I have a .load that executes a php mysql query from another page. This query displays all the data of the database. Each result is wrapped around a div.
<div id ="post<? echo $row['post_id']; ?>">
the id of the div depends on the post id of the result. How do I put the data of $row['post_id'] in my javascript?
could someone please point me in the right direction for creating an AJAX page that displays "live" data from a mysql database? I need the page to update its self every time data changes in a mysql table.
View 1 Replies View RelatedI have a listings page which displays results using images and text which are stored in a MySQL database, all is working fine. The images are pulled into the page from the database and each listing can have up to a maximum of 10 images. Some will have all 10, some probably one or two, so the page is coded such that if there's an image in the field, it displays a thumbnail, if there isn't then it shoves a "Â " in instead.
The results page has one main photo (image 1) and then a series of thumbnails (images 2-10) below it and I need to be able to set this up so that when someone clicks on image 2 it shows the full-size version of that image in the div where image1 sits, and the same for however many remaining images there are.
So my question is, how easy it is to do this with javascript and does anyone have any idea how to code it?
The main photo sits in a div whose id is "mainphoto" the remainder all sit in a div whose id is "thumbpix".
I'm triyng to use the $.ajax jquery function to insert some dates in a database, using php.I have the page that insert the data called : sign.php and in the page I have the form, and the ajax scritp.
$("#submit_sign").click(function(data){
$.ajax({
type: "POST",
url: ("sign.php"),
[code]....
if I use the page without ajax it works, if I use the script jquery it works but doesn't insert the dates in the field, it send only white field. can't pass the variable POST beetween the ajax script and the php script.
I am having no luck with my post form to mysql. It is only posting the first letter of the word/phrase for the text input fields to the mysql database. It is a photo and text post form. The photo and only first letter of text are posting to database. I am using Jqtouch, jquery, and phonegap.
Here is my form fields:
Here is my java script:
The below coding is the javascript coding in which i have used AJAX coding also.its only pagenavigation coding.
function change(which)
{
if(which=="page1")
{
document.getElementById(which).style.borderBottomColor="white";
document.getElementById("page2").style.borderBottomColor="#778";
document.getElementById("page3").style.borderBottomColor="#778";
document.getElementById("page4").style.borderBottomColor="#778";
[Code]...
Not sure if this is the correct forum as it covers data retrieved from mysql in a .js file...
I need to grab the last 5 rows from my database (2 fields per row) and list all 5 in a table but from within a .js file that I can externally link to.
I can manage the php / mysql and the output to a .php page but how can this be contained within a .js file?
I believe it is possible but after 2 days of searching on google I'm appealing for assistance.
I realise this could be done with a php include or iframe but that isn't an option and the only way available to import this data is via an external javascript script.
I'm trying to display data from mysql database using getJSON
this is the code JQuery Code
Code:
//get data from database
$.getJSON('getCategories.php', parseCat);
// display data
[Code]....
I am writing a web page that accesses Mysql database data through PHP then dynamically displayes the Mysql data when the user mouses over different parts of an imagemap. I use Javascript OnLoad function to load the Mysql data into the header and then I use the Onmouseover function to change the display dynamically.
Here is my question; when I mouse-over a part of an image the data in my side bar changes (exactly what I want) but I can't seem to make the data linkable. For example, when a user mouse-overs a certain part of the image, on the side bar it displays the companies web adr. How do I make that data a link? On the initial load the default data displayed is linkable but because I use <div> </div> to change the data dynamically, I loose the likability.
I have a form.On the form I have a drop down box that allows the user to select a data set to work with (A or B). The table loads just fine and all is right with the world. No problems there.What I need is for the user to be able to edit the data set and have those changes written directly back to the mySQL database. They also need the option of deleting a record entirely.I know how to do all the database queries, updates, etc. I just don't know how to write the ajax forms to accomplish this.
View 4 Replies View RelatedI want to ask you is it possible to use jquery dialog with php. Using this tutorial [URL] I want to call a php script with will delete a row into Mysql database.
View 2 Replies View RelatedI am working on a project for which I need an autocomplete form which uses the value from a mysql database. I've seen many examples about using local data.
View 1 Replies View RelatedBasically i have a form with jqueryui implemented (autocompletes) and I need the form to display the number of current results as the user fills the form, i.e. once the user has finishedinputtingdata into one field, the form will query the database with the current form details and return just the number of results ($mysql_num_rows)
View 2 Replies View Relatedi want to add a part of the website that will be generated from mysql database from an external file just like php include just that i want these parts to update realtime without refreshing the browser. i also want it to have pagination.
View 6 Replies View Relatedhow to connect with MYSQL database using javascript..
View 3 Replies View RelatedI would like to use jQuery to prepopulate a form - ie make a call to a php program to get data from a database and pre-populatea form with appropriate data for the user. Can anyone point me in the right direction for some examples on the simplest way to do this?
