I have a form and i am using jquery validation plugin to validate form.now i want to after validation submit form using ajax.
here is the example.
Code:
<form id="frmRegister" action="" method="Post" >
<input type="text" id="username" name="username" value="" />
<input type="submit" id="btnRegister" name="btnRegister" value="Register" />
</form>
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I have a problem where if a form submission (set up to submit via AJAX) fails validation, the next time the form is submitted, it doubles the number of post requests - which is definitely not what I want to happen. I'm using the jQuery ValidationEngine plugin to submit forms and bind validation messages to my fields. This is my code below. I think my problem is that I need to unbind from the validationEngine plugin when the form fails, but I can't figure out how to do this.
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I've literally tried everything. Read 26 tutorials, interchanged code, etc. My validation functions all work. My AJAX functions work (tested manually using servlet URL's). The second servlet validates the reCaptcha form that's generated on my webpage. After the form is validated, even if everything's correct, nothing happens upon clicking submit. I even have an alert pop up if with the captcha result, just for middle-layer debugging purposes.
I want to do all of my validation clientside; none serverside. However, going to be tough if I can't get my god damn form to submit. I've been puzzled by this for close to 36 hours straight. I can't see, and I'm going to get some rest and hope that there is some useful insight on my problem when I return.
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I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedI'm using the Validation plugin for JQuery and was wondering if there was a function to submit the form without causing it to validate the form. I have a table with a list of radio-buttons and above that is a drop down list of states. The drop down list of states is used to filter the table rows and when the selected item changes it posts-back to the server (via $("#frm").submit()). I don't want this to cause any validation to occur. Is there another function I can call besides submit(), or some other method?
View 1 Replies View RelatedI use ajax submit for my jquery validation form. I NEED a captcha for the form, being I am getting attacked by bots. I cannot figure out how to do it. I will past my code below.
$('#contact_form2').validate({
submitHandler: function(form) {
var str = $("form").serialize();
$.ajax({
type: "POST",
url: "contactpage.php",
data: str,
success: function(){
$('#contact_form2').html("<div id='message'></div>");
$('#message').html("<h2>Contact Form Submitted!</h2>")
.append("<p>We will be in touch soon.</p>")
.hide()
.fadeIn(1500, function() {
$('#message').append("<img id='checkmark' src='images/check.png' />");
});}});
return false;
}
I am trying to use jquery's ajax framework to check if the data that is entered is valid or not. The form works properly except i cannot get the page to go to action="something.php" file in the form part.
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I enter a company into the form and hit submit The form will send the data to my validate company.php file. Validate company will return either "good" or "bad" If "bad" the form works as expected. it will stop the function by returning false and alert you that it is already in the database If "good" the page just sits there, basically returned false. however if you click submit again on the html form the function will go through and do what return: true should do.
I've a form. Before submit this forum i have to check if there are uploaded pictures for this form. I check the pictures with ajax. If there are no pictures the must come a alert (see below) otherwise the form must bu submitted with a post (regular submit, no ajax or something). It's working fine but only the formsubmit don't work. Someone who know this 'problem'?
<script type="text/javascript">
$(document).ready(function(){
$("#submit").click(function(){
[code]....
I'd like to know how to hide a form after a success validate with validation plugin. I'm try this:
submitHandler: function(form) {
$("#form").hide();
form.submit();
}
When I submit the form, it is hidden a few seconds, but then it come back.
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
I have a form on my page, which I want to validate on submit. The code looks something like this:
$('#form').submit(function(){ if ($('#field1').length == 4 && $('#field2').length == 3) {
$.ajax({
url: someAjaxUrl,
dataType: 'html',
type: 'get',
success: function(html){ if (html != '') {
//show error
} else {
//submit form
}}});
} else {
//show other error
} return false;
});
Now, if I try to use
$('#form').submit();
In the else statement within the success function, the validation keeps getting triggered in an endless loop.
But if I use
document.form.submit();
- or document.getElementById('kbaFormSearch').submit(); -
The form gets submitted correctly. Is this because the anonymous callback function within the earlier defined
$('#form).submit()
gets triggered again? And if so, is there a way to get this to work without using "native JS" (not that I'm against it, but it would not make much sense to me unless there is no other way).
I seem to be having trouble getting the submithandler form attribute working. The link is here: [URL]. For some reason it submits and does not show the alert I have inside the function of the submithandler attribute.
View 1 Replies View RelatedI want to submit my problem. I use the plug-in "Validation" to check and send my "form", and thus far everything is working correctly, just do not know how to retrieve information from the page to which I have submitted my form, such as errors or other info.
View 2 Replies View RelatedI am beginner inthe programming , & I am trying to apply validation for different fields of a form, so that a user can get alert messages instantly at the time of mistake as if any form fields are empty or any Invalid values are entered. My validation is not working systematically & properly,the alert messages hangs the data entering process & some fields does not throw any alert messages & the process jumps over the remaining empty fields.Here is my code:-
Code:
<html>
<head>
[code]....
What I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I'll start out by confessing that I only dabble in javascript. But I need it in this case to validate information before allowing the item to be added to the PayPal cart.Here is the Javascript:
Code JavaScript:
function validateFields() {
var message = " ";
[code]....
Can't get form to submit but validation works... Even once the validation is accepted the form still will not submit.
Code HTML4Strict:
I'm trying to make a username form validation combined with ajax but I'm stuck at 1 point. I need to use a var that is outside of my $.get() function so that I can add the function to the validate plugin.
This is what I have:
As you can see, I'm trying to change the value of "var result" to true, but since that is outside of my $.get() it doesn't seem to happen. I tried to put the return command inside the $.get function, but then my validator always keep saying it's a false check.
Is there anyway I can call that var inside my $.get function?
I have an issue with my form validation working with a hidden submit button. My code below shows both the form validation and the form fields. My submit button should be hidden until the fields: FirstName, LastName, and Campus have been entered.
function formValidation(oEvent) {
oEvent = oEvent || window.event;
var txtField = oEvent.target || oEvent.srcElement;
[code]....
I am currently using jquery .post ajax code to submit a form.
The problem is that when I click on submit it takes me to the php file page. Which is blank.
I don't want this... this functions just like if I made the form in html meaning when submit it takes you to the .php file well opens it in a page.
I want to use ajax that when you click submit it submits the form and then shows a message on screen.
When I click the submit button my message gets shown on the screen saying it submittedsuccessful then with at least 2 seconds it sends the user to the php file meaning opens the page up in the browser not a new tab or new window but sends the user to the php file. Which I don't want it to happen. So the page is blank.
I used the .post and serialized the form. Is this the right thing to do?
I don't want to send the user to the php file. Just use ajax and check if it updated the database and if so send either 1 or 0 depending if it went threw then the form page willreceivethat data and then fade in a message saying either error or success depending what went on.
I would like to know how you can use jquery ajax to submit a form without refreshing the page. I do know about the serialization function but would like to see an example of what is submit().
I currently tried to get my form working but but can't get it to work meaning to submit something from the form.
I have a general idea of how this works but i need further explanation. I have a form that needs to post into one list and then post into another list as well.Here is the ajax code and html code:
View 2 Replies View RelatedI have a scenario where I have the following jquery
Code:
$("#frompdc<?php echo $JavaCnt;?>").change(function(){
var id = $('#id<?php echo $JavaCnt;?>').attr('value');
var frompdc = $('#frompdc<?php echo $JavaCnt;?>').attr('value');
var topdc = $('#topdc<?php echo $JavaCnt;?>').attr('value');
$.ajax({
type: "POST",
url: "AJ_Update.php",
data: "firm=y&id="+ id + "&frompdc=" + frompdc&topdc=" + topdc
});
And some php to insert this data
Code:
mysql_query("UPDATE TBLTRANSFERS SET FROMPDC = ".$_POST['frompdc'].", MOD_TS = '". $timenow ."' WHERE ID = ".$_POST['id']);
I'm trying to throw some validation in here which I can do in php (a language that I'm much more proficient in) but can't figure out how to get the two together. I want to be able to do a select against another table I have for both the frompdc and the topdc.
Code:
$tofpdcresult = mysql_query("SELECT * FROM tbltransferspdcexclusions where FROMPDC = '".$frompdc."' AND TOPDC = '".$topdc."'");
$tofpdcnum_rows = mysql_num_rows($tofpdcresult);
And if it exists I want to give a popup message to the user as well as blank out the field.
I'm struggling with two things:
How do I get ajax to run two queries and return the results to a popup window?
How do I blank out the field in the form?
My HTML with Javascript I had a problem with the form submittion.. where the javascript working fine for validation after completing validation my form submit is not processing to action specified in the form tag.
Here is the HTML Code
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I am trying to make form in dreamweaver with several text boxes. If the person doesn't fill out one or more of the boxes, I want an error message to come up which lists which boxes weren't filled out. If they ARE filled correctly, I want the page to redirect to a thanks page.This isn't online, and I'm new to coding. But its going ok, I just can't get the form to validate AND redirect if return true (or something???). I don't know how to do that. I've tried googling it, searching youtube tutes, and reading a few javascript books, but no joy.[code]
View 6 Replies View Relateddt_save is a <form>, the submit trigger works as usual but when doing an Ajax request the code interrupts without any error. I put in 2 alert's just to check, only the first alert box appears when submitting the form. Also I can't find my request in Firebug's Network window (Firefox addon).
$('#dt_save').submit(function(){ alert('json request'); $.ajax({ type: "POST", url: "json.php?action=extendable_select_insert", dataType: "json", data: "into=empfaengerliste&col=empfaenger&value=" + encodeURIComponent(document.getElementByID("data[empfaenger]_t").value), success: function(data) {} }); alert('done'); });
PS: Of course the requested PHP-File exists!