This should be so simple but it isn't working. I just want to check that the value of a form element isn't empty before the form is submitted, if it is empty display an error, if not,submit the form. 101 right?[code]So how do I make the form not submit on fail?
I am building a registration form and have some javascript that checks the forms user input. This is all activated when the submit button is pressed and the forms onSubmit event is called and runs a function.
I have tested me functions and even when it returns false the form still submits?
Im not sure how i can stop it submiting even if it returns false.
Then onSubmit called this function:
function subForm(theform){ if(checkForm(theform)==false){ alert("it is false"); return false; } alert("it is true"); return true; }
checkForm is working and is throwing alerts when certain criteria is not correct in the form, and then i will get an alert "it is false" so i know that the script is running until then, but the form will still submit?
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() { $("#ARTransferForm").submit(function() { var msgsCount = 0;[code]....
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I'm wondering if there is a way to check if a form is valid withouttriggering UI feedback for invalid fields in the form? I tried boththe $('#myform').valid() and validator.form() methods, but they bothtrigger the UI.
I'm building a site that requires user registration, I've already built myself a PHP based user registrationg system, and it already has all the usual checks that are required before letting someone sign up (i.e. that the username is unique, that all required fields are filled, that the two passwords match, that the email address is valid, etc..) using PHP, and so I could ship the system as it is.. but.. I wanted to add some JavaScript checks to it aswell (just to be sure, and to save processor power, etc.. you know how it is). Code:
I'm trying to do this with PHP, although I think it would be easier if I used JavaScript, or maybe the same, I'm not sure.
If a user enters a value into the textbox, I want him to be able to move on only if it's a number, otherwise have text come up next to the textbox saying that he should enter a number.
I have another problem (Im not very handy with javascript).I want to check if a value entered into a form is a whole number. This means it cannot contain a decimal.I wanted to use isNumeric() but realised that allows for decimals.Is there a way I can make sure a value is simply a whole number (0-9)
i have a form and would like to check two fields. if field 1 containes the letter 'c' and the other field contains 'undefined', then an error should apprear ina box on the screen.
Is there way to make it to where if someone clicks one check box the rest get checked without knowing the names of the other form names? Meaning if I load a form with a dynamic number of entries, maybe it will show 8 check boxes or perhaps 6 and I wont know the name of the form fields. So is there a way if they click one main check box the rest get checked?
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
Is it possible to read a web page on some web site that contains a form. Then identify the fields in the forms. Then fills the fields with my data. and then submits the form as it submitted normally. I need to do this to automate for my final proyect , i need to fill many web pages remotly
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
I am allowing a user to selected a date to schedule an event and it seems like the best way to do this is with drop down menus for Year, month, date. However I would like to make it so when you choose a year and a month the appropriate days for that month show (i.e. 28 days if you chose February 2006). I can easily do this with a loop if I can find out what month the user has selected, but I can't seem to find a way to get that value. Is there a simple javascript solution to this problem?
I'm currently learning many web programming languages and figured this would be a good way to learn more and do things better. I have been working on a contact form for my website. I had originally did the error checking in PHP, but I would like to change it to JaveScript since this is the preferred way. I have it all semi working,It seems like I have some unnecessary variables and such.. I would like to clean it all up as best as possible.
I have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
I'm trying to get an upload popup working with the jQuery form plugin[URL].. When I click a link I load a form html from the server and add it to a container div by setting the div's html attribute. I then attach a submit handler to the form so I can call the ajaxSubmit function of the form plugin.
Malsup's most excellent and comprehensive Form plugin has me completely stuck on just one thing.Take a look at this: http:[url]....At the bottom are a variety of submit buttons, and when you click one, it knows which one has been clicked.And I've been through the js and the source and the examples and I can't figure out how the bleep it's done!I'll tell you why I'm asking, then perhaps you can probably tell me I'm doing it wrong anyway!Let's say a blind person logs in, and want to edit their presets.I don't want the form to be too complex or clever or ajaxy, as screenreaders don't like that, so it just iterates through as many presets as they have, and populates a form with edit boxes.But there's no point "pushing back" 29 unchanged items just to edit one row.
So my idea was I'd just "fieldSerialize()" the details of the row that was currently being edited and submit that to my little php routine that updates the db. Then they can do a refresh just to hear the list again.The js looks like:
$(document).ready(function() { $('#myForm').ajaxForm(function() { var queryString = $('#myForm').formSerialize(); [code]....
All works fine like that. But if I change line 3 to: var queryString = $('#myForm :button').fieldSerialize(); it doesn't work. I've also tried:
Maybe I should just generate as many separate forms as there are presets, but then I'm going to need as many ready(function)'s as there are rows, which is going to be very messy.
I have a php form and it has 3 submit buttons namely "delete" , "update_quantity" and "place_order".They all work fine but I want to build in a check for each one just in case the user click one of the buttons by mistake.So Each one must have a different message like for delete it must be, "Are you sure you want to delete Record nr ......" OK or Cancle. And for update " Are you sure you want to update Quantity to....." OK or Cancle.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code: What I've tried so far is like this: savedSubmit = document.inputs.submit; document.inputs.submit = None; then later: document.inputs.submit = savedSubmit;
I am having some trouble with my code in that I am trying to take the value from the date of birth field and check to see if over 18 years old. I they are not over 18, a window.alert dialog box pops up to tell them. Below is the check if 18 validation.
Script section in the document head:
//check if over 18 function overAge(){ var age;
[code]....
Code for body section:
Date of Birth: <br/> <input type = "text" name = "date" value = "(mm/dd/yyyy)"/>
What I am wanting to do is have my form open up a new part of the form when the previous sections are filled out. i.e name field shows, when it has content, the next field opens up for it to be filled out, and so on.
I made a contact form for my website originally in PHP. I wanted to change it to JavaScript because that is the preferred way. Originally I had the form in my HTML file using a separate PHP file for error checking. For JavaScript do I have to make a separate page and call to it like the last time? I have put it all on my HTML page and where it was calling for the php page, I also put the JavaScript code. When I go to my site, the error checking is not working at all. There must be something wrong, but I haven't been able to point it out and I am very new to JavaScript. Also, when I go to my page and right click for the source code, the JavaScript I have in there does not show up. Below is my HTML code.
I have my form working great as long as my submit button is contained within the form tags. But the design calls for the submit button to be outside of the form. Sample code and diagrams are below.
<form> my form here </form> <div> </div> <div> Submit button </div>
I've created a table in my document, presenting a list of items, one can 'select' by clicking on it... (Kinda like a menu, you make your choice from) But since this table can get very long, I've put something of a 'search-form' on top, which enables the user to make a selection of products from the list.
Now, the form uses a "post" method, and submits to itself, using the form action. Some PHP script will make sure that the form is filled out already, the next time it's presented.
The table, containing a list of products is presented, below the form. When a user clicks on a product, the product should be "selected". At first i just used a <a href="zoeken.php?prod_id=24"> link to do this, but the problem is that my form won't remain in tact.
So now, the global idea is to submit the form after setting a hidden form-field using JavaScript, using a onClick event.