DIV Tag & Dilemma - Cannot Insert The Form Data Into The Database
Apr 28, 2011I have a problem with the DIV tag (which I think is related with the Javascript). I cannot insert the form data into the database.
[Code]...
I have a problem with the DIV tag (which I think is related with the Javascript). I cannot insert the form data into the database.
[Code]...
I have a problem with the DIV tag (which I think is related with the Javascript).I cannot insert the form data into the database.
Code:
<script type="text/javascript">
var member_prices = new Array();
member_prices["no"]=200.00;[code]........
I'm triyng to use the $.ajax jquery function to insert some dates in a database, using php.I have the page that insert the data called : sign.php and in the page I have the form, and the ajax scritp.
$("#submit_sign").click(function(data){
$.ajax({
type: "POST",
url: ("sign.php"),
[code]....
if I use the page without ajax it works, if I use the script jquery it works but doesn't insert the dates in the field, it send only white field. can't pass the variable POST beetween the ajax script and the php script.
The below coding is the javascript coding in which i have used AJAX coding also.its only pagenavigation coding.
function change(which)
{
if(which=="page1")
{
document.getElementById(which).style.borderBottomColor="white";
document.getElementById("page2").style.borderBottomColor="#778";
document.getElementById("page3").style.borderBottomColor="#778";
document.getElementById("page4").style.borderBottomColor="#778";
[Code]...
i am trying to build my form to submit without reloading the screen. I am using jquery and it inserts the data but it also reloads the screen and two database records get inserted. It appears that one is being inserted by jquery and the other is being inserted by the normal form submission. How do I remove/override the normal form submission? My html code is as follows:
[Code]...
I would like to use jQuery to prepopulate a form - ie make a call to a php program to get data from a database and pre-populatea form with appropriate data for the user. Can anyone point me in the right direction for some examples on the simplest way to do this?
View 3 Replies View RelatedI'm doing an ajax call to a remote php file... it returns a value fine,
and even enters a value into a text field on my form. The problem is,
right after the function call to the ajax function, I do an alert of
what the field value is, and it doesn't recognize the field value has
been changed. Two caveats:
1 - It will recognize the last call's change
(if I run it a 2nd time, it'll see the 1st call changes)
onBlur="ajaxCall(document.form1);alert(document.form1.ajax Field.value);">
2 - It'll recognize the current call's change if I set a 2 second
timeout
onBlur="ajaxCall(document.form1);setTimeout('checkFields(d ocument.form1)',2000);">
It seems, although I can see the text field getting updated,
programmatically speaking, it isn't reflecting it until everything is
done... including any alerts and such.
It's weird seeing the empty alert popup, when I can see the value in
the text field underneath it.
I managed to send data from the form using php & jquery/ajax. But now I need to be able to load that data back onto the form. Is it somehow possible to use the code I have for sending the data to retrieve the data?
Here's the jquery:
Here's the php:
how can I load data onto a form using jquery/java?
View 2 Replies View RelatedI want to build-up ajax based friends system. though i no nothing about ajax (would like to learn but) actually i have form where user can add his friend. on very next page of this page he/she can see what he/she is entered and where
they should probably see the add and remove button(which i want to build up using ajax)
how to start for this? till now i have code where user can write his friend name and to the next page he/she can see the value he has written. on submit button it all goes in to database. means i have devloped php form for this.
I want to verify that the data in my form in HTML is already exist in my database if this is true then the form must not be sent. I know this is done in javascript but I can not found the right solution. I would like an illustrative example.
View 6 Replies View RelatedI have a form which goes to my insert page which inserts the data into the table. Except I didn't want to do a redirect to another page so I thought I would do an Ajax call. Both pages work until I change it to an ajax call.
I am pretty certain that it is because I took out the <form action="insert.php"> because otherwise the page would redirect but if that is the case I don't know my way around it and if it isn't the problem I'm not sure what is.
But here is my code:
Form:
I have an ajax function which passes form field values to a PHP script which in turn saves the data to my database. all works great.
I now need to add a file input to my form and pass the file upload ot the same PHP script.
I have read an article [url] which explains how to do this but this would suggest it is a completely separate function.
My question is, is there anyway I can expand my existing function (below) to inlude the file upload process to save having 2 functions doing the same process?
