I've the following AJAX code:
[Code]...
This code works to insert a MySQL record to a Database using AJAX. It works fine on IE, but it's not working on FF or Chrome. When I test it on FF/Chrome, i just get the text "Just a second..." and it doesn't advance from there.
The below coding is the javascript coding in which i have used AJAX coding also.its only pagenavigation coding.
function change(which)
{
if(which=="page1")
{
document.getElementById(which).style.borderBottomColor="white";
document.getElementById("page2").style.borderBottomColor="#778";
document.getElementById("page3").style.borderBottomColor="#778";
document.getElementById("page4").style.borderBottomColor="#778";
[Code]...
my javascript does not working after I retrieve a record that contains square symbol in the database. The square symbol should be a newline in a textarea. This is how the record "looks" in the table: [URL]
I am inserting the record using ASP and the value with square symbol is the value from a textarea with newline/enter. After that I retrieve the value using ASP and pass it to javascript and then the page is not working. If I retrieve other record which contain no square symbol then the script is working.
I'm triyng to use the $.ajax jquery function to insert some dates in a database, using php.I have the page that insert the data called : sign.php and in the page I have the form, and the ajax scritp.
$("#submit_sign").click(function(data){
$.ajax({
type: "POST",
url: ("sign.php"),
[code]....
if I use the page without ajax it works, if I use the script jquery it works but doesn't insert the dates in the field, it send only white field. can't pass the variable POST beetween the ajax script and the php script.
I'm trying to add a single test record (a comment item) to my MySQL database.The double f:ajax tags in commandLink body are to solve a problem, where I had to double click the button to reload content div.And now here comes similar problem:After loading the page, the first click of comment adding button never works - nothing happens. I was adding some logging methods into the addComment method and it is not executed at all on first click. I suspect it's caused by my Ajax reloaded div code, because when I launch such button on a plain page, it works good.Alternatively are there other ways of realizing panel refreshing instead of using ui:include tag, which might be causing the problem here?
View 4 Replies View RelatedI am having no luck with my post form to mysql. It is only posting the first letter of the word/phrase for the text input fields to the mysql database. It is a photo and text post form. The photo and only first letter of text are posting to database. I am using Jqtouch, jquery, and phonegap.
Here is my form fields:
Here is my java script:
I'm using AJAX for all the updates to the web site I'm building and it works very well. But now I face the need to:
1) Upload a file (an image or video) to a folder in the server.
2) Insert a row in MySQL with the name of the file plus some other information (year and a comment).
The user would upload the file and fill in the information in the same window, and should have a single message (if possible) saying that the file was added or not (meaning both the upload and the insert).I have been doing some googling and found information as how to simulate and AJAX upload, since it seems AJAX does not support file uploads (hope I'm wrong). This is what I found: [URL]
So following that example I could upload the file, and I'd have all the information from the form, in the PHP, and I could synchronize the upload and the insert, but then I can't figure out how to send the OK from the PHP to a Javascript (i guess) to update the html and display the message in the web site.
I'm using AJAX for all the updates to the web site I'm building and it works very well. But now I face the need of:
1) Upload a file (an image or video) to a folder in the server
2) Insert a row in MySQL with the name of the file plus some other information (year and a comment).
The user would upload the file and fill in the information in the same window, and should have a single message (if possible) saying that the file was added or not (meaning both the upload and the insert).
I have been doing some googling and found information as how to simulate and AJAX upload, since it seems AJAX does not support file uploads (hope I'm wrong). This is what I found:
So following that example I could upload the file, and I'd have all the information from the form, in the PHP, and I could synchronize the upload and the insert, but then I can't figure out how to send the OK from the PHP to a Javascript (i guess) to update the html and display the message in the web site. And anyway, is this the right approach to do what I need?
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
View 15 Replies View RelatedI need to create three dropdown boxes (box 1:colour, box 2: price, box 3:brand) and when the user presses "GO" they are returned with the correct information, pulled from corresponding fields in my MYSQL database.
For example, colour: silver, price £100-£200, brand:samsung...should return 5 items on the page. I do not need the dropdown boxes to populate depending on ther previous selection - they are static, so to speak. If possible, I would like the information to be retuned to my page without the URL changing, which leads me to think I will need to be ausing ajax....?
could someone please point me in the right direction for creating an AJAX page that displays "live" data from a mysql database? I need the page to update its self every time data changes in a mysql table.
