I'm not sure if this is a php issue or jquery issue. When I complete the form and hit submit it puts the successful message up like its supposed to but also with the fields still filled in the form which it shouldn't be doing and it doesn't actually post in the database so I'm not sure if its a php issue or jquery issue.
<?php
I want to be able to send my whole form using jQuery ajax.The reason I want to send everything is that I have a lot of dynamic fields generated depending on choices the user does in the form and before the form is generated.
View 2 Replies View RelatedI am trying to submit a JSP page .
I will describe in short the scenario so that it would be clear.
The Scenario
I have some input elements made up in a html component on JSP page.
The table has many <tr>. These <tr> have been given ids, for e.g. <tr id="1">.
Now I am trying to pass a comma separated list of these tr ids to server side code or Servlet.
The comma separated list is formed with looping some logic on submit of JSP or more specifically a form.
The Problem:
When I submit the form sometimes I do not receive the comma separated values mentioned above at server side code.
This happens occasionally. Now when I put some delay through Java Script like setTimeOut() I do not face the issue.
Is Java Script behavior a bit non-sequential sometimes?
I am currently using jquery .post ajax code to submit a form.
The problem is that when I click on submit it takes me to the php file page. Which is blank.
I don't want this... this functions just like if I made the form in html meaning when submit it takes you to the .php file well opens it in a page.
I want to use ajax that when you click submit it submits the form and then shows a message on screen.
When I click the submit button my message gets shown on the screen saying it submittedsuccessful then with at least 2 seconds it sends the user to the php file meaning opens the page up in the browser not a new tab or new window but sends the user to the php file. Which I don't want it to happen. So the page is blank.
I used the .post and serialized the form. Is this the right thing to do?
I don't want to send the user to the php file. Just use ajax and check if it updated the database and if so send either 1 or 0 depending if it went threw then the form page willreceivethat data and then fade in a message saying either error or success depending what went on.
I would like to know how you can use jquery ajax to submit a form without refreshing the page. I do know about the serialization function but would like to see an example of what is submit().
I currently tried to get my form working but but can't get it to work meaning to submit something from the form.
I have a general idea of how this works but i need further explanation. I have a form that needs to post into one list and then post into another list as well.Here is the ajax code and html code:
View 2 Replies View Relateddt_save is a <form>, the submit trigger works as usual but when doing an Ajax request the code interrupts without any error. I put in 2 alert's just to check, only the first alert box appears when submitting the form. Also I can't find my request in Firebug's Network window (Firefox addon).
$('#dt_save').submit(function(){ alert('json request'); $.ajax({ type: "POST", url: "json.php?action=extendable_select_insert", dataType: "json", data: "into=empfaengerliste&col=empfaenger&value=" + encodeURIComponent(document.getElementByID("data[empfaenger]_t").value), success: function(data) {} }); alert('done'); });
PS: Of course the requested PHP-File exists!
How can I submit the contents of my form? This code submits NO data. I want to submit the data in my form. I want the values of my form to be submitted.
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I have a form and i am using jquery validation plugin to validate form.now i want to after validation submit form using ajax.
here is the example.
Code:
<form id="frmRegister" action="" method="Post" >
<input type="text" id="username" name="username" value="" />
<input type="submit" id="btnRegister" name="btnRegister" value="Register" />
</form>
[Code]...
I am adapting a small cart for a website of mine - I am using the cart below
[url]
I have tweaked it to my liking but I am wondering how exactly the form is setup to post? I would like to set it up so that it posts directly into a database on submit, and then displays confirmation that it has been submitted. At the moment it just echo's "TOTAL PRICE:" XXX it's obviously submitting the form somewhere, but where is it going and how can I change it?
Here we are (a part of index.php) :
My problem is that when I submit my form,writePersonneSGBD.php seems to be quite well executed , because my record is created as wished in my database, but there is no way it returns anything (out) and display something in my div container. instead of that,and I really dont understand why, after the end of the function, index.php is executed again and so a new form is displayed again in the div "container"
I'm using the submit and ajax functions to check a form. When the form is submitted the submit event executes and within that event the data (a code the user has to fill in) is sent to the server to check if it's correct. If it is correct, the submit event supposes to return true (so the form submits), if it's incorrect the submit event supposes to return false (so submitting the form cancels).
