Ajax :: Displaying Results Of Call In A Pop Up Window?
Aug 4, 2010
I've got a page that lists a bunch of info in a large table. In each row is a link, and when that link is clicked on, an ajax call fires that returns detailed info on the item in that row. I usually display the html just to the right of the table, but the table has gotten too large. I need to display the info in a pop up now. The only thing is, how do I get the results of my ajax call into a pop up window? I've been having an awful time getting this to work.
I'm using JQuery to make the ajax call, what can I put in my success of complete event to create the pop up using the data the ajax call returns?
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Dec 14, 2010
The general framework is a simple user login function. The user name is selected and a password entered as usual. The function grabs the element values and passes them to a php page that queries the database. An AJAX call returns the password to the function and then I want the innerHTML to be a choice of two web pages, depending on success or failure of validation. There are existing AJAX functions available on the internet but they are overly complicated for what I think should be a simple, quick to load function.
Where I am stuck is that the standard procedure to make an AJAX call is the browser window event. How do you make the call from within the function? I have tried creating two new variables, "success" and "again" to replace xmlhttp, but still stumble on the event to assign a value. I left the blank password protection (if statement) with that variable to demonstrate what I mean.
I've put in my code below, which is in development and successfully alters the innerHTML text depending on user input but I can't figure out how to insert the relevant php page. I have '// out' the testing bits, but left them for info. (I have tried full 'scripting' as the innerHTML, but it's messy.)
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Dec 25, 2011
With storing values Ajax call results into Javascript:
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Apr 18, 2011
In the code below I am trying to show the echo statement from a php file. The ajax call works when I use the alert(), but I am trying to put it in a div tag but not working.
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Mar 25, 2010
I am trying to use a $.post call in jQuery to check a user's credentials before submitting a form (so I can show errors without reloading the page), but I've run into a problem. I know why it is, because AJAX is not synchronous, but I just can't figure out how to do it.
In my code the script I'm making the call to returns "valid" or "invalid". If the return is "valid", I want to submit the form, if not, show an error message. Here is a simplified version:
$("#my_form").submit( function () {
some_value = "username"
$.post(script_location, {data : some_value}, function (data) {
response = data
[Code]...
This obviously does not work because code is executed quickly one after another and the variable "response" is not yet set when the execution gets to the if statement, since it is set sometime later, asynchronously.
I looked into using functions, callbacks, but nothing seems to work properly, I always run into the same issue. This is probably really simple, i just a complete dunce, please do let me know what is the standard way of doing this properly.
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Apr 29, 2010
I'm having a little problem with a jQuery/JS script I just wrote in IE7/8. The problem is the first 2 lines of the returned data are not being displayed (w or wo styling) but only in IE. The strange thing is though if I alert the returned data it's there.
The code can be found at [url]
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Mar 4, 2009
I am also trying to achieve , displaying a loading activity indicator gif till the server (JSP) processes the validation work for my Ajax call.
Below is my code:
Code:
var httpRequest = newXMLHttpRequest();
//Show loading activity indicator gif
showLoadingImg();
[Code].....
The only thing I am not able to see the loading gif functionality.. But as I said..
If I put an alert message in function showLoadingImg() or the make the red line uncomment (making the line a error), Then I am getting the loading gif functionality work..
But, all next functions fail due to above red lined error (if its uncommented).
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Sep 24, 2009
I'm putting together the following website, HGV/LGV Training [URL] and have an issue regarding a form submit action. Basically I've used an open-source script for the search form so can't get any support from the Author.
My problem is that I need the search results to appear in a different URL but at the moment they just appear in a new DIV on the home page. My knowledge of JS is limited and can't get my head around what the OS script is doing. I think the relevant section of the search form is as follows:
<form method=post action=<?echo $_PHP_SELF;?>>
<input type="text" name="zipcode">
<? echo show_country_codes(); ?>
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Nov 2, 2010
I'm trying to get each of the if statements below in a text text box with the result depending on the answer of the equation. However i can't figure out a way to allow the user to click a button to to show the result in a text box.