My Code:
Code:
I have been trying to figure out how to go about making a table of comments auto-refresh when someone inserts from a comment form without refreshing the whole page.I've tried looking into AJAX for this, but everything I have looked at, in terms of tutorials, just flies right over my head, and I can't really make much sense of it.
View 2 Replies View Relatedhow to dynamically insert items in list box in javascript.That is . When ever new element in stored in oracle that should be listed in listbox
View 1 Replies View Relatedi'm busy making a site for a audiovisual company and i'm stuck at the CMS system by adding pictures to a project page. Adding one single photo isn't the problem but I want a button to add a new file input field and insert that second (or thirth, fourth etc etc) into a new row in the database.... The script that i'm using right now, clones the input field but doesn't "activates" it.... You can't select a file....
[Code]...
i am trying to create a form that where the page will not refresh if the form is submitted specially if the user inputs any errors in the form my problem is i do not know how to send multiple variables using jquery to a php file i saw somewhere that in order to do this you need to concatenate the variables you will be sending this is the code i am using
<html>
<head>
<style type="text/css">
#add(display: none;}
[code]....
the jquery successfully sends the variable to the php file the problem is once i insert it into a database all the variables i sent are concatenated for example in the column stud_no once you send the form this is what will be inserted "123123name=asdasd"
I have this table:CREATE TABLE IF NOT EXISTS Assignments (uid TEXT PRIMARY KEY ON CONFLICT REPLACE, instruction TEXT, start TEXT, stop TEXT, createdTimestamp TEXT, theTimestamp TEXT, taskID TEXT, resID TEXT, flowID TEXT, flowDefID TEXT, currentState TEXT, iconRef TEXT, colorRef TEXT, dispatched BOOLEAN, inStartState INTEGER, inStopState INTEGER, writeLock INTEGER, workItemID TEXT, companyID TEXT, metadata INTEGER)
The thing is that when making a insert and then going to the development toolbar in chrome and look at the storage tab and look at my table. Depending on what is in the table chrome crashes.I drop the table between the executions.The difference here is that "theTimestamp" is something rather then empty. If I set theTimestamp to '10/15/10 3:07 P' it works. But just adding that last M or any other letter will make chrome crash when you try to look at the table. Whether it is by navigating to the table with mouse clicks or writing a select * from Assignments statement.
I'm working on a site now in which I will be toggling a div from visible to hidden every time you click the link. I have successfully done this, and it looks like this Code:
However, as you can see there is a "+" to the left of the title of the button, and i have another GIF that has a minus for when it is closed and the div is hidden. My question is what should I add to my existing code (if possible) to make the image switch to the minus version if the div is hidden. Code:
I am having no luck with my post form to mysql. It is only posting the first letter of the word/phrase for the text input fields to the mysql database. It is a photo and text post form. The photo and only first letter of text are posting to database. I am using Jqtouch, jquery, and phonegap.
Here is my form fields:
Here is my java script:
I've the following AJAX code:
[Code]...
This code works to insert a MySQL record to a Database using AJAX. It works fine on IE, but it's not working on FF or Chrome. When I test it on FF/Chrome, i just get the text "Just a second..." and it doesn't advance from there.
How do I insert the following data into a php file using AJAX
function AddCity()
{
itemID = document.form.ItemID.value;
countryID = document.form.refCountryID.value;
regionID = document.form.refRegionID.value;
[Code]....
i want to know is there any code which will print a data into the bottom of a exist table? let say now i have a table like below
[Code]...
without overwrite all the old data...
I am using an xml file to pull in data to jqm. I am appending the first and last name to a listview. (I am working with Datazombies example for the a-z index contact list from the iscroll git hub). How would I specify where to append ie, if the lastname is Adams (or anything that begins withletter A) Adams is appended under the listdivider with ID of A.
<script type="text/javascript">
$.ajax({
type: "GET",
[code]....
I need to get some data from the database, then perform actions based on them.
Is it possible in jQuery or is there any way around?
I am looking for a solutions for the following problem,
I need to access at database from within a website, from where I can
retrive a specific document in the database and mailing it to someone
else. Of course I cut crab the document from the database and save it on
my harddrive, and then send it. But this process don't fit into our
busy days.