Insert Data Into The Mysql Database Using Ajax
Oct 19, 2009
The below coding is the javascript coding in which i have used AJAX coding also.its only pagenavigation coding.
function change(which)
{
if(which=="page1")
{
document.getElementById(which).style.borderBottomColor="white";
document.getElementById("page2").style.borderBottomColor="#778";
document.getElementById("page3").style.borderBottomColor="#778";
document.getElementById("page4").style.borderBottomColor="#778";
[Code]...
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Jun 15, 2009
I'm triyng to use the $.ajax jquery function to insert some dates in a database, using php.I have the page that insert the data called : sign.php and in the page I have the form, and the ajax scritp.
$("#submit_sign").click(function(data){
$.ajax({
type: "POST",
url: ("sign.php"),
[code]....
if I use the page without ajax it works, if I use the script jquery it works but doesn't insert the dates in the field, it send only white field. can't pass the variable POST beetween the ajax script and the php script.
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Mar 11, 2011
I've the following AJAX code:
[Code]...
This code works to insert a MySQL record to a Database using AJAX. It works fine on IE, but it's not working on FF or Chrome. When I test it on FF/Chrome, i just get the text "Just a second..." and it doesn't advance from there.
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Jun 6, 2010
could someone please point me in the right direction for creating an AJAX page that displays "live" data from a mysql database? I need the page to update its self every time data changes in a mysql table.
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Jul 11, 2010
I have a form.On the form I have a drop down box that allows the user to select a data set to work with (A or B). The table loads just fine and all is right with the world. No problems there.What I need is for the user to be able to edit the data set and have those changes written directly back to the mySQL database. They also need the option of deleting a record entirely.I know how to do all the database queries, updates, etc. I just don't know how to write the ajax forms to accomplish this.
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Jul 13, 2011
I am having no luck with my post form to mysql. It is only posting the first letter of the word/phrase for the text input fields to the mysql database. It is a photo and text post form. The photo and only first letter of text are posting to database. I am using Jqtouch, jquery, and phonegap.
Here is my form fields:
Here is my java script:
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Nov 13, 2011
I have a .load that executes a php mysql query from another page. This query displays all the data of the database. Each result is wrapped around a div.
<div id ="post<? echo $row['post_id']; ?>">
the id of the div depends on the post id of the result. How do I put the data of $row['post_id'] in my javascript?
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Mar 16, 2004
Not sure if this is the correct forum as it covers data retrieved from mysql in a .js file...
I need to grab the last 5 rows from my database (2 fields per row) and list all 5 in a table but from within a .js file that I can externally link to.
I can manage the php / mysql and the output to a .php page but how can this be contained within a .js file?
I believe it is possible but after 2 days of searching on google I'm appealing for assistance.
I realise this could be done with a php include or iframe but that isn't an option and the only way available to import this data is via an external javascript script.
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Oct 10, 2010
I'm trying to display data from mysql database using getJSON
this is the code JQuery Code
Code:
//get data from database
$.getJSON('getCategories.php', parseCat);
// display data
[Code]....
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Apr 28, 2011
I have a problem with the DIV tag (which I think is related with the Javascript).I cannot insert the form data into the database.
Code:
<script type="text/javascript">
var member_prices = new Array();
member_prices["no"]=200.00;[code]........
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Apr 28, 2011
I have a problem with the DIV tag (which I think is related with the Javascript). I cannot insert the form data into the database.
[Code]...
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Apr 8, 2011
I am writing a web page that accesses Mysql database data through PHP then dynamically displayes the Mysql data when the user mouses over different parts of an imagemap. I use Javascript OnLoad function to load the Mysql data into the header and then I use the Onmouseover function to change the display dynamically.
Here is my question; when I mouse-over a part of an image the data in my side bar changes (exactly what I want) but I can't seem to make the data linkable. For example, when a user mouse-overs a certain part of the image, on the side bar it displays the companies web adr. How do I make that data a link? On the initial load the default data displayed is linkable but because I use <div> </div> to change the data dynamically, I loose the likability.
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Sep 17, 2009
I'm using AJAX for all the updates to the web site I'm building and it works very well. But now I face the need to:
1) Upload a file (an image or video) to a folder in the server.
2) Insert a row in MySQL with the name of the file plus some other information (year and a comment).
The user would upload the file and fill in the information in the same window, and should have a single message (if possible) saying that the file was added or not (meaning both the upload and the insert).I have been doing some googling and found information as how to simulate and AJAX upload, since it seems AJAX does not support file uploads (hope I'm wrong). This is what I found: [URL]
So following that example I could upload the file, and I'd have all the information from the form, in the PHP, and I could synchronize the upload and the insert, but then I can't figure out how to send the OK from the PHP to a Javascript (i guess) to update the html and display the message in the web site.
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Sep 17, 2009
I'm using AJAX for all the updates to the web site I'm building and it works very well. But now I face the need of:
1) Upload a file (an image or video) to a folder in the server
2) Insert a row in MySQL with the name of the file plus some other information (year and a comment).
The user would upload the file and fill in the information in the same window, and should have a single message (if possible) saying that the file was added or not (meaning both the upload and the insert).