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
[Code]....
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Feb 17, 2011
I want to do is let the user input a file,then read the contents send it to the server, loop over the inputs to query MySQL, return the results and display it in a user friendly,scrollable table?
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Feb 1, 2011
I have a PHP file which is called upon through AJAX. The PHP file "fetch.php" searches the database with the given JS variables, an x and y co-ordinate, through GET, and brings back the user id associated with those co-ordinates. So I then get that users information... I'm then trying to bring those PHP variables back into the AJAX call on the original page and display the results. Here's what I've got so far...
Javascript/jQuery
Code JavaScript:
<script type="text/javascript">
jQuery.fn.elementlocation = function() {
var curleft = 0;
var curtop = 0;
var obj = this;
do {
curleft += obj.attr('offsetLeft');
curtop += obj.attr('offsetTop');
obj = obj.offsetParent();
} while ( obj.attr('tagName') != 'BODY' ); .....
Everything is working fine, except one thing, I've check the php file and it does echo a username so I know there is a result being sent back from my query. It's just I can't seem to get the user_name_area and user_online_area to display the results from the fetch.php file. Am I parsing them correctly, do I have to assign them to a variable or is what I'm trying to do impossible? I've never attempted this whole json thing before and I seem to be having some problems with it.
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Oct 5, 2011
I have successfully loaded an element of content from another section of our website on a page, but for some reason it is firing .load() twice and displaying the section of content twice, stacked on top of each other.
<script type="text/javascript" src="/js/jquery.162.min.js"></script>
<script type="text/javascript">
$(function() {
$('#site_navigation').load('/store/ .menu_div', function() {
[Code]....
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Sep 18, 2011
I have been searching for a way to display facebook api friends.getAppUsers in set of 5. I am able to do this if i hard code it but I cant seem to find and comprehend a method to do this dynamically.
What i want to achieve is, if i have 43 friends using the application, the code should allow users to view this result in set of 5.
[Code]...
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Apr 15, 2010
I'm using JSON/jQuery to pre populate a drop down menu. What I want to do, is once I select a plan from the drop down menu and click submit (go button), to get the details about the plan. The drop down menu get's pre populated, but I don't get anything after clicking go. I check the functions and it seems that in the DoPlanSearch() I get the alerts showing the newly constructed URL that gets me the correct JSON. But not sure what happens once the data is processed after that. I say this, because my alert statement in the DoPlanSearchCompleted(data) gets me NULL data.
I'm just getting started with this, I'm not exactly sure what's the best approach. Also, I'm not sure the way .JSON files is setup here works, it does on my Dev server though.
Code has line: function DoPlanSearchCompleted(data)
It should read function UserPlanSearchCompleted(data). The same problem though exists.
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Nov 7, 2011
I've got this:
Code:
var noteCount = "";
jsonRequest('media.getFiles', params,
function(result) { noteCount = result['totalCount']},
function(exception) { noteCount = "0"},
true
);
The console returns results['totalCount'] with a value of 2 (that's correct).
When I call noteCount for display, it shows nothing. Neither the var set by result or exception.
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Mar 2, 2011
I am building an app in Facebook and would like to pull in some Causes stats. In order to do this I am using jQuery and the ajax call. I am also using YQL.
Here is what I have:
As you know this is getting pulled in through an iFrame. This is working just fine in Chrome and FF.
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Jun 5, 2011
I'm a newbie when it comes to PHP & JQuery. I have a small issue and was wondering if someone could help me out.
I have a PHP page which takes in the 'source' and 'destination' from the user and results the distance in a new window.
I just want the distance displayed within the same window. I have absolutely NO clue how to use Jquery or what the syntax is.[code]...
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May 6, 2010
I found an article [URL] that allows a user to search Google directions from a web page. It works very well, however is it possible to have the resulting page open in a popup window?
