I am adapting a small cart for a website of mine - I am using the cart below
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I have tweaked it to my liking but I am wondering how exactly the form is setup to post? I would like to set it up so that it posts directly into a database on submit, and then displays confirmation that it has been submitted. At the moment it just echo's "TOTAL PRICE:" XXX it's obviously submitting the form somewhere, but where is it going and how can I change it?
I have a website that I'm trying to install a shopping cart on and I'm trying to make it so when a certain color is selected an option pops up as an additional feature people have the option of choosing, but I only want the option visible when certain colors are selected. I think I have the code figured out, but there are 2 colors I want the option visible for and currently the option is only showing up for one of the colors. I tried creating two id's for each color and two jQuery codes that were basically the same but one for #color1 and one for #color2 but that didn't work either.
Need some possible technical solutions to my current project. Im in the middle of creating an 'offline' photo gallery website (on CD). Quite simple, but the challenge