Here's my code that should do this:
$(function(){
var submit = false;
$('#login').submit(function(){
$('span.error').fadeOut('slow');
$.ajax({
url: '/ajax/login',
type: 'POST',
data: 'code=' + $('#code').val(),
success: function(response){
if (response != ''){
$('span.error').fadeIn('slow').text(response);
submit = false;
}else{
submit = true;
}}})
return submit;
})});
But here's the problem: While jQuery does the ajax request, the script continues. So it will return false - even if the code is validated - because the var submit has been set to false at line 4. When I submit the form again, the form is validated because 'submit' is true (but that's set to true the first time). How can I ensure the submit function waits for the ajax request to finish?
i am trying to build my form to submit without reloading the screen. I am using jquery and it inserts the data but it also reloads the screen and two database records get inserted. It appears that one is being inserted by jquery and the other is being inserted by the normal form submission. How do I remove/override the normal form submission? My html code is as follows:
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im trying to learn how jquery ajax function works by validating some form after submit is clicked.
[Code]....
the alert didnt pop until i added the registration_ok = false; right before, so im assuming it has something to do with the ajax functions's scope.... why does the ajax function not affect the registration_ok variable outside the function? and how should i solve this problem? any better way of doing it?
I've literally tried everything. Read 26 tutorials, interchanged code, etc. My validation functions all work. My AJAX functions work (tested manually using servlet URL's). The second servlet validates the reCaptcha form that's generated on my webpage. After the form is validated, even if everything's correct, nothing happens upon clicking submit. I even have an alert pop up if with the captcha result, just for middle-layer debugging purposes.
I want to do all of my validation clientside; none serverside. However, going to be tough if I can't get my god damn form to submit. I've been puzzled by this for close to 36 hours straight. I can't see, and I'm going to get some rest and hope that there is some useful insight on my problem when I return.
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I'm making a call to a Twitter JSON feed, and when I pass an incorrect username, jQuery's ajax complete method never gets called.
An example of a JSON response that causes complete not to be called (nor error, nor success) is: [url]
Here's my code:
Any ideas on why the complete method isn't getting called? Shouldn't this always get called?
I would like to submit a form depending on the success data of an ajax post.
Below is my jquery code; as you see #theform is the main form and before submitting the form I need to check the availability of the the date and time and the room using$.ajax. However it doesn't submit the main form if the date, time and the room is available.
required=["txtCal_Event_CalendarID","txt_TreatmentRoom","txtTreatmentID","txtTreatmentTypeID","datepicker1","datepicker2","timepicker1","timepicker2"];
emptyerror="Please fill out this field.";
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I have what I think is a simple $.ajax() call.I added complete and error functions but a time out in firefox 3.5.2 doesn't cause the error function to be called and when the complete function is called both parameters are undefined.If I make the ajax call return a http 500 response the error function is called.[code]Running on FF 3.5.2, JQuery 1.6.2 on XP Pro.
View 3 Replies View RelatedHow might I go about getting the parsed JSON object in the complete function? The json param shown below seems to just receive the http status text message.
My 2nd question would be how should I knwo if the first place what params I can receive to a callback function like this?
$.ajax({
type: 'POST',
url: 'url.json',
dataType: 'json',
[Code].....
I have a problem where if a form submission (set up to submit via AJAX) fails validation, the next time the form is submitted, it doubles the number of post requests - which is definitely not what I want to happen. I'm using the jQuery ValidationEngine plugin to submit forms and bind validation messages to my fields. This is my code below. I think my problem is that I need to unbind from the validationEngine plugin when the form fails, but I can't figure out how to do this.
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Does the "submit" button always submit form data in non-ajax way?What are the best practices for submitting forms using xhr?
View 1 Replies View RelatedI have a page (run with classic asp) that uses drop down boxes and this function to refresh the page for form submit:
<script>
function dept_onchange(frmSelect) {
frmSelect.submit();
};
</script>
<SELECT onchange="return dept_onchange(frmSelect)">
[code]...
For example, I have commenting system where I want to use ajax to display and submit comments.
How do I check if user is logged in, if logged in then display the form, otherwise forward it to login page.
Once they submit the form, how do you update the page to reflect the changes?
Do you update the partial page or just reload the whole page with new comment?
I'm looking for an autocomplete that have no "submit" button, but that when the user click on the autocomplete keyword he would be redirected to another URL, that i will choose
I'm using [url] but even the author dont know how to make this
Example: user type "goo" then appears GOOGLE for him, when he click on GOOGLE the script send him to [url]
I have one-field form on my website, which is supposed to be filled with barcode number. It was functional until few days age when the need emerged for the auto-submit. As you can see, I have to make script which will automatically submit form when data is filled in barcode field.
View 9 Replies View RelatedScenario: I have a form with around 125 input fields. I want to use .ajax() to send these form data to the server.Is there a way to send the entire form to the server? Like, the form is passed when we click submit button and url changes. But I want to achieve this using AJAX.
View 2 Replies View Related