i am trying to build my form to submit without reloading the screen. I am using jquery and it inserts the data but it also reloads the screen and two database records get inserted. It appears that one is being inserted by jquery and the other is being inserted by the normal form submission. How do I remove/override the normal form submission? My html code is as follows:
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I revise the hrefs of the a-Attributes of my page. Now I include new content in this page and want to revise those hrefs again, but it won't work...
open: function( page ){
this.showPageLoader();
$.ajax({
type: "GET",
[Code]....
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
i am trying to create a form that where the page will not refresh if the form is submitted specially if the user inputs any errors in the form my problem is i do not know how to send multiple variables using jquery to a php file i saw somewhere that in order to do this you need to concatenate the variables you will be sending this is the code i am using
<html>
<head>
<style type="text/css">
#add(display: none;}
[code]....
the jquery successfully sends the variable to the php file the problem is once i insert it into a database all the variables i sent are concatenated for example in the column stud_no once you send the form this is what will be inserted "123123name=asdasd"
The below coding is the javascript coding in which i have used AJAX coding also.its only pagenavigation coding.
function change(which)
{
if(which=="page1")
{
document.getElementById(which).style.borderBottomColor="white";
document.getElementById("page2").style.borderBottomColor="#778";
document.getElementById("page3").style.borderBottomColor="#778";
document.getElementById("page4").style.borderBottomColor="#778";
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I am java developer using jquery tabs in my project.I have terrible problem with jquery tabs. when i am in second tab and submit the form,tabs are reloading and first tab selected by default, but i have to be in the second tab.
View 1 Replies View RelatedI have a problem with the DIV tag (which I think is related with the Javascript).I cannot insert the form data into the database.
Code:
<script type="text/javascript">
var member_prices = new Array();
member_prices["no"]=200.00;[code]........
I wish to submit a form without reloading the page, so I'm guessing I need some ajax to handle this. Here is an example of a simplified form:
HTML Code:
<form action="email.php" method="post" id="contact">
<textarea name=msg id="msg">
we have product pages; example page: [URL]
there is a selection of menus on the screen that you can change select different options to show you a price.
issue is as follows; i want to be able to create url's for every product in the database for google adword purposes; for example if they click on the google ad they come direct to the page/selection from the table/drop downs that is what they want. currently we have got as far as creating the below link;
[URL]
this link will take you to the product, but the drop downs from the menus haven't changed, just the price and the quantity.
i need to know of a way of selecting from the database and it be able to change the drop downs from a specific url.
our problem is we need to populate a select option in order of the one we send.
I have a problem with the DIV tag (which I think is related with the Javascript). I cannot insert the form data into the database.
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I've the following AJAX code:
[Code]...
This code works to insert a MySQL record to a Database using AJAX. It works fine on IE, but it's not working on FF or Chrome. When I test it on FF/Chrome, i just get the text "Just a second..." and it doesn't advance from there.
I'm triyng to use the $.ajax jquery function to insert some dates in a database, using php.I have the page that insert the data called : sign.php and in the page I have the form, and the ajax scritp.
$("#submit_sign").click(function(data){
$.ajax({
type: "POST",
url: ("sign.php"),
[code]....
if I use the page without ajax it works, if I use the script jquery it works but doesn't insert the dates in the field, it send only white field. can't pass the variable POST beetween the ajax script and the php script.
I have a form that I perform some AJAX business on when it is submitted. However, I wanted to have an if...else statement but when I add it it allows the page to refresh upon submit. For example.
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I have a problem, I am by no means new to PHP/Javascript but am finding an error that I cannot ridicule how to stop.Ok Ill try and explain it in simple terms:I have two divs, div1 and div2,In div1 there are links whitch are fetched from the databaseIn div2, content from links href ? in div1 is collected through AJAX.No I have a php preg_replace function that replaces it to look like <a href='#' onclick=\"showTopic(0,$char,'$1');\">$1</a> Now when you click this, it inserts into the "tpm" table in the database,(this table holds the links for div1) But it will not update the links unless i refresh the page? I would like to knoe how to update the links in div1 without refreshing, because refreshing = going back to the start of the code i am working on.
