JQuery :: Associate AJAX Results With Initial Data?
Sep 12, 2010
This is tough to explain which makes it impossible to search on. I'm guessing this is very basic.
I have an array of objects with variables and ids.
[
{
id: "totalCountOfPeopleToSite",
action: "add",
[Code].....
I loop through this array and create an AJAX request to Google Analytics who returns the data I requested (or an error).
When the data comes back, I want to re-associate it with the object used to make it (as you can see, there might need to be an action performed on it and it should be stored with its ID so I can use it later).
I feel like I've read about a built-in way to pass along arbitrary information (in this case just getting an AJAX request with my made up "id" would be enough), but I can't find it anywhere, and I'm not explaining myself well enough to the Google to get results back.
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Oct 27, 2010
I've got a problem on a site using AJAX navigation where when you first request a page, parts of the script haven't been executed, but if you visit again, it's fine. Is there a common pitfall causing this problem?
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Mar 21, 2006
I'm using AJAX to list all values to select box(second) based on first select Box value.
It works fine. but, for initial loading it takes so much time to load. how can i reduce that?
once it loaded first time after that it'z very fast. whatz the problem on initial load time? How to reduce that?
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May 4, 2010
I have a html form which produces 3 post varaibles.
I'd link to be able to call a php file when sumbitted that sends the data from my form and returns the results from my php file to a div on the oringal page.
I know that you can use .load to call a page to be diaplayed within a div $('#container').load('url #div_on_page') but dont know how to send the from data.
this is the code.
<form method="post" id="new_user_form" >
<input type="text" name="newuser" />
<br /><br />
<input type="password" name="newpassword1" />
[Code].....
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Mar 2, 2011
I am building an app in Facebook and would like to pull in some Causes stats. In order to do this I am using jQuery and the ajax call. I am also using YQL.
Here is what I have:
As you know this is getting pulled in through an iFrame. This is working just fine in Chrome and FF.
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Dec 25, 2011
With storing values Ajax call results into Javascript:
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Jan 13, 2010
We're using jQuery ajax quite a bit without issue. Today, however, we ran into an issue where the results of a query are not displayed.fyi... the following works fine in firefox. scenario:
1. load ajax "$("#location").load( url... )" used to retrieve results
2. using fiddler, we can see the results are returned as expected
3. results not displayed. look at the updated dom in IE8 with dev tools and the results are not put into the display area Additional info...
a. using $("#location").load( url, function(data) { alert(data); }); the alert shows the results are returned via the function call as well.
b. the #location is an empty div.. e.g. <div id="location"></div>
c. if we put some text in the div, it will be removed, by the call, but the results still will not display
d. we have removed all .show(), .hide() options
e. if we remove the ajax call and just do a $("#location").text("blah blah blah..."); the results are displayed
f. we have tried both 1.3.2 and 1.4.a1 again, every variation works just fine in firefox.t
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Apr 18, 2011
In the code below I am trying to show the echo statement from a php file. The ajax call works when I use the alert(), but I am trying to put it in a div tag but not working.
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Aug 24, 2009
Is it possible to return Query results from a jquery $.ajax POST call?It seems as though it will only return one value. What am I missing? [code]
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Mar 25, 2010
I am trying to use a $.post call in jQuery to check a user's credentials before submitting a form (so I can show errors without reloading the page), but I've run into a problem. I know why it is, because AJAX is not synchronous, but I just can't figure out how to do it.
In my code the script I'm making the call to returns "valid" or "invalid". If the return is "valid", I want to submit the form, if not, show an error message. Here is a simplified version:
$("#my_form").submit( function () {
some_value = "username"
$.post(script_location, {data : some_value}, function (data) {
response = data
[Code]...
This obviously does not work because code is executed quickly one after another and the variable "response" is not yet set when the execution gets to the if statement, since it is set sometime later, asynchronously.
I looked into using functions, callbacks, but nothing seems to work properly, I always run into the same issue. This is probably really simple, i just a complete dunce, please do let me know what is the standard way of doing this properly.
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Jun 27, 2011
I am using .ajax() to access cross-domain data using JSONP. Because I need to be able to cache the data I want to use a static name for thejsonpCallback function, so I have set the jsonpCallback option in the .ajax() request. However that appears to requires a global function whereas the auto generated function didn't (well maybe it did but that was all hidden from me).
I definitely need to be able to cache the results. Ideally I wouldn't have a global function handling the data. Is there another way to do this? If not what is the best practice way to go about using a global function these days and how do I provide it with the context of the object/module it was called from - which is where the data is needed?
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Jan 1, 2012
so, the pseudo code: - on change of input contents, check to see if two input fields are set - if set, update a third field with "loading..." text and a loading gif - use ajax to send data to a url, and get a calculated json response - update the third field with the calculated response
I know I'm getting the correct response, according to firebug: {"pace":"10:00"}
the code:
$('#run_distance').change(function() {
if ($(this).val() != '' && $('#run_time').val() != '')
{
$('#run_pace').val('Calculating Pace…');
[Code].....
how to update the #run_pace input field with the json response.
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Jul 13, 2009
I am still new to jQuery and I am trying to figure something out. I have this code:
[Code]...
This is working fine on itself. What is does is when I click a link it loads data into the following div. When done loading it slides out. But I want to change the appearance of the slide. I have tried to do that like this: $(this).show("slide", { direction: "down" }, 1000); But this doesn't work. When I check firebug it says the following: o.easing[this.options.easing || (o.easing.swing ? "swing" : "linear")] is not a function
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Oct 11, 2011
For example I have a HTML table...
name | grade | action
bob | 1.0 | [button class="button" id='1']
jack | 2.0 | [button class="button" id='2']
john | 3.0 | [button class="button" id='3']
When I click the button,
[Code]...
so if I were to press buttonid 1 how do I get the grade '1.0' without having to open the database?
