I have an issue with my form validation working with a hidden submit button. My code below shows both the form validation and the form fields. My submit button should be hidden until the fields: FirstName, LastName, and Campus have been entered.
function formValidation(oEvent) {
oEvent = oEvent || window.event;
var txtField = oEvent.target || oEvent.srcElement;
[code]....
I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedI'm using the Validation plugin for JQuery and was wondering if there was a function to submit the form without causing it to validate the form. I have a table with a list of radio-buttons and above that is a drop down list of states. The drop down list of states is used to filter the table rows and when the selected item changes it posts-back to the server (via $("#frm").submit()). I don't want this to cause any validation to occur. Is there another function I can call besides submit(), or some other method?
View 1 Replies View RelatedI have an order form where a customer can select a number of artwork prints supplied by different artists and suppliers. The name, price, postage amount and other details for each of the prints are held in a table in a MySQL database. As postage amount may vary between prints and suppliers of the prints we must have the customer select postage per print - not the amount just yes or no. The customer may select as many of these prints as he desires - printa, printb, printc, printd etc. through to printz. Many of the prints are provided by separate individual suppliers and must therefore have postage paid for each ordered print and this is automatically added by the order form. However some prints are provided by the same supplier and only one postage fee needs to be chosen (yes or no), so these are not automatically added and the customer must choose to pay postage on only one of the prints (not all 3 if he orders 3 of them).
So for postage purposes I have a postage code on the table in the MySQL database. For example printa, printb and printc are all supplied by the same supplier so each have a linked postage code of A. Similarly others may also be linked using different postage codes e.g. printx and printy may have a postage code of B. So whenever a customer chooses a print that does not have a linked postage code then the postage fee is automatically selected for him and charged to the total. However where prints are linked to the same postage code we must allow the costomer to select postage (yes or no), but we must force him to select yes or no for at least one of the linked prints.
So to do this I need a javascript validation alert to force the customer to choose yes for postage for at least one of the prints, not necessarily all of them, where they have a linked postage code. To do that I can add the the postage linked code as an array for each print selected to a form hidden field so that my javascript can use the field as follows: <input type="hidden" name="postagearray[]" value="<? echo $postagecode; ?>">
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I have a user name, password, phone number etc., that all need to be validated before being submitted. The functions filter out the unwanted characters and null and zero length strings. I did have a pop up that listed the errors but I would prefer them to be listed below the log in screen that is a hidden div.I cannot get it to work.The validation works fine,
<html>
<head>
<title>WebCheatSheet - JavaScript Tutorial</title>[code].........
I am trying to do something, which should be fairly easy. I have a link that is defined as:
<a href="javascript: doTemplates(<?php echo $toggle_templates; ?>);" title="Click to show/hide message templates.">
The php code simply echos either 1 or 0 depending if the templates should be shown. Then I have the following function, doTemplates() defined as:
function doTemplates(input)
{
document.write('<input type="hidden" name="showMessageTemplates" value="' + input + '" />');
document.send_msg.submit();
}
The problem is that when you click the link, the page simply reloads to a blank page with the only code being the hidden field. This is not what I want, I want the hidden field code to be passed along, and then for the form to submit. So, what should have is that the hidden field code is added, and then the form submits.
I want to be able to set a hidden field with a value when I submit a form.
Here is the javascript
function submitEntry() {
var form = document.sobi2EditForm;
if (form.field_secondarycat1.value=='Nurseries'){
[Code]....
I've literally tried everything. Read 26 tutorials, interchanged code, etc. My validation functions all work. My AJAX functions work (tested manually using servlet URL's). The second servlet validates the reCaptcha form that's generated on my webpage. After the form is validated, even if everything's correct, nothing happens upon clicking submit. I even have an alert pop up if with the captcha result, just for middle-layer debugging purposes.
I want to do all of my validation clientside; none serverside. However, going to be tough if I can't get my god damn form to submit. I've been puzzled by this for close to 36 hours straight. I can't see, and I'm going to get some rest and hope that there is some useful insight on my problem when I return.
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I am beginner inthe programming , & I am trying to apply validation for different fields of a form, so that a user can get alert messages instantly at the time of mistake as if any form fields are empty or any Invalid values are entered. My validation is not working systematically & properly,the alert messages hangs the data entering process & some fields does not throw any alert messages & the process jumps over the remaining empty fields.Here is my code:-
Code:
<html>
<head>
[code]....
I am trying to use jquery's ajax framework to check if the data that is entered is valid or not. The form works properly except i cannot get the page to go to action="something.php" file in the form part.
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I enter a company into the form and hit submit The form will send the data to my validate company.php file. Validate company will return either "good" or "bad" If "bad" the form works as expected. it will stop the function by returning false and alert you that it is already in the database If "good" the page just sits there, basically returned false. however if you click submit again on the html form the function will go through and do what return: true should do.
I've a form. Before submit this forum i have to check if there are uploaded pictures for this form. I check the pictures with ajax. If there are no pictures the must come a alert (see below) otherwise the form must bu submitted with a post (regular submit, no ajax or something). It's working fine but only the formsubmit don't work. Someone who know this 'problem'?
<script type="text/javascript">
$(document).ready(function(){
$("#submit").click(function(){
[code]....
