AJAX :: User To Be Able To Edit The Data Set And Have Those Changes Written Directly Back To The MySQL Database?
Jul 11, 2010
I have a form.On the form I have a drop down box that allows the user to select a data set to work with (A or B). The table loads just fine and all is right with the world. No problems there.What I need is for the user to be able to edit the data set and have those changes written directly back to the mySQL database. They also need the option of deleting a record entirely.I know how to do all the database queries, updates, etc. I just don't know how to write the ajax forms to accomplish this.
could someone please point me in the right direction for creating an AJAX page that displays "live" data from a mysql database? I need the page to update its self every time data changes in a mysql table.
I would like to be able to generate a table from which I can easily edit the contents of a mySQL database (similar to phpMyAdmin.) In that table I would like to have a button that will open a pop-up, allowing me to edit - and maintain formatting such as apostrophes and line breaks - a long description field. That popup will then populate a hidden input field on its parent with the modified description.
I've got the pop-up opening and its fields are populated using php's GET function (see line 11). The special characters, particularly carriage returns, are messing me up; I can remove them using php's str_replace, but I want to retain them for formatting.
I am trying to set up a web based tool for my wife and I to use to balance our checkbook together. I am using HTML, Javascript (Ajax), PHP and MYSQL. I have read beginner books on all of these subjects, I can get data out of MYSQL, BUT can't do it the way I want to do it. If someone could point me to a book, or even the name of what I need to study it would be very helpful. The top line will always be input. But as you submit the top line it refreshes the "growing list" beneath it. (kind of like on-line banking, where you can look at 50 or so lines and then go back further if necessary) The catch is within the "growing list" I want to show Bank and book balance running totals and have three buttons next to each transaction ... EDIT DELETE SUBMIT. If edit is clicked, I want to be able to change that line and then resubmit it to MYSQL.
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This way we can both input our transactions as we spend money and know at all times how much money is in the account. What do I need to study to be able to program this?
I am having no luck with my post form to mysql. It is only posting the first letter of the word/phrase for the text input fields to the mysql database. It is a photo and text post form. The photo and only first letter of text are posting to database. I am using Jqtouch, jquery, and phonegap.
I've got this form that needs to check if the user input is already in the database, if this isn't the case it should disable the submit button and display an error depending on which input isn't found.
I'm triyng to use the $.ajax jquery function to insert some dates in a database, using php.I have the page that insert the data called : sign.php and in the page I have the form, and the ajax scritp.
if I use the page without ajax it works, if I use the script jquery it works but doesn't insert the dates in the field, it send only white field. can't pass the variable POST beetween the ajax script and the php script.
I have a .load that executes a php mysql query from another page. This query displays all the data of the database. Each result is wrapped around a div.
<div id ="post<? echo $row['post_id']; ?>">
the id of the div depends on the post id of the result. How do I put the data of $row['post_id'] in my javascript?
Not sure if this is the correct forum as it covers data retrieved from mysql in a .js file...
I need to grab the last 5 rows from my database (2 fields per row) and list all 5 in a table but from within a .js file that I can externally link to.
I can manage the php / mysql and the output to a .php page but how can this be contained within a .js file?
I believe it is possible but after 2 days of searching on google I'm appealing for assistance.
I realise this could be done with a php include or iframe but that isn't an option and the only way available to import this data is via an external javascript script.
I am writing a web page that accesses Mysql database data through PHP then dynamically displayes the Mysql data when the user mouses over different parts of an imagemap. I use Javascript OnLoad function to load the Mysql data into the header and then I use the Onmouseover function to change the display dynamically.
Here is my question; when I mouse-over a part of an image the data in my side bar changes (exactly what I want) but I can't seem to make the data linkable. For example, when a user mouse-overs a certain part of the image, on the side bar it displays the companies web adr. How do I make that data a link? On the initial load the default data displayed is linkable but because I use <div> </div> to change the data dynamically, I loose the likability.
I would like to use jQuery to prepopulate a form - ie make a call to a php program to get data from a database and pre-populatea form with appropriate data for the user. Can anyone point me in the right direction for some examples on the simplest way to do this?
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
I am trying to use AJAX to pull back mysql table information. I tried to alter an example I found (w3 schools) where they showed how use a selection table to pull a specific line out of a mysql table, using the "q" (not really sure if the "q" character is important or not). xmlhttp.open("GET","xxxxxxx.php?q="+str,true) I follow what they were doing there, but I want to pull the entire table back not just specific lines. (So I got rid of the Q)
Here is a snipit of HTML. The showdata function is part of the testpull.js code. You click the button and it should run the javascript to pull back the entire table and place it in the "placedata" div section.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html lang="en" xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head>
I need to create three dropdown boxes (box 1:colour, box 2: price, box 3:brand) and when the user presses "GO" they are returned with the correct information, pulled from corresponding fields in my MYSQL database.