View 1 Replies View Relatedi am trying to create a form that where the page will not refresh if the form is submitted specially if the user inputs any errors in the form my problem is i do not know how to send multiple variables using jquery to a php file i saw somewhere that in order to do this you need to concatenate the variables you will be sending this is the code i am using
<html>
<head>
<style type="text/css">
#add(display: none;}
[code]....
the jquery successfully sends the variable to the php file the problem is once i insert it into a database all the variables i sent are concatenated for example in the column stud_no once you send the form this is what will be inserted "123123name=asdasd"
I am looking for an Ajax combobox (drop down, not a text box) auto complete script. I searched for it on Google and only result which seems similar to what I am looking for, is dhtmlxCombo. And that one is too complicated for me. What I basicly need is:
When the client types on the drop down, the records appear from MySQL database and when the client chooses one and submits the form, I want the ID (not the text written) to be posted.
I have a form.On the form I have a drop down box that allows the user to select a data set to work with (A or B). The table loads just fine and all is right with the world. No problems there.What I need is for the user to be able to edit the data set and have those changes written directly back to the mySQL database. They also need the option of deleting a record entirely.I know how to do all the database queries, updates, etc. I just don't know how to write the ajax forms to accomplish this.
View 4 Replies View Relatedi am trying to build my form to submit without reloading the screen. I am using jquery and it inserts the data but it also reloads the screen and two database records get inserted. It appears that one is being inserted by jquery and the other is being inserted by the normal form submission. How do I remove/override the normal form submission? My html code is as follows:
[Code]...
I am trying to create a form to edit existing data in my database. I have 2 drop down boxes( category then item) they do not work correctly. I am using php to populate the drop down boxes but there is nothing dynamic about doing this. I think I need to totally rewrite the page using java script or Ajax but I don't know what parts.So I want the user to select a category from a drop down list populated by database then have it populate the item list(so I think both of these need to be java script in case they change the category it will re populate the item list). Then I just want the selection of the item to pull the information to my form so they can update it and save the update(which I am pretty sure I can save the update as a php function but need to populate the item editable information in java script). I am really looking for help on how to setup the page with java script to make database queries and use the results to update parts of the page.In case you confused here is my flow:page loads
-User selects catagory query database for item list (on change event it think)
-User selects item.Item information is pulled and displayed from database(cost, serial number, quantity(another on change event)
-User is able to edit information and save updated results(run an update.php...)
I have my doubts if this question belongs to the javascript side since it's all good until the data from MySQL comes in, but since the javascript is the one breaking I'll take my chances.
The external js (portada.js)
Code:
$(document).ready(function(){
var currentPosition = 0;
var currentPosition2 = 0;
var currentPosition3 = 0;
[Code]....
As you can see I have three divs with different slideshows (slideshow, slideshow2 and slideshow3), they have products that slide to the left. When I was testing to make sure it all looks good the sliding feature was working fine, but I lost this feature when the data was being retrieved from MySQL (at the moment on <div class="slide">).
I am new to jquery and i have no freaking idea about jquery. One of the requirement is to use Jquery to datastore and dataretrieval so on my aspx page, a user enters a comment and clicks on "Add" button.When user clicks on Add button, I wan to add comments to database. Once data is added to db, I also want to retrieve same data, user name and current datetime as a dataset and show it on the page. How can I achieve this? I am creating a webservice which accepts "comments" as parameter and stores into database.
View 2 Replies View RelatedOn my mobile app, the 2nd input box isn't working as it should?!it's called weight1
<!doctype html>
<html>
<head>
[code]....
so far any values recorded in my database are shown on the map:
[Code]...
I have a jQuery code to allow users to login using a lightbox [URL] and immediately start downloading files, without being redirected or having the page reloaded. It's perfectly working in Firefox but Internet Explorer keeps showing the login box until I reload the page
[Code]...
im using this teturial [URL].. how to insert to mysql i make a new database for test but can't found the way how to insert the records
View 5 Replies View Relatedhow to connect with MYSQL database using javascript..
View 3 Replies View RelatedI want to ask you is it possible to use jquery dialog with php. Using this tutorial [URL] I want to call a php script with will delete a row into Mysql database.
View 2 Replies View RelatedBelow i have attached my code. This code is working.....but i want some modification in that code such that when i select 'vegetable' or 'fruits', it should give list of that selected one in second list, BUT THAT list should be stored in mysql database.
In the below program , i have hard-coded that second list, but i want second list to be dynamic from database.
Code:
I am trying to execute a query in mysql using javascript to check the username isnt taken, but dont know how.
View 3 Replies View Related