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Jan 27, 2010
How do I associate a button with a function andn still have it display text, click to calculate,and start a function in JavaScript
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Jun 21, 2006
I am trying to use DOM to create a UI for editing info pulled from a database. The info pulled are the locations of a given company. So, company A might have 2 locations (address, city, zip), and this is the info I want to present.
The way I have it now I use dom to parse the returned XML file and display the location info for each location on a seperate line. At the end of each line I want a button that the user can click which will then replace the current line (just text) with 3 input boxes populated with the values for address, city, zip.
Another button (UPDATE) will then be used to call a function which will update the db with the new location information. This is all no problem, but the part I cannot fathom is how do I associate the "location id" (from the database) with the UPDATE button on a given line, so that when the UPDATE button is clicked the function it activates will know which location (ie row) in the db to update. Code:
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Aug 31, 2009
i have a tree object, how can i associate keyboard events to it?
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May 31, 2010
i have a series of <select> fields. The first one, via ajax(), generates a 2nd one, based on the first ones' data with the .change() method. there is then a 3rd <select> - who's data will depend on choice of the second one although step 1 works, and i can generate the 2nd one, i still can't generate the 3rd one.
when i test the script on its own, both the 2nd and 3rd <select> fields are fine - but not via the ajax, which leads me to believe that the .change() from the 2nd one, isnt triggering the ajax call - its not being picked up (even the 'hello' alert isnt working).
[Code]...
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Jan 9, 2009
I have a <div> tag that contains a table of results returned using AJAX. I have an onmouseover on the div so that when the user is viewing the results the div stays visible. An onmouseout is also declared so that when the user goes off of the div, it will disappear after a few seconds. When the user clicks on an entry I perform some logic and close the div.
However the problem occurs when my AJAX returns too many results to display in the set size of my div. When this occurs my div becomes scrollable. When the user is interacting with the scrollable, it seems to fire the onmouseout event because the div disappears.
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May 1, 2010
I'm calling a ajax function that brings back the results, it works fine the first time i call the ajax function but if i call it again nothing get's updated.here is ajax function in search.php (This is just an example - to keep it simple i'm only passing a random number)
Code:
function searchUsers() {
var iamt = document.getElementById('sGender').value;
[code]....
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Dec 9, 2010
I'm using BBC's glow to make an ajax post, its works fine, but I'm having trouble displaying the results, if I use:
It displays the results in a div with all the html escaped.
Does anyone know how I can display the results as html?
Code:
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Aug 4, 2010
I've got a page that lists a bunch of info in a large table. In each row is a link, and when that link is clicked on, an ajax call fires that returns detailed info on the item in that row. I usually display the html just to the right of the table, but the table has gotten too large. I need to display the info in a pop up now. The only thing is, how do I get the results of my ajax call into a pop up window? I've been having an awful time getting this to work.
I'm using JQuery to make the ajax call, what can I put in my success of complete event to create the pop up using the data the ajax call returns?
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Jun 22, 2011
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
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Aug 15, 2009
I'm new to ajax. I've made a script that should return results from database but it keeps telling me just undefined. Code what I have:
Code:
var ajax = null;
function showRes(wut) {
if(wut.length == 0) {
document.getElementById("results").innerHTML = "";
return;
} if(window.XMLHttpRequest) {
// IE7+, ff, chrome, opera, safari
ajax = new XMLHttpRequest();
}else if(window.ActiveXObject) {
// retards
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} else {
alert("Your "browser" does not support AJAX!");
return;
} var url = "search.php?q=" + wut;
url = url + "&sid=" + Math.random();
ajax.open("GET", url, true);
ajax.send(null);
document.getElementById("results").innerHTML = ajax.reponseText;
}
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Mar 27, 2009
I have an AJAX script which is used for a "live search" type function.When a user begins to type their search, after 3 characters, my AJAX script jumps into action and shows them a list of possible results.I has worked fine for months, and now suddenly I have found that it is causing a javascript error.I have traced the error down to the "open" call... ie: this.xmlHttp.open("GET", url, true);Like I said, this has worked for ages and I haven't changed these files since I got them working.
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Jul 30, 2009
I have a few input and textarea fields and when the submit button is pressed, I use $.ajax to send the data to a PHP script, which in turn, simply prints the data, which in turn is displayed in an alert msg box back in my callback. (The script will eventually load the data into a database but for simplification this is all it does for now).
The only problem, is that the $.ajax encodes/escapes special characters automatically and I can't figure out how to decode/unescape them to make them usable again. Here is the javascript (I simplified it to make it easy to understand):
$.ajax(
Here is my php ajax script (super simple)
So anyways, everything appears to work fine. I enter some info into 'myTextArea', and press submit. The script sends it to the PHP script, which it turn returns the same value and the javascript puts it in a message box.
So the problem specifically is if I send special characters like any of the quotes ' " (single or double quotes). Lets say my text area had this text in it: It's My "Birthday"
$.ajax sends the following data: It's My "Birthday"
So how do I unescape this? Ya, I could simply replace all backslashes, but I assume there are other characters it may escape in special ways I'm not sure about. What is the proper way to do it?
The only possible way I could figure out to do this was to use escape($('#myTextArea').val())
So the data gets sent as: It%27s%20My%20%22Birthday%22
And then use the PHP command "urldecode" on the other end. It turns out correct that way. However, that doesn't seem like the proper way to do it. Javascript 'escape' command was meant for escaping characters for sending GET variables and for sending formatted URLs. Not for text and input forms. Is there a better/more proper way?
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