I'm calling a ajax function that brings back the results, it works fine the first time i call the ajax function but if i call it again nothing get's updated.here is ajax function in search.php (This is just an example - to keep it simple i'm only passing a random number)
Code:
function searchUsers() {
var iamt = document.getElementById('sGender').value;
[code]....
I'll make it short. Here's the code (the GET request is taken from a Google example):
Code:
<html>
<script>
function hello() {
[Code]....
The problem: the alert never displays. Firebug shows xmlhttp.status = 0 and responseText = "" all the time. The page is on my local machine.
P.S> I've tried doing a synchronous call as well but that gives me an error message; something like 0x80004005 (NS_ERROR_FAILURE) [nsIXMLHttpRequest.send
Hope this is where I'm supposed to post, I'mlookingfor something for my site I'm trying to if a button is pressed a form comes up, I'm also trying to allow this to happen as many times as the user requires.
Eg button is pushed they input text and they hit add more code, they another text box comes up, then when they have done it they hit submit, it then goes through to the database
I am building an app in Facebook and would like to pull in some Causes stats. In order to do this I am using jQuery and the ajax call. I am also using YQL.
Here is what I have:
As you know this is getting pulled in through an iFrame. This is working just fine in Chrome and FF.
We are using the jquery droppable plugin on our portal. We have a situation when drag n drop brings in the IE 8 mixed content warning dialog. There is a AJAX load request which is fired when there is a drop. Does this plugin have support over SSL? Is there any way to fix this issue. I did use Fiddler, HTTPWatch Basic and also the FireFox Net tab and the AJAX requests are indeed https://.
View 2 Replies View RelatedI have a <div> tag that contains a table of results returned using AJAX. I have an onmouseover on the div so that when the user is viewing the results the div stays visible. An onmouseout is also declared so that when the user goes off of the div, it will disappear after a few seconds. When the user clicks on an entry I perform some logic and close the div.
However the problem occurs when my AJAX returns too many results to display in the set size of my div. When this occurs my div becomes scrollable. When the user is interacting with the scrollable, it seems to fire the onmouseout event because the div disappears.
If I am doing this:
alert($(".ivts_thead").find("tr:first").find("td").length);
alert($(".ivts_thead tr:first td").length);
I get in both cases the same result, the expected elements are in my object, but in the second case, I get a Firebug warning saying "Unknown pseudo-calls or pseudo-element 'first'". This happens each time I am adding any :filter to any selector which uses more than one single expression. Does that mean that I should create my selectors as I did in the first case?
With storing values Ajax call results into Javascript:
View 1 Replies View RelatedI'm using BBC's glow to make an ajax post, its works fine, but I'm having trouble displaying the results, if I use:
It displays the results in a div with all the html escaped.
Does anyone know how I can display the results as html?
Code:
I've got a page that lists a bunch of info in a large table. In each row is a link, and when that link is clicked on, an ajax call fires that returns detailed info on the item in that row. I usually display the html just to the right of the table, but the table has gotten too large. I need to display the info in a pop up now. The only thing is, how do I get the results of my ajax call into a pop up window? I've been having an awful time getting this to work.
I'm using JQuery to make the ajax call, what can I put in my success of complete event to create the pop up using the data the ajax call returns?
We're using jQuery ajax quite a bit without issue. Today, however, we ran into an issue where the results of a query are not displayed.fyi... the following works fine in firefox. scenario:
1. load ajax "$("#location").load( url... )" used to retrieve results
2. using fiddler, we can see the results are returned as expected
3. results not displayed. look at the updated dom in IE8 with dev tools and the results are not put into the display area Additional info...
a. using $("#location").load( url, function(data) { alert(data); }); the alert shows the results are returned via the function call as well.
b. the #location is an empty div.. e.g. <div id="location"></div>
c. if we put some text in the div, it will be removed, by the call, but the results still will not display
d. we have removed all .show(), .hide() options
e. if we remove the ajax call and just do a $("#location").text("blah blah blah..."); the results are displayed
f. we have tried both 1.3.2 and 1.4.a1 again, every variation works just fine in firefox.t
This is tough to explain which makes it impossible to search on. I'm guessing this is very basic.
I have an array of objects with variables and ids.
[
{
id: "totalCountOfPeopleToSite",
action: "add",
[Code].....
I loop through this array and create an AJAX request to Google Analytics who returns the data I requested (or an error).
When the data comes back, I want to re-associate it with the object used to make it (as you can see, there might need to be an action performed on it and it should be stored with its ID so I can use it later).
I feel like I've read about a built-in way to pass along arbitrary information (in this case just getting an AJAX request with my made up "id" would be enough), but I can't find it anywhere, and I'm not explaining myself well enough to the Google to get results back.
In the code below I am trying to show the echo statement from a php file. The ajax call works when I use the alert(), but I am trying to put it in a div tag but not working.
