String.Length Function Returns Undefined?

Mar 27, 2011

When I run the following code, the .Length function returns "undefined."

var strTest = 'test';
alert(strTest.Length);

Using the typeof function, I know that JS is treating the variable as a string.

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Execution Of Function Bar - Returns Undefined

Dec 12, 2011

Suppose we have following javascript codes: Case 1.
var foo = function (){
var x = "hello";
var bar = function () {
alert(x);
} return bar;
} var bar_ref= foo();
document.write(bar_ref()); // it pops up "hello" and print-outs "undefined".

If we modified above code slightly, shown as follow: Case 2.
var foo = function (){
var x = "hello";
var bar = function () {
alert(x);
} return bar();
} var bar_ref= foo();
document.write(bar_ref()); // it only pops up "hello".

As you can see, Case 2 modified the return value from "return bar" to "return bar()," which won't cause the "undefined" output. To me, it looks like when the JS interpreter executes the line "bar_ref();" it triggers the execution of function "foo", besides both "return bar" and "return bar()" do the same job which is to execute function body of "bar".

The only difference is that after the execution of function bar, its function body does not exist anymore, so when the interpreter executes the line "return bar;" it follows the function identifier "bar" and ends up with "undefined". This is why the Case 1 gives us "undefined", but I am not quite clear about why the Case 2 can trace down to the function body of "bar". Do you have any ideas about such difference outputs?

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Nov 22, 2011

I am trying to make a function that will return part of some xml data, but It keeps returning "Undefined" here is the function, with the call:

Code:

function getUserInfo(u, t) {
$.ajax({
type: 'GET',

[code]....

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Jul 27, 2011

Here is a code I use to calculate distance b//w 2 places using google api. It works perfectly and shows the results in the html but when I add a return statement at the end of the function showlocation() it returns undefined.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "[URL]">
<html xmlns="[URL]">
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
<meta name="robots" content="noindex,follow" />
<title>Calculate driving distance with Google Maps API</title>
<script src="[URL]" type="text/javascript"></script>
<!-- According to the Google Maps API Terms of Service you are required display a Google map when using the Google Maps API. see: [URL] -->
<script type="text/javascript">
var geocoder, location1,addr1,addr2, location2, result1,gDir;
function coolAl(add1,add2) {
addr1=add1;
addr2=add2;
var result= return initialize();
showLocation();
alert(result);
} function initialize() {
geocoder = new GClientGeocoder();
gDir = new GDirections();
GEvent.addListener(gDir, "load", function() {
var drivingDistanceMiles = gDir.getDistance().meters / 1609.344;
var drivingDistanceKilometers = gDir.getDistance().meters / 1000;
result1=location1.address + ' (' + location1.lat + ':' + location1.lon + ')/' + location2.address + ' (' + location2.lat + ':' + location2.lon + ')/' + drivingDistanceKilometers + ' kilometers';
document.body.innerHTML=result1;
return drivingDistanceKilometers;
});
} function showLocation() {
geocoder.getLocations(addr1, function (response) {
if (!response || response.Status.code != 200) {
alert("Sorry, we were unable to geocode the first address");
} else {
location1 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address};
geocoder.getLocations(addr2, function (response) {
if (!response || response.Status.code != 200) {
alert("Sorry, we were unable to geocode the second address");
} else {
location2 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address};
gDir.load('from: ' + location1.address + ' to: ' + location2.address);
}});}});}
</script></head>
<body onload="coolAl('pune','mumbai')">
</html>

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How can I call a function in javascript like code...

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Aug 16, 2010

i used the String.length(string) function in javascript to get the length of string but nothing happened. It doesn't give me a value when i tried to view the result using an alert function. Actually, this kind of problem does not only exist with the length function, it's also the same with the trim(). I have not tried using other functions but perhaps it won't also work. What could be the possible reason for this?