For example, colour: silver, price £100-£200, brand:samsung...should return 5 items on the page. I do not need the dropdown boxes to populate depending on ther previous selection - they are static, so to speak. If possible, I would like the information to be retuned to my page without the URL changing, which leads me to think I will need to be ausing ajax....?
I am looking for an Ajax combobox (drop down, not a text box) auto complete script. I searched for it on Google and only result which seems similar to what I am looking for, is dhtmlxCombo. And that one is too complicated for me. What I basicly need is:
When the client types on the drop down, the records appear from MySQL database and when the client chooses one and submits the form, I want the ID (not the text written) to be posted.
I am attempting to create a profile page with PHP utilizing AJAX technologies as well. I need profile data to auto-refresh on the page when a change is made in the database but every 15-30 seconds intervals are fine too. I would really like to use AJAX/PHP for this because I think it will be good for me to know and learn.
I have checked the internet for this and all of the examples show a form select/combobox where you select a "User" and then it populates the information automatically in a div below.
But... I need AJAX or PHP to READ THE VARIABLE FROM THE URL instead of a form(Combobox) and ultimately refresh the data on the page with the results from the DB query in the php file.
This code works to insert a MySQL record to a Database using AJAX. It works fine on IE, but it's not working on FF or Chrome. When I test it on FF/Chrome, i just get the text "Just a second..." and it doesn't advance from there.
I am trying to create a web page in which the contents of one selection list depends upon which element in another selection list is chosen, but where the information to populate the first selection list comves from an SQL database on the web server.
There are a couple of these situations in my application but, for example, the first list might be a list of counties, and the second list a list of states/provinces. Obviously the names of counties depend upon which state/province is chosen, but there are too many possibilities to be able to embed them within the web page itself. So when the user selects a state/province I need to go to the server to ask for the list of counties.
I have seen a number of posts that sort of address this issue. For example it is suggested to use <script src="a URL"/> to ask the server side code to send up data of type "text/javascript". However the examples do not seem to address how the server side code would know which state/province the user had selected.
If there is a web site that addresses this sort of thing, I would appreciate any pointers.
I want to add a comment system after my article, <form id="postform" class="postform"> is written into a MYSQL_QUERY result circle. but after post a comment, the current posted comment will be showed in all the <div class="post_comment"></div>, how to modify jquery ajax part so that the current posted comment only be showed in its own <div class="post_comment"></div>? [code]...
Im having the weirdest problems with my ajax. Now first off i have horrible coding convention!! I have one Ajax.js file which handles all my ajax requests and one ajax.php file which handles retrieving data from a database. The problem I am having is when ever I call a certain method which contains a if statement and runs the respective ajax function, it sometimes evaluates the if statement wrong. The weirdest thing of all is when I use FireFox's firebug and step through the javascript code to see why its evaluating the if statement wrong, it evaluates it correctly.
So basically if I don't step through the javascript code it evaluates the if statement wrong which means one of my variables are not being set in time for it to be used in the if statement. BUT if i step through the code with firebug it evaluates the if statement correctly! Now I have tried this is all the browsers and sometimes it evaluates the if statement correctly and when i keep refreshing the page it will sometimes evaluate the if statement correctly! Now I know this makes no sense, but I'm just as confused! The only reason I can think why this is happening is that one of my variables are not being set in time for the if statement to use it!!
I want to build-up ajax based friends system. though i no nothing about ajax (would like to learn but) actually i have form where user can add his friend. on very next page of this page he/she can see what he/she is entered and where
they should probably see the add and remove button(which i want to build up using ajax)
how to start for this? till now i have code where user can write his friend name and to the next page he/she can see the value he has written. on submit button it all goes in to database. means i have devloped php form for this.
there is a selection of menus on the screen that you can change select different options to show you a price.
issue is as follows; i want to be able to create url's for every product in the database for google adword purposes; for example if they click on the google ad they come direct to the page/selection from the table/drop downs that is what they want. currently we have got as far as creating the below link;
[URL]
this link will take you to the product, but the drop downs from the menus haven't changed, just the price and the quantity.
i need to know of a way of selecting from the database and it be able to change the drop downs from a specific url.
our problem is we need to populate a select option in order of the one we send.