View 1 Replies View RelatedIs it possible to return Query results from a jquery $.ajax POST call?It seems as though it will only return one value. What am I missing? [code]
View 1 Replies View RelatedThis form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
View 15 Replies View RelatedI am trying to use a $.post call in jQuery to check a user's credentials before submitting a form (so I can show errors without reloading the page), but I've run into a problem. I know why it is, because AJAX is not synchronous, but I just can't figure out how to do it.
In my code the script I'm making the call to returns "valid" or "invalid". If the return is "valid", I want to submit the form, if not, show an error message. Here is a simplified version:
$("#my_form").submit( function () {
some_value = "username"
$.post(script_location, {data : some_value}, function (data) {
response = data
[Code]...
This obviously does not work because code is executed quickly one after another and the variable "response" is not yet set when the execution gets to the if statement, since it is set sometime later, asynchronously.
I looked into using functions, callbacks, but nothing seems to work properly, I always run into the same issue. This is probably really simple, i just a complete dunce, please do let me know what is the standard way of doing this properly.
I'm new to ajax. I've made a script that should return results from database but it keeps telling me just undefined. Code what I have:
Code:
var ajax = null;
function showRes(wut) {
if(wut.length == 0) {
document.getElementById("results").innerHTML = "";
return;
} if(window.XMLHttpRequest) {
// IE7+, ff, chrome, opera, safari
ajax = new XMLHttpRequest();
}else if(window.ActiveXObject) {
// retards
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} else {
alert("Your "browser" does not support AJAX!");
return;
} var url = "search.php?q=" + wut;
url = url + "&sid=" + Math.random();
ajax.open("GET", url, true);
ajax.send(null);
document.getElementById("results").innerHTML = ajax.reponseText;
}
I have just started learning JQuery and have a doubt in the below code. $.get('myhtmlpage.html', myCallBack);The doubt is should the 1st parameter of the get function be a HTML file or can it be a unction name?
View 1 Replies View RelatedI have a program that calculates change and added a function to determine what currency that should be dispensed based on the change.Right now with my code as is, the calculate change portion works, also if I manually enter a value into the change field it will calculate the currency to be dispursed. My problem is I can't get it to read the value passed to the currency field from the calculate change portion. Here is my code:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<meta name="Content-Script-Type" content="text/javascript">
[code]....
so, the pseudo code: - on change of input contents, check to see if two input fields are set - if set, update a third field with "loading..." text and a loading gif - use ajax to send data to a url, and get a calculated json response - update the third field with the calculated response
I know I'm getting the correct response, according to firebug: {"pace":"10:00"}
the code:
$('#run_distance').change(function() {
if ($(this).val() != '' && $('#run_time').val() != '')
{
$('#run_pace').val('Calculating Pace…');
[Code].....
how to update the #run_pace input field with the json response.
I'm using JSON/jQuery to pre populate a drop down menu. What I want to do, is once I select a plan from the drop down menu and click submit (go button), to get the details about the plan. The drop down menu get's pre populated, but I don't get anything after clicking go. I check the functions and it seems that in the DoPlanSearch() I get the alerts showing the newly constructed URL that gets me the correct JSON. But not sure what happens once the data is processed after that. I say this, because my alert statement in the DoPlanSearchCompleted(data) gets me NULL data.
I'm just getting started with this, I'm not exactly sure what's the best approach. Also, I'm not sure the way .JSON files is setup here works, it does on my Dev server though.
Code has line: function DoPlanSearchCompleted(data)
It should read function UserPlanSearchCompleted(data). The same problem though exists.
Today I've tried to create simple hover effect on a <div>: if the cursor is over the box, the background-image css property of the div is modified. On the HTML side, a <div> with an id:
<div id="round">Blah blah
</div>
I'm trying to pass an object to a function and not getting the results I need. If I get a reference to the object and pass it like so
[Code]...
Here's the problem: I have several hidden divs containing information. When you click on a link, javascript executes which is supposed to move the appropriate info from one of the hidden divs into the visible 'body' div. The javascript isn't working, though, and I'm getting 'undefined' instead
View 2 Replies View Relatedhow do i pass values back to javascript from the server via ajax? I don't want to pass entire html. Is there any way to simply pass a JavaScript object or an array without stuff like xml and json? I could probably do an eval() on the result to convert it to a javascript understandable array, but maybe there's a more clever way to do that?
View 2 Replies View RelatedI am trying to use AJAX to pull back mysql table information. I tried to alter an example I found (w3 schools) where they showed how use a selection table to pull a specific line out of a mysql table, using the "q" (not really sure if the "q" character is important or not). xmlhttp.open("GET","xxxxxxx.php?q="+str,true) I follow what they were doing there, but I want to pull the entire table back not just specific lines. (So I got rid of the Q)
Here is a snipit of HTML. The showdata function is part of the testpull.js code. You click the button and it should run the javascript to pull back the entire table and place it in the "placedata" div section.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html lang="en" xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
[Code]....