Array Value Returns Undefined?
Dec 11, 2009
I have a homework assignment which is pretty simple. It is a grade calculator that uses arrays to gather the grades from the user. This is what I have for the problematic section:
var homework = new Array(2);/* The grades entered by the user for Homework 1, 2, and 3 */
var project = new Array (3);/* The grades entered by the user for Project 1, 2, 3, and 4 */
[Code].....
My problem is the document.write portion of the code, where it is supposed to return either homework[0], project [0], or exam[0], it instead returns undefined. There is no problem with any other subscript. And yes, it does successfully prompt me for each of the [0] subscripts in the first part of the code. Am I just missing something that is right in front of my face? Does all arrays not start with the [0] subscript?
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Dec 12, 2011
Suppose we have following javascript codes: Case 1.
var foo = function (){
var x = "hello";
var bar = function () {
alert(x);
} return bar;
} var bar_ref= foo();
document.write(bar_ref()); // it pops up "hello" and print-outs "undefined".
If we modified above code slightly, shown as follow: Case 2.
var foo = function (){
var x = "hello";
var bar = function () {
alert(x);
} return bar();
} var bar_ref= foo();
document.write(bar_ref()); // it only pops up "hello".
As you can see, Case 2 modified the return value from "return bar" to "return bar()," which won't cause the "undefined" output. To me, it looks like when the JS interpreter executes the line "bar_ref();" it triggers the execution of function "foo", besides both "return bar" and "return bar()" do the same job which is to execute function body of "bar".
The only difference is that after the execution of function bar, its function body does not exist anymore, so when the interpreter executes the line "return bar;" it follows the function identifier "bar" and ends up with "undefined". This is why the Case 1 gives us "undefined", but I am not quite clear about why the Case 2 can trace down to the function body of "bar". Do you have any ideas about such difference outputs?
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Aug 27, 2009
Shouldn't history.previous return an url address of previously visited web site???
I used this code in my web page: <body onload="alert(history.previous+''+window.history.next)">
then I visited some web sites and went back, but the code always returns undefined, although there are URLs of the previous and next pages visited .
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Feb 25, 2010
I'm doing something with grails + jquery. My controller send a rendered json (which I know is sending correctly) but when the object "arrives" in the callback method it comes undefined. I can see it lenght, but not it's content.
[Code]...
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May 18, 2009
I have to use scrollTop and scrollHeight properties, but on jQuery object it returns `undefined`.
Is there any method to get this property from jq object?
It doesn't matter, but my object looks like this:
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Feb 13, 2009
I am trying to access the width variable from my main page. Within the imageinfo.js script functions I can alert() the width value which returns 1024. But I can't seem to pass this variable to my main page or access it directly so that I can use document.write() to write the variable on the page. Whenever I try to call the 'width' variable directly from the main page I get undefined. How can I access this variable? However, with the test code below, I was able to get ducument.write() to write the 'width' variable on the page but now the page doesn't stop loading - there's an endless loop in the code...
Code:
BinaryAjax(url,function(http) {findEXIFinJPEG(http.binaryResponse);test(width)},null,useRange ? [0, Range] : null);
Main page
Code:
<html>
<head>
<script>
function test(width){
document.write('Image Width = ' + width)
} </script>
<script type="text/javascript" src="binaryajax.js"></script>
<script type="text/javascript" src="imageinfo.js"></script>
</head>
<body>
<script type="text/javascript">readFileData('image.jpg')</script>
</body>
</html>
Imageinfo script - This script uses the binaryajax script found below.
Code:
/*
* ImageInfo 0.1.2 - A JavaScript library for reading image metadata.
* Copyright (c) 2008 Jacob Seidelin
*/ .....
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Nov 22, 2011
I am trying to make a function that will return part of some xml data, but It keeps returning "Undefined" here is the function, with the call:
Code:
function getUserInfo(u, t) {
$.ajax({
type: 'GET',
[code]....
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Mar 27, 2011
When I run the following code, the .Length function returns "undefined."
var strTest = 'test';
alert(strTest.Length);
Using the typeof function, I know that JS is treating the variable as a string.