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Jan 9, 2009
I have a <div> tag that contains a table of results returned using AJAX. I have an onmouseover on the div so that when the user is viewing the results the div stays visible. An onmouseout is also declared so that when the user goes off of the div, it will disappear after a few seconds. When the user clicks on an entry I perform some logic and close the div.
However the problem occurs when my AJAX returns too many results to display in the set size of my div. When this occurs my div becomes scrollable. When the user is interacting with the scrollable, it seems to fire the onmouseout event because the div disappears.
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Oct 2, 2004
I use php includes to display a small form on a web page.The form has only about 2 fields,and when the user hits submit I want the form to be submitted but at the same time I dont want the page to be redirected.Instead I want a small window to pop up saying thank you or whatever.To see a demonstration of what I want to do,please go to download.com ,scroll down to the bottom of the page and you'll see a poll.When you make a vote a new window pops up showing the results of the vote but you arent moved from download.com's homepage to any other page in the parent window.How can I acheive that?I'm using this code right now:
<script language="JavaScript">
function showpoll() {
window.open('manage.php','manage','width=260,height=360,status=no,scrollbars=yes,resizable=no,toolbar=no');
document.forms["form1"].submit();
}
</script>
<form method="post" action="manage.php" onSubmit= "showpoll();" name="form1">
When I hit the submit button on the form a new window does pop up containing manage.php but it doesnt submit the form since manage.php doesnt give the message that its supposed to give when the form is submitted.It instead asks me to input all the fields.While the parent window is redirected to manage.php and it shows the message that its supposed to show when the form has been submitted.I hope I made myself clear.
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May 1, 2010
I'm calling a ajax function that brings back the results, it works fine the first time i call the ajax function but if i call it again nothing get's updated.here is ajax function in search.php (This is just an example - to keep it simple i'm only passing a random number)
Code:
function searchUsers() {
var iamt = document.getElementById('sGender').value;
[code]....
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Dec 9, 2010
I'm using BBC's glow to make an ajax post, its works fine, but I'm having trouble displaying the results, if I use:
It displays the results in a div with all the html escaped.
Does anyone know how I can display the results as html?
Code:
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Jul 8, 2010
I have a question about child parent window in firefox. I have 2 pages Parent.php and child.php... user enter details in Parents.php to show the results from DB. results are displayed in child.php. I tried to put a link/button on child.php "close the window". it closes BUT it takes me to parent page. IS there anyway I can close both windows simeltaneously???
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Jan 13, 2010
We're using jQuery ajax quite a bit without issue. Today, however, we ran into an issue where the results of a query are not displayed.fyi... the following works fine in firefox. scenario:
1. load ajax "$("#location").load( url... )" used to retrieve results
2. using fiddler, we can see the results are returned as expected
3. results not displayed. look at the updated dom in IE8 with dev tools and the results are not put into the display area Additional info...
a. using $("#location").load( url, function(data) { alert(data); }); the alert shows the results are returned via the function call as well.
b. the #location is an empty div.. e.g. <div id="location"></div>
c. if we put some text in the div, it will be removed, by the call, but the results still will not display
d. we have removed all .show(), .hide() options
e. if we remove the ajax call and just do a $("#location").text("blah blah blah..."); the results are displayed
f. we have tried both 1.3.2 and 1.4.a1 again, every variation works just fine in firefox.t
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Sep 12, 2010
This is tough to explain which makes it impossible to search on. I'm guessing this is very basic.
I have an array of objects with variables and ids.
[
{
id: "totalCountOfPeopleToSite",
action: "add",
[Code].....
I loop through this array and create an AJAX request to Google Analytics who returns the data I requested (or an error).
When the data comes back, I want to re-associate it with the object used to make it (as you can see, there might need to be an action performed on it and it should be stored with its ID so I can use it later).
I feel like I've read about a built-in way to pass along arbitrary information (in this case just getting an AJAX request with my made up "id" would be enough), but I can't find it anywhere, and I'm not explaining myself well enough to the Google to get results back.
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Aug 24, 2009
Is it possible to return Query results from a jquery $.ajax POST call?It seems as though it will only return one value. What am I missing? [code]
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