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How would you go about writing a function that returns a string that outputs a branched bulleted list using <ul> and <li> tags of all the html elements in a page? The html elements don't all have id's or names, so I cannot reference them directly. I would like to do it recursively so that I can grab all the elements, not just those two or three levels deep.

[Code]...

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Mar 18, 2010

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RegExp Match Returns An Array Of Length 2?

Jan 11, 2010

why I get an array containing [xml, xml]

Code:
str = 'index.xml'
re = RegExp( /([^s./]+)$/ ) ;
str.match(re) // -> [xml, xml]

I only need xml, not an array, and especially not [xml, xml]

Update: thnx mrhoo, thats clear now!

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Array Value Returns Undefined?

Dec 11, 2009

I have a homework assignment which is pretty simple. It is a grade calculator that uses arrays to gather the grades from the user. This is what I have for the problematic section:

var homework = new Array(2);/* The grades entered by the user for Homework 1, 2, and 3 */
var project = new Array (3);/* The grades entered by the user for Project 1, 2, 3, and 4 */

[Code].....

My problem is the document.write portion of the code, where it is supposed to return either homework[0], project [0], or exam[0], it instead returns undefined. There is no problem with any other subscript. And yes, it does successfully prompt me for each of the [0] subscripts in the first part of the code. Am I just missing something that is right in front of my face? Does all arrays not start with the [0] subscript?

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Jun 2, 2011

I have a json encoded array

[Code]...

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Shouldn't history.previous return an url address of previously visited web site???

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then I visited some web sites and went back, but the code always returns undefined, although there are URLs of the previous and next pages visited .

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Jan 12, 2010

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Feb 25, 2010

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[Code]...

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It doesn't matter, but my object looks like this:

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Feb 13, 2009

I am trying to access the width variable from my main page. Within the imageinfo.js script functions I can alert() the width value which returns 1024. But I can't seem to pass this variable to my main page or access it directly so that I can use document.write() to write the variable on the page. Whenever I try to call the 'width' variable directly from the main page I get undefined. How can I access this variable? However, with the test code below, I was able to get ducument.write() to write the 'width' variable on the page but now the page doesn't stop loading - there's an endless loop in the code...

Code:
BinaryAjax(url,function(http) {findEXIFinJPEG(http.binaryResponse);test(width)},null,useRange ? [0, Range] : null);

Main page
Code:
<html>
<head>
<script>
function test(width){
document.write('Image Width = ' + width)
} </script>

<script type="text/javascript" src="binaryajax.js"></script>
<script type="text/javascript" src="imageinfo.js"></script>
</head>
<body>
<script type="text/javascript">readFileData('image.jpg')</script>
</body>
</html>

Imageinfo script - This script uses the binaryajax script found below.
Code:
/*
* ImageInfo 0.1.2 - A JavaScript library for reading image metadata.
* Copyright (c) 2008 Jacob Seidelin
*/ .....

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Aug 15, 2009

I'm new to ajax. I've made a script that should return results from database but it keeps telling me just undefined. Code what I have:

Code:
var ajax = null;
function showRes(wut) {
if(wut.length == 0) {
document.getElementById("results").innerHTML = "";
return;
} if(window.XMLHttpRequest) {
// IE7+, ff, chrome, opera, safari
ajax = new XMLHttpRequest();
}else if(window.ActiveXObject) {
// retards
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} else {
alert("Your "browser" does not support AJAX!");
return;
} var url = "search.php?q=" + wut;
url = url + "&sid=" + Math.random();
ajax.open("GET", url, true);
ajax.send(null);
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Aug 10, 2006

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Jan 10, 2003

Having trouble with this simple code...


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form.SSN.focus()
return false; }


It always displays the alert even if it does equal 9 digits long. I'm new to javascript so if this is a really simple error just go with it....

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This is quite mysterious. I have several list items like this:

HTML Code:
<li>Private</li>
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Javascript Code:
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I have a form with an id "modClassForm" when I try:$("#modClassForm").serialize() it returns an empty string ("") When I get the action attribute it's right so it is the form I was expecting. When I do the following:

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