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Jul 27, 2011
Here is a code I use to calculate distance b//w 2 places using google api. It works perfectly and shows the results in the html but when I add a return statement at the end of the function showlocation() it returns undefined.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "[URL]">
<html xmlns="[URL]">
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
<meta name="robots" content="noindex,follow" />
<title>Calculate driving distance with Google Maps API</title>
<script src="[URL]" type="text/javascript"></script>
<!-- According to the Google Maps API Terms of Service you are required display a Google map when using the Google Maps API. see: [URL] -->
<script type="text/javascript">
var geocoder, location1,addr1,addr2, location2, result1,gDir;
function coolAl(add1,add2) {
addr1=add1;
addr2=add2;
var result= return initialize();
showLocation();
alert(result);
} function initialize() {
geocoder = new GClientGeocoder();
gDir = new GDirections();
GEvent.addListener(gDir, "load", function() {
var drivingDistanceMiles = gDir.getDistance().meters / 1609.344;
var drivingDistanceKilometers = gDir.getDistance().meters / 1000;
result1=location1.address + ' (' + location1.lat + ':' + location1.lon + ')/' + location2.address + ' (' + location2.lat + ':' + location2.lon + ')/' + drivingDistanceKilometers + ' kilometers';
document.body.innerHTML=result1;
return drivingDistanceKilometers;
});
} function showLocation() {
geocoder.getLocations(addr1, function (response) {
if (!response || response.Status.code != 200) {
alert("Sorry, we were unable to geocode the first address");
} else {
location1 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address};
geocoder.getLocations(addr2, function (response) {
if (!response || response.Status.code != 200) {
alert("Sorry, we were unable to geocode the second address");
} else {
location2 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address};
gDir.load('from: ' + location1.address + ' to: ' + location2.address);
}});}});}
</script></head>
<body onload="coolAl('pune','mumbai')">
</html>
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Aug 15, 2009
I'm new to ajax. I've made a script that should return results from database but it keeps telling me just undefined. Code what I have:
Code:
var ajax = null;
function showRes(wut) {
if(wut.length == 0) {
document.getElementById("results").innerHTML = "";
return;
} if(window.XMLHttpRequest) {
// IE7+, ff, chrome, opera, safari
ajax = new XMLHttpRequest();
}else if(window.ActiveXObject) {
// retards
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} else {
alert("Your "browser" does not support AJAX!");
return;
} var url = "search.php?q=" + wut;
url = url + "&sid=" + Math.random();
ajax.open("GET", url, true);
ajax.send(null);
document.getElementById("results").innerHTML = ajax.reponseText;
}
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May 13, 2011
Since upgrading from 1.4.x to 1.6.1 all the code that selects the contents of an XML attribute by the name of 'value' has stopped working. Upon investigation, any time you do
$(someXMLObject).attr("value")
now always returns 'undefined'. This worked fine in previous versions and currently is preventing us from upgrading. I know the obvious solution would be to change the attribute name from 'value' to something else, but this would require some real effort on our part as a lot of our front end code is assuming an attribute of 'value' be passed in.
My question is, is this bug likely to be fixed in a forthcoming release of JQuery or should we implement the necessary workarounds on the assumption that this isn't being worked on?
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Nov 14, 2011
Have searched this forum thoroughly as well as googled it, but no luck in understanding why the following simple code does not work:
Code:
function changeSelect(){
var id = $(this).attr("id");
[code].....
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Jan 11, 2010
why I get an array containing [xml, xml]
Code:
str = 'index.xml'
re = RegExp( /([^s./]+)$/ ) ;
str.match(re) // -> [xml, xml]
I only need xml, not an array, and especially not [xml, xml]
Update: thnx mrhoo, thats clear now!
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Jun 6, 2007
var myString = "hello0x0there";
splitString = string.split(/(0x0){1}/);
in firefox the returned array is 3 elements long, with the middle one being the actual 0x0. is this the intended implementation, and why?
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May 11, 2011
<script>
// Declared Constants
MORSE_ALPHABET = new Array (
'.-', // A
'-...', // B
'-.-.', // C
'-..', // D
'.', // E
'..-.', // F
'--.', // G
'....', // H
'..', // I
'.---', // J
'-.-', // K
'.-..', // L
'--', // M
'-.', // N
'---', // O
'.--.', // P
'--.-', // Q
'.-.', // R
'...', // S
'-', // T
'..-', // U
'...-', // V
'.--', // W
'-..-', // X
'-.--', // Y
'--..' // Z
);
CHAR_CODE_A = 65;
var CTS = prompt('Enter Morse code','here')
var inMessage = CTS.split(' ');
searchLocation(inMessage,MORSE_ALPHABET)
function searchLocation(targetValue, arrayToSearchIn) {
var searchIndex = 0; // Iterative counter
for(i=0;i < targetValue.length;) {
targetValue = targetValue[i];
// Search until found or end of array
while( searchIndex<arrayToSearchIn.length && i != targetValue.length &&
arrayToSearchIn[searchIndex]!=targetValue) {
i++searchIndex++;
} if(searchIndex<arrayToSearchIn.length) {
return String.fromCharCode(CHAR_CODE_A + searchIndex);
} else {
return -1;
}}}
document.writeln(searchLocation(inMessage,MORSE_ALPHABET));
</script><head></head><body></body>
This is my code and I have figured it to create an array from the prompt and then use the function to return the first array it finds but I cant seem to make it go on to the next index of the array. I know that when you return a value the function closes and I have tried to store my return in a variable but its not working the way I want it to or I'm not writing the correct command or is there away to do multiply returns, I think what I need to do is simply but I have been staring at this screen for a while now and just cant see it.
