Double Ajax Calls, Using $F The Second Time Returns Null

Feb 11, 2006

I'm using the $F of the prototype library to send data through the Ajax
Request. I'm having problems using the $F to reference fields sent
back through an original Request. My first request sends a form back
to the user in the type such as <input text name=foo> and at the bottom
of the returned form I have a second ajax call to send the fresh data
to the another script. The problem is that the new data in the form
cannot be referenced from $F. My question is how can I pass the new
data in the javascript to another Ajax call either by $F or by other
means?

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Code:

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Code:
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a
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Code:
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/**
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* @return none
*/
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{

var sourceListBox = document.getElementById(sourceListId);
var destListBox = document.getElementById(destListId);

var sourceTableName ;
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sourceTableName = "left_table";
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if(sourceListId == 'secondList')
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sourceTableName = "right_table";
destTableName = "left_table";
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}
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*/
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var url = '/run.php/SelectList'
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var myAjax = new Ajax.Request(
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method: 'get',
parameters: pars,
onComplete: showResponse
}
);
}

function showResponse(originalRequest)
{
// CODE IN THIS FUNCTION DOES NOT ALWAYS EXECUTE.
}

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