View 3 Replies View RelatedI have a web application in which I want users to be able to submit a form. Something like this:
Code PHP:
<form method="post" action="index.php">
<input type="text" name="text" value="" />[code]....
Then when it is submitted, the data will be processed and the script which is processing the data will echo some data on-screen based on the data from the form.I need this to happen in an AJAX manner, ie: the page won't need to reload.how to go about doing this? I'll be using jQuery on the same page in case
I want to build-up ajax based friends system. though i no nothing about ajax (would like to learn but) actually i have form where user can add his friend. on very next page of this page he/she can see what he/she is entered and where
they should probably see the add and remove button(which i want to build up using ajax)
how to start for this? till now i have code where user can write his friend name and to the next page he/she can see the value he has written. on submit button it all goes in to database. means i have devloped php form for this.
I am currently using jquery .post ajax code to submit a form.
The problem is that when I click on submit it takes me to the php file page. Which is blank.
I don't want this... this functions just like if I made the form in html meaning when submit it takes you to the .php file well opens it in a page.
I want to use ajax that when you click submit it submits the form and then shows a message on screen.
When I click the submit button my message gets shown on the screen saying it submittedsuccessful then with at least 2 seconds it sends the user to the php file meaning opens the page up in the browser not a new tab or new window but sends the user to the php file. Which I don't want it to happen. So the page is blank.
I used the .post and serialized the form. Is this the right thing to do?
I don't want to send the user to the php file. Just use ajax and check if it updated the database and if so send either 1 or 0 depending if it went threw then the form page willreceivethat data and then fade in a message saying either error or success depending what went on.
I would like to know how you can use jquery ajax to submit a form without refreshing the page. I do know about the serialization function but would like to see an example of what is submit().
I currently tried to get my form working but but can't get it to work meaning to submit something from the form.
I have a general idea of how this works but i need further explanation. I have a form that needs to post into one list and then post into another list as well.Here is the ajax code and html code:
View 2 Replies View RelatedThis form retrieves results from a mysql database. It works fine but when I click submit it shows the result only for a second. When I hold down submit the result stays there. How do I get the result to stay on the screen after I hit submit? Even better how do I get it to spit out results without having to hit a submit button or press enter?
View 15 Replies View RelatedI have a form which goes to my insert page which inserts the data into the table. Except I didn't want to do a redirect to another page so I thought I would do an Ajax call. Both pages work until I change it to an ajax call.
I am pretty certain that it is because I took out the <form action="insert.php"> because otherwise the page would redirect but if that is the case I don't know my way around it and if it isn't the problem I'm not sure what is.
But here is my code:
Form:
dt_save is a <form>, the submit trigger works as usual but when doing an Ajax request the code interrupts without any error. I put in 2 alert's just to check, only the first alert box appears when submitting the form. Also I can't find my request in Firebug's Network window (Firefox addon).
$('#dt_save').submit(function(){ alert('json request'); $.ajax({ type: "POST", url: "json.php?action=extendable_select_insert", dataType: "json", data: "into=empfaengerliste&col=empfaenger&value=" + encodeURIComponent(document.getElementByID("data[empfaenger]_t").value), success: function(data) {} }); alert('done'); });
PS: Of course the requested PHP-File exists!
I'm not sure if this is a php issue or jquery issue. When I complete the form and hit submit it puts the successful message up like its supposed to but also with the fields still filled in the form which it shouldn't be doing and it doesn't actually post in the database so I'm not sure if its a php issue or jquery issue.
<?php
How can I submit the contents of my form? This code submits NO data. I want to submit the data in my form. I want the values of my form to be submitted.
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I have a form and i am using jquery validation plugin to validate form.now i want to after validation submit form using ajax.
here is the example.
Code:
<form id="frmRegister" action="" method="Post" >
<input type="text" id="username" name="username" value="" />
<input type="submit" id="btnRegister" name="btnRegister" value="Register" />
</form>
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I am trying to generate an ajax form based on a database value of max and min years. At present i have the following.
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What I am struggling with is the logic to say if minyears is more than 1 (string in option needs to say years), then add in every year between min and max as additional options. My brain has been melting with this for a few days now