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Jul 23, 2005
in javascript, is there a way to test if an array is undefined????
eg...
for (var x=0; x<10; x++){
if test_array[x] is undefined then x++
document.write(test_array[x])
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Jul 1, 2009
var allProductIDs = [5410, 8362, 6638, 6758, 7795, 5775, 1004, 1008, 1013, 1014, 1015, 1072, 1076, 1086, 1111, 1112, 1140]; lastProductID = 6758;
for some reason I get a -1 or I guess which is equivalent to not found for this:
alert(allProductIDs[allProductIDs.indexOf(lastProductID));
I can't figure out for the life of my why because it should find 6758 and that would be index 3. If it's index 3 then I should get back 6758 I would think.
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Oct 16, 2002
what is the reason for the undefined answer?
<head>
</head>
<body>
<script>
var numberstring = "123 456 789";
document.write(numberstring);
var matchnumber = new Array();
matchnumber = numberstring.match(/d+/g);
alert (matchnumber.lenght);
</script>
</body>
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Feb 20, 2009
I am working on a very simple code to determine the highest value from an array and also use parallel arrays.
The problem I am having is, when I try to invoke the parallel array namesArray it returns undefined.
I have coded the function so it can be used to find the highest value in more arrays as this is only the beginning of my code. Im not sure if this is what is causing the problems but I have a feeling it is code...
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Apr 23, 2010
This routine used to work when I was using jQuery 1.3.2. Now that I've switched to 1.4.2 it fails. I've verified that returning to 1.3.2 fixes the problem.
I have a page which includes this select pulldown:
<select
name
="template"
id
[Code]....
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Apr 5, 2011
The form allows users to enter there details, and when they click on the signup button the following is suppose to happen
1. Thank you note for signing up is displayed, including details they just entered
2. The details entered are stored in an array
3. When you want to view all signups you can click on a signup button and all details are shown
4. The form resets and clears all input fields
I have a form that allows input and functions that validate input, store input, and shows the input and html for the design layout. [code] The two buttons are called signup and members [code]When i run it i can enter all the details and click on signup all the details are still there and then i click on members and it shows all the details i have just entered along side the string signup but it also displays the words 'undefined', so I think there are problems with the array.
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Apr 7, 2009
I keep getting <undefined> when I alert out the value of my array 'fadeimages1'. Using php/mysql I retrieve filenames from a directory and create <INPUT> fields to store the filenames. In the javascript portion of the code, I use getElementsByName() to retrieve all of the <INPUT> fields. I then declare an array, 'fadeimages1'. Next, using a for loop I try to copy the values from the <INPUT> fields into the array 'fadeimages1'. When I alert out the length and value variable for each <INPUT> field, I get the correct filename, but after trying to store the value into 'fadeimages1' array, I get value is <undefined> when I alert it out. BTW, the following code uses 'fadeimages1.push()', but I also tried 'fadeimages1[i]=...'. Both result in <undefined> values.
[Code]....
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Oct 8, 2009
Either I'm having a really dim Friday, or something strange is going on. I'm trying to add a method to the Validator plugin, using the following regex:
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May 10, 2009
I use ASP to write the arrays at the start of my page:
<script language="Javascript">
var ArrManu1 = new Array();
var ArrManu2 = new Array();
var ArrManu3 = new Array();
[Code]....
...to populate the second dropdown box. However, when the user selects the first option in the first dropdown box (therefore making the variable "Co" equal to 1), ((ManuArr[Co-1])[i-1]) is "undefined" - why doesn't it add "Bell" to the dropdown?
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Oct 4, 2010
The .find() method does not seem to match on input fields by using a class. The ti This problem seems to be only visible on input fields. The following is a demonstration of the issue:
Example at [url]
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Jun 22, 2006
I have a page with a div on it. The div displays a user comment. When
the user logs into this page, their current comment is pulled from a db
and displayed in the div. The user can edit the comment through a
pop-up that contains a textarea. When the user hits OK on the pop-up,
the text in the textarea is sent to a function on the main page. The
function inserts the text into the div's text node.
Please don't ask why I'm making this so complicated - there are other
things going on on the page and the pop-up that are irrelevant to my
problem.
Everything works perfectly except when the user puts carriage returns
in their comment. For some reason I can't get the carriage returns to
show up in the div. BUT! When they view the existing comment in the
div (the one pulled from the database) the carriage returns are
displayed. That initial display does not use any javascript - it's
just php so the page is initially rendered with the text in the div.
So it seems that when I programmatically put text into my div, the
carriage returns don't show. But if the page is rendered with the text
already there, the carriage returns do show.
This seems like it should be so simple, what am I doing wrong??? Do I
have to replace the carriage returns with a different character (e.g.
<br>,
,
,
,
)? Or is there a css setting for the div?
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