.
[Code]...
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Apr 23, 2010
This routine used to work when I was using jQuery 1.3.2. Now that I've switched to 1.4.2 it fails. I've verified that returning to 1.3.2 fixes the problem.
I have a page which includes this select pulldown:
<select
name
="template"
id
[Code]....
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Feb 11, 2006
I'm using the $F of the prototype library to send data through the Ajax
Request. I'm having problems using the $F to reference fields sent
back through an original Request. My first request sends a form back
to the user in the type such as <input text name=foo> and at the bottom
of the returned form I have a second ajax call to send the fresh data
to the another script. The problem is that the new data in the form
cannot be referenced from $F. My question is how can I pass the new
data in the javascript to another Ajax call either by $F or by other
means?
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Sep 27, 2010
The goal is to change the source on the fly (as with a firefox extension webdev or another or even Greasemonkey) to add a link. Until then, easy does it work well. This link launches an application ajax jquery like:
$.get(...) or even $.ajax(...)
If I'm on [URL], added my link, I click and it works, I see the ajax request and pass my "alert ()" gives me the return of application. Great! But if I'm on a site other than mine (the url of the ajax request is [URL] while I'm at [URL] for example), the return of the ajax request is empty.
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Jun 29, 2011
Clearly I am invoking this wrong.
[Code]...
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