I want to build-up ajax based friends system. though i no nothing about ajax (would like to learn but) actually i have form where user can add his friend. on very next page of this page he/she can see what he/she is entered and where
they should probably see the add and remove button(which i want to build up using ajax)
how to start for this? till now i have code where user can write his friend name and to the next page he/she can see the value he has written. on submit button it all goes in to database. means i have devloped php form for this.
I have an ajax function which passes form field values to a PHP script which in turn saves the data to my database. all works great.
I now need to add a file input to my form and pass the file upload ot the same PHP script.
I have read an article [url] which explains how to do this but this would suggest it is a completely separate function.
My question is, is there anyway I can expand my existing function (below) to inlude the file upload process to save having 2 functions doing the same process?
I would like to use jQuery to prepopulate a form - ie make a call to a php program to get data from a database and pre-populatea form with appropriate data for the user. Can anyone point me in the right direction for some examples on the simplest way to do this?
Im having the weirdest problems with my ajax. Now first off i have horrible coding convention!! I have one Ajax.js file which handles all my ajax requests and one ajax.php file which handles retrieving data from a database. The problem I am having is when ever I call a certain method which contains a if statement and runs the respective ajax function, it sometimes evaluates the if statement wrong. The weirdest thing of all is when I use FireFox's firebug and step through the javascript code to see why its evaluating the if statement wrong, it evaluates it correctly.
So basically if I don't step through the javascript code it evaluates the if statement wrong which means one of my variables are not being set in time for it to be used in the if statement. BUT if i step through the code with firebug it evaluates the if statement correctly! Now I have tried this is all the browsers and sometimes it evaluates the if statement correctly and when i keep refreshing the page it will sometimes evaluate the if statement correctly! Now I know this makes no sense, but I'm just as confused! The only reason I can think why this is happening is that one of my variables are not being set in time for the if statement to use it!!
there is a selection of menus on the screen that you can change select different options to show you a price.
issue is as follows; i want to be able to create url's for every product in the database for google adword purposes; for example if they click on the google ad they come direct to the page/selection from the table/drop downs that is what they want. currently we have got as far as creating the below link;
[URL]
this link will take you to the product, but the drop downs from the menus haven't changed, just the price and the quantity.
i need to know of a way of selecting from the database and it be able to change the drop downs from a specific url.
our problem is we need to populate a select option in order of the one we send.
could someone please point me in the right direction for creating an AJAX page that displays "live" data from a mysql database? I need the page to update its self every time data changes in a mysql table.
I managed to send data from the form using php & jquery/ajax. But now I need to be able to load that data back onto the form. Is it somehow possible to use the code I have for sending the data to retrieve the data?
I have a form.On the form I have a drop down box that allows the user to select a data set to work with (A or B). The table loads just fine and all is right with the world. No problems there.What I need is for the user to be able to edit the data set and have those changes written directly back to the mySQL database. They also need the option of deleting a record entirely.I know how to do all the database queries, updates, etc. I just don't know how to write the ajax forms to accomplish this.
I want to verify that the data in my form in HTML is already exist in my database if this is true then the form must not be sent. I know this is done in javascript but I can not found the right solution. I would like an illustrative example.
This form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
I am trying to generate an ajax form based on a database value of max and min years. At present i have the following.
[Code]...
What I am struggling with is the logic to say if minyears is more than 1 (string in option needs to say years), then add in every year between min and max as additional options. My brain has been melting with this for a few days now
I have a situation where I need to populate form fields by grabbing information from a database when the user enters information in a specific field. I got this to work with a single field just to make sure I had the basics in place:
* User fills out "Field A" onchange event triggers Javascript function that uses Ajax to search and retrieve info from database (PHP/MySQL) Javascript function autofills "Field B" with Ajax response
Works perfectly. My trouble is that I need to do this with a whole series of fields at once, not just one. I tried using the PHP to output a Javascript array and then use the values from the array to populate the fields, but that didn't work. I got a message saying that my array was undefined. I'm not even sure this was the proper way to approach this, but it's all I could think of.
i am trying to build my form to submit without reloading the screen. I am using jquery and it inserts the data but it also reloads the screen and two database records get inserted. It appears that one is being inserted by jquery and the other is being inserted by the normal form submission. How do I remove/override the normal form submission? My html code is as follows:
I'm trying to populate a form with information from a database based on a textbox entry. However, when I begin to key in the textbox I receive "undefined" in each textbox throughout the form.
Take a look at my code for any errors? It also appears that my $_GET['jobid'] is not working properly.
I've been reading up on click() and I can't figure out how to get it to run another php script that will remove an ID from a database.. How would I go about doing that? I need to send the current li ID to this php script.
Is it possible to send an AJAX XMLHttpRequest using prototype.js API for a multipart/form-data ?
I already done parsing form parameters and sending GET/POST request, but does this work with <input type="file"> ? Who handle file submit and encoding ?
I have a problem with sending data from a form to a php script with AJAX. To test if it works, I try to send data from the form, print it in the php with "echo", and then put it back in the initial html file.
My Javascript code is:
The function stateChanged, basically says:
The problem is that the response is empty, but I don't know why. I have checked the input data and the postData variable says "firstName="+input (e.g. "firstName=Robert"), so that's not the error.
The server i'm trying to post data to in an ajax call expects data in xml format, including a particular attribute value. I have to use Chrome browser which does not support the XML Class (e4x).
I tried to marshal my data as follows:
But the ajax call does not appear to transfer the xml data to the server even though the xmlhttprequest call appears ok in Chrome's developer tool console.
I'm wondering whether I'm forming the xml formatted data correctly.
Well i do have a mysql query in one php page(php_1) & I want to submit the variables to the query in different php page(php_2) via form action but how am I supposed to do it without redirecting to php_1..All I need is to post the data to the first php page query so that It performs some action over there & thats all... So hoping sumone who knows ajax might helpme out with a sample code or point me in the right direction.
php_1 page :- $query = ("SELECT * FROM state4 WHERE (LONG_HI<'".$_POST['Ymax']."')"); php_2 page:-
I am writing a form that grows using ajax server responses to info as the form is filled in and everything is fine in standards compliant browsers but IE is having a problem. I have two js functions on the page that collect form data, send it to the server, and then write the server response as innerHTML to specified divs on the page. This works great in FF but in IE it runs the first function but fails on the second function and the two functions are identical except for the server routine.
The div that is populated with the server response so it doesn't seem to be a problem with the coding because if one works, and they are identical, the other should work too so perhaps IE is choking with the way it is handling two ajax objects on the same page? You will need to add something to the shopping cart first at [uRL] and proceed to checkout, then on the checkout page look in the url and change ste_chkout_proc to ste_checkout_proc and load the new url to see the dev checkout vs. the live checkout.
I am having no luck with my post form to mysql. It is only posting the first letter of the word/phrase for the text input fields to the mysql database. It is a photo and text post form. The photo and only first letter of text are posting to database. I am using Jqtouch, jquery, and phonegap.
