I want to be able to send my whole form using jQuery ajax.The reason I want to send everything is that I have a lot of dynamic fields generated depending on choices the user does in the form and before the form is generated.
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I'm not sure if this is a php issue or jquery issue. When I complete the form and hit submit it puts the successful message up like its supposed to but also with the fields still filled in the form which it shouldn't be doing and it doesn't actually post in the database so I'm not sure if its a php issue or jquery issue.
<?php
I am trying to submit a JSP page .
I will describe in short the scenario so that it would be clear.
The Scenario
I have some input elements made up in a html component on JSP page.
The table has many <tr>. These <tr> have been given ids, for e.g. <tr id="1">.
Now I am trying to pass a comma separated list of these tr ids to server side code or Servlet.
The comma separated list is formed with looping some logic on submit of JSP or more specifically a form.
The Problem:
When I submit the form sometimes I do not receive the comma separated values mentioned above at server side code.
This happens occasionally. Now when I put some delay through Java Script like setTimeOut() I do not face the issue.
Is Java Script behavior a bit non-sequential sometimes?
I'm looking for an autocomplete that have no "submit" button, but that when the user click on the autocomplete keyword he would be redirected to another URL, that i will choose
I'm using [url] but even the author dont know how to make this
Example: user type "goo" then appears GOOGLE for him, when he click on GOOGLE the script send him to [url]
Scenario: I have a form with around 125 input fields. I want to use .ajax() to send these form data to the server.Is there a way to send the entire form to the server? Like, the form is passed when we click submit button and url changes. But I want to achieve this using AJAX.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I am having trouble with a page that has a form on it. What I need to be able to do is to pop up a message on the page (alert or confirm function) that will tell the user that leaving this page is unwise as their information will not be sent. Here is the tricky part:
1. This page has a lot of links on it that can take the user to any number of different pages. I am not able to put any javascript additions to the html of the links.
2. I don't want the message to pop up when the user clicks the Finish button ( a submit or button form input, whichever works best ).
I have added and onunload() javascript to the body of my page so that when any link is pressed (including the finish button) it runs a script to verify the pressing of the finish button. It SHOULD be checking to see if Finish was pressed and if it was continue, if not issue the confirm or alert to warn the user that they should not leave before finishing.
I have already been through the javascript O'reilly guide and can't figure it out. In PHP (which is my primary language) I could say something like:
if (!isset($finishbutton)) { do what I want };
However, PHP won't work for this. I need to be able to have JS do something like this:
if ({formelement finishbutton} has NOT been clicked) { do what I want }
I am trying to have a form calculate total using this script, works OK until the total reaches 99 from there on it only returns 2 figures. Also it won't work if I complete the dollar value (i.e add .00)
<script type="text/javascript">
function startCalc(){
interval = setInterval("calc()",1);[code]....
I have a form set up and I need to set the validation so if one option is selected from a picklist, they need to complete a text field as well.
This is the code i'm using:
Code:
Reason is a picklist, I want it to show the alert when option 1 from the picklist is selected and no text is in the Row_Number field.
If any of the other options are selected, I want to make sure the Row_Number field is blank.
As I said, I'm sure this is a very simple thing, but I been working on it for ages, and cannot get it to work, I get the alert every time the Row_Number field is blank.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIs it possible to read a web page on some web site that contains a form. Then identify the fields in the forms. Then fills the fields with my data. and then submits the form as it submitted normally. I need to do this to automate for my final proyect , i need to fill many web pages remotly
View 2 Replies View RelatedThe following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
$(document).ready(function(){
$("#myForm").validate();
});
[code]....
I'm trying to get an upload popup working with the jQuery form plugin[URL].. When I click a link I load a form html from the server and add it to a container div by setting the div's html attribute. I then attach a submit handler to the form so I can call the ajaxSubmit function of the form plugin.
[Code]...
Malsup's most excellent and comprehensive Form plugin has me completely stuck on just one thing.Take a look at this: http:[url]....At the bottom are a variety of submit buttons, and when you click one, it knows which one has been clicked.And I've been through the js and the source and the examples and I can't figure out how the bleep it's done!I'll tell you why I'm asking, then perhaps you can probably tell me I'm doing it wrong anyway!Let's say a blind person logs in, and want to edit their presets.I don't want the form to be too complex or clever or ajaxy, as screenreaders don't like that, so it just iterates through as many presets as they have, and populates a form with edit boxes.But there's no point "pushing back" 29 unchanged items just to edit one row.
So my idea was I'd just "fieldSerialize()" the details of the row that was currently being edited and submit that to my little php routine that updates the db. Then they can do a refresh just to hear the list again.The js looks like:
$(document).ready(function() {
$('#myForm').ajaxForm(function() {
var queryString = $('#myForm').formSerialize(); [code]....
All works fine like that. But if I change line 3 to: var queryString = $('#myForm :button').fieldSerialize(); it doesn't work. I've also tried:
'#myForm :button'
'#myForm .button'
':button'[code]....
Maybe I should just generate as many separate forms as there are presets, but then I'm going to need as many ready(function)'s as there are rows, which is going to be very messy.
I have a php form and it has 3 submit buttons namely "delete" , "update_quantity" and "place_order".They all work fine but I want to build in a check for each one just in case the user click one of the buttons by mistake.So Each one must have a different message like for delete it must be, "Are you sure you want to delete Record nr ......" OK or Cancle.
And for update " Are you sure you want to update Quantity to....." OK or Cancle.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I have my form working great as long as my submit button is contained within the form tags. But the design calls for the submit button to be outside of the form. Sample code and diagrams are below.
<form>
my form here
</form>
<div> </div>
<div> Submit button </div>
[Code].....
So, here's my problem :
I've created a table in my document, presenting a list of items, one
can 'select' by clicking on it... (Kinda like a menu, you make your
choice from) But since this table can get very long, I've put
something of a 'search-form' on top, which enables the user to make a
selection of products from the list.
Now, the form uses a "post" method, and submits to itself, using the
form action. Some PHP script will make sure that the form is filled
out already, the next time it's presented.
The table, containing a list of products is presented, below the form.
When a user clicks on a product, the product should be "selected". At
first i just used a <a href="zoeken.php?prod_id=24"> link to do this,
but the problem is that my form won't remain in tact.
So now, the global idea is to submit the form after setting a hidden
form-field using JavaScript, using a onClick event.
Here's my code :
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
[Code]...
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
I have a form in my webpage that I would like to submit to a different action in a _blank window, but without changing the original form.So I've tried this :
$('#myform').clone().attr('action', '/something/else').attr('target', '_blank').submit();
But it won't submit unless I append the new form in the page (which I don't want).
I am trying to use jquery's ajax framework to check if the data that is entered is valid or not. The form works properly except i cannot get the page to go to action="something.php" file in the form part.
[Code]...
I enter a company into the form and hit submit The form will send the data to my validate company.php file. Validate company will return either "good" or "bad" If "bad" the form works as expected. it will stop the function by returning false and alert you that it is already in the database If "good" the page just sits there, basically returned false. however if you click submit again on the html form the function will go through and do what return: true should do.
This should be so simple but it isn't working. I just want to check that the value of a form element isn't empty before the form is submitted, if it is empty display an error, if not,submit the form. 101 right?[code]So how do I make the form not submit on fail?
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