I have been doing some googling and found information as how to simulate and AJAX upload, since it seems AJAX does not support file uploads (hope I'm wrong). This is what I found:
So following that example I could upload the file, and I'd have all the information from the form, in the PHP, and I could synchronize the upload and the insert, but then I can't figure out how to send the OK from the PHP to a Javascript (i guess) to update the html and display the message in the web site. And anyway, is this the right approach to do what I need?
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Jun 22, 2011
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
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Jun 20, 2009
I need to create three dropdown boxes (box 1:colour, box 2: price, box 3:brand) and when the user presses "GO" they are returned with the correct information, pulled from corresponding fields in my MYSQL database.
For example, colour: silver, price £100-£200, brand:samsung...should return 5 items on the page. I do not need the dropdown boxes to populate depending on ther previous selection - they are static, so to speak. If possible, I would like the information to be retuned to my page without the URL changing, which leads me to think I will need to be ausing ajax....?
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Dec 24, 2011
i am trying to create a form that where the page will not refresh if the form is submitted specially if the user inputs any errors in the form my problem is i do not know how to send multiple variables using jquery to a php file i saw somewhere that in order to do this you need to concatenate the variables you will be sending this is the code i am using
<html>
<head>
<style type="text/css">
#add(display: none;}
[code]....
the jquery successfully sends the variable to the php file the problem is once i insert it into a database all the variables i sent are concatenated for example in the column stud_no once you send the form this is what will be inserted "123123name=asdasd"
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Apr 14, 2010
I am looking for an Ajax combobox (drop down, not a text box) auto complete script. I searched for it on Google and only result which seems similar to what I am looking for, is dhtmlxCombo. And that one is too complicated for me. What I basicly need is:
When the client types on the drop down, the records appear from MySQL database and when the client chooses one and submits the form, I want the ID (not the text written) to be posted.
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Aug 1, 2010
i am trying to build my form to submit without reloading the screen. I am using jquery and it inserts the data but it also reloads the screen and two database records get inserted. It appears that one is being inserted by jquery and the other is being inserted by the normal form submission. How do I remove/override the normal form submission? My html code is as follows:
[Code]...
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Jan 21, 2010
i want to retrieve data from mysql database using ajax and php. my code is below which does not work
here is index.html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
[Code].....
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Dec 13, 2011
I am attempting to create a profile page with PHP utilizing AJAX technologies as well. I need profile data to auto-refresh on the page when a change is made in the database but every 15-30 seconds intervals are fine too. I would really like to use AJAX/PHP for this because I think it will be good for me to know and learn.
I have checked the internet for this and all of the examples show a form select/combobox where you select a "User" and then it populates the information automatically in a div below.
But... I need AJAX or PHP to READ THE VARIABLE FROM THE URL instead of a form(Combobox) and ultimately refresh the data on the page with the results from the DB query in the php file.
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Mar 11, 2009
How do I insert the following data into a php file using AJAX
function AddCity()
{
itemID = document.form.ItemID.value;
countryID = document.form.refCountryID.value;
regionID = document.form.refRegionID.value;
[Code]....
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Jan 30, 2011
I want to add a comment system after my article, <form id="postform" class="postform"> is written into a MYSQL_QUERY result circle. but after post a comment, the current posted comment will be showed in all the <div class="post_comment"></div>, how to modify jquery ajax part so that the current posted comment only be showed in its own <div class="post_comment"></div>? [code]...
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Sep 2, 2009
Im having the weirdest problems with my ajax. Now first off i have horrible coding convention!! I have one Ajax.js file which handles all my ajax requests and one ajax.php file which handles retrieving data from a database. The problem I am having is when ever I call a certain method which contains a if statement and runs the respective ajax function, it sometimes evaluates the if statement wrong. The weirdest thing of all is when I use FireFox's firebug and step through the javascript code to see why its evaluating the if statement wrong, it evaluates it correctly.
So basically if I don't step through the javascript code it evaluates the if statement wrong which means one of my variables are not being set in time for it to be used in the if statement. BUT if i step through the code with firebug it evaluates the if statement correctly! Now I have tried this is all the browsers and sometimes it evaluates the if statement correctly and when i keep refreshing the page it will sometimes evaluate the if statement correctly! Now I know this makes no sense, but I'm just as confused! The only reason I can think why this is happening is that one of my variables are not being set in time for the if statement to use it!!
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Apr 21, 2009
I want to build-up ajax based friends system. though i no nothing about ajax (would like to learn but) actually i have form where user can add his friend. on very next page of this page he/she can see what he/she is entered and where
they should probably see the add and remove button(which i want to build up using ajax)
how to start for this? till now i have code where user can write his friend name and to the next page he/she can see the value he has written. on submit button it all goes in to database. means i have devloped php form for this.
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Oct 6, 2010
I have a form which goes to my insert page which inserts the data into the table. Except I didn't want to do a redirect to another page so I thought I would do an Ajax call. Both pages work until I change it to an ajax call.
I am pretty certain that it is because I took out the <form action="insert.php"> because otherwise the page would redirect but if that is the case I don't know my way around it and if it isn't the problem I'm not sure what is.
But here is my code:
Form:
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