View 3 Replies View RelatedBelow i have attached my code. This code is working.....but i want some modification in that code such that when i select 'vegetable' or 'fruits', it should give list of that selected one in second list, BUT THAT list should be stored in mysql database.
In the below program , i have hard-coded that second list, but i want second list to be dynamic from database.
Code:
I am trying to execute a query in mysql using javascript to check the username isnt taken, but dont know how.
View 3 Replies View RelatedAm looking to find the easiest way to populate an order form that customers can email through to us.
I have created a database with 2 fields, id and name.
I would like to be able to have a form on my page with 3 fields, id name and qty.
I want to link the id and name fields on my form to my database so that when a customer starts to type a product id or description it will show a list of available matches. underneath which once clicked will populate the mssing field.
So for example is i have 2 products id 998 green apples and 999 red apples.
Typing in 999 in the id field of the form would populate the name field with red apples and typing red apples in the name field would populate the id field with 99.
if someone didn't know which apples they wanted they could type apples in the name field and underneath it would show both red and green which when clicked will populate both fields.
i have a image that need user click on it and get the coordinates and store the coordinates to mysql database by using php. Here my code:
Code:
<script type="text/javascript">
function(ev){
var pos=zxcPos(this.img);
var mse=[ev.clientX-pos[0],ev.clientY-pos[1]];
var ary=this.ary;
if (ary.length>4)
[Code]...
Does anyone know how to set a javascript variable as a query result from a MySQL database.
As an example, like this:
Set this query:
I just can't do it. I've tried doing it like this:
But the thing stops my <body onLoad=""> function from working. I'm no expert in Javascript.
My google map route creator. And of coure, I made my google maps route creator source.
Now i need :
1) Make markers draggable and animate;
2) Store, retrieve and delete route and marker positions to database;
3) Automatic route calculations (total route lenght and lenght between markers).
How to create file for databas synchronisation and retrieve data from database?
I have this PHP page that has the following functions...Insert Form into Table in MySQL DatabaseDelete Entry from Table in MySQL DatabaseA Link to a separate page where I Edit entries I have coded a PHP function for Delete. Looks like this:
// delete if provided if (isset($_GET['id'])) { // query to delete $query = "delete from student where STUDENT_ID =".$_GET['id']; //execute query if ($db->query($query)) {
Somewhere else I query the results and print them into a table. I added a column to this table with a Delete link for each row. Clicking on delete will execute the PHP function to delete.
The link looks like this: PHP Code:
echo "<td><a href=".$_SERVER['PHP_SELF']."?id=".$row[0]."></a></td>";
Likewise the first names also have links when clicked bring the user to another page with a form to edit form data.
The link looks like this: PHP Code:
echo "<td><a href='editstudent.php?id=".$row[0]."'>".$row[1]."</a></td>";
From here however I need to change those links to Buttons. One for Delete and another for Edit and use JavaScript functions to make them work as they originally did. So this is what I've done...
<td><form name='myform1'><input type='button' name='edit' value='Edit'
<td><form name='myform2'><input type='button' name='delete' value='Delete'
Next I need to write functions...this is where I am lost. Usually I'd know what to do when referencing elements in forms, i'd do something like document.formname.inputname, but my problem is those links or should I call them actions are replaced by those new buttons.
Should I put them into a form, or make them hidden, and then name the element? Or should my function look something like this...all I really want to do is to call the function, and have the function just do the action of loading the link (don't know if that sounds clear). I've tried to do this but it does not work.
<script>
function Delete()
{
document.myform2.action="href='$_SERVER['PHP_SELF']."?id=".$row[0]'";
document.myform2.submit();
}
</script>
Can anyone tell me what i am doing wrong, and could you please point me in the right direction?
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
View 15 Replies View RelatedI've got this form that needs to check if the user input is already in the database, if this isn't the case it should disable the submit button and display an error depending on which input isn't found.
eg. client name isn't found...
This is the form:
How do I get this to work?
I've been advised that the only way to accomplish this is via some hand-coded javascript, at which I'm a complete noob, so hopefully someone here might be able to steer me in the right direction.I have a listings page which displays results using images and text which are stored in a MySQL database, all is working fine. The images are pulled into the page from the database and each listing can have up to a maximum of 10 images. Some will have all 10, some probably one or two, so the page is coded such that if there's an image in the field, it displays a thumbnail, if there isn't then it shoves a "Â " in instead.The results page has one main photo (image 1) and then a series of thumbnails (images 2-10) below it and I need to be able to set this up so that when someone clicks on image 2 it shows the full-size version of that image in the div where image1 sits, and the same for however many remaining images there are.
So my question is, how easy it is to do this with javascript and does anyone have any idea how to code it?The main photo sits in a div whose id is "mainphoto" the remainder all sit in a div whose id is "thumbpix".