What I would like to do is have 2 buttons to submit a single form. One button is to save the form for editing later the other is to process it.With...
$("#saveform_ns").click(function(){
$('form#form_main').attr({action:"http://path/to/save.php"});
$('form#form_main').submit(); })
I can get the submit button to work and the above button to work.The issue I am having is that I have jquery validation in the form and whenever I hit the SAVE button it wants to validate the form (which I dont want it to as I want it to save at any point in the form). Does anyone know of a quick way to bypass validation code in jquery. Say with using an ajax call and form submit or someway to say if the SAVE button is clicked ignore the validation plugin.
I'll start out by confessing that I only dabble in javascript. But I need it in this case to validate information before allowing the item to be added to the PayPal cart.Here is the Javascript:
Code JavaScript:
function validateFields() {
var message = " ";
[code]....
Can't get form to submit but validation works... Even once the validation is accepted the form still will not submit.
Code HTML4Strict:
I have a form and i am using jquery validation plugin to validate form.now i want to after validation submit form using ajax.
here is the example.
Code:
<form id="frmRegister" action="" method="Post" >
<input type="text" id="username" name="username" value="" />
<input type="submit" id="btnRegister" name="btnRegister" value="Register" />
</form>
[Code]...
I'd like to know how to hide a form after a success validate with validation plugin. I'm try this:
submitHandler: function(form) {
$("#form").hide();
form.submit();
}
When I submit the form, it is hidden a few seconds, but then it come back.
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
I have a form on my page, which I want to validate on submit. The code looks something like this:
$('#form').submit(function(){ if ($('#field1').length == 4 && $('#field2').length == 3) {
$.ajax({
url: someAjaxUrl,
dataType: 'html',
type: 'get',
success: function(html){ if (html != '') {
//show error
} else {
//submit form
}}});
} else {
//show other error
} return false;
});
Now, if I try to use
$('#form').submit();
In the else statement within the success function, the validation keeps getting triggered in an endless loop.
But if I use
document.form.submit();
- or document.getElementById('kbaFormSearch').submit(); -
The form gets submitted correctly. Is this because the anonymous callback function within the earlier defined
$('#form).submit()
gets triggered again? And if so, is there a way to get this to work without using "native JS" (not that I'm against it, but it would not make much sense to me unless there is no other way).
My HTML with Javascript I had a problem with the form submittion.. where the javascript working fine for validation after completing validation my form submit is not processing to action specified in the form tag.
Here is the HTML Code
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I am trying to make form in dreamweaver with several text boxes. If the person doesn't fill out one or more of the boxes, I want an error message to come up which lists which boxes weren't filled out. If they ARE filled correctly, I want the page to redirect to a thanks page.This isn't online, and I'm new to coding. But its going ok, I just can't get the form to validate AND redirect if return true (or something???). I don't know how to do that. I've tried googling it, searching youtube tutes, and reading a few javascript books, but no joy.[code]
View 6 Replies View RelatedI seem to be having trouble getting the submithandler form attribute working. The link is here: [URL]. For some reason it submits and does not show the alert I have inside the function of the submithandler attribute.
View 1 Replies View RelatedI want to submit my problem. I use the plug-in "Validation" to check and send my "form", and thus far everything is working correctly, just do not know how to retrieve information from the page to which I have submitted my form, such as errors or other info.
View 2 Replies View RelatedI have a problem where if a form submission (set up to submit via AJAX) fails validation, the next time the form is submitted, it doubles the number of post requests - which is definitely not what I want to happen. I'm using the jQuery ValidationEngine plugin to submit forms and bind validation messages to my fields. This is my code below. I think my problem is that I need to unbind from the validationEngine plugin when the form fails, but I can't figure out how to do this.
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In another thread I found that a good way to show and hide parts of a form based on previous entries would be as follows:
function showhidefield (method) {
var hideablearea = document.getElementById("hideablearea");
var hideablearea2 = document.getElementById("hideablearea2");
var hideablearea3 = document.getElementById("hideablearea3");
switch (method) {
case "1":
hideablearea.style.display = 'block';
hideablearea2.style.display = 'none';
hideablearea3.style.display = 'none';
break;
case "2":
hideablearea.style.display = "none";
hideablearea2.style.display = "block";
hideablearea3.style.display = "block";
break;
case "3":
hideablearea.style.display = "block";
hideablearea2.style.display = "block";
hideablearea3.style.display = "block";
break;
default:
hideablearea.style.display = "none";
hideablearea2.style.display = "none";
hideablearea3.style.display = "none";
}}
I know how to use javascript to validate that the forms are infact filled but how do I make it so that it doesn't scan the hidden forms. The only way I could think of would be a huge bunch of if statements. Is there any other way to do this?
I've an input field in the form which is displayed based on the user selection. Initially it is set to 'display:none' and I do have a validation rule for that field.
How do I skip validation on this hidden input field and only validate when its displayed on the page.
I am trying to display validation error messages when form validation fails. Currently it does display the error messages but then disappears straight away. How can I stop the page from refreshing when validation fails? I have return false in my code when validation fails but still having same problem. Currently I have only done the validation for the full name only. The error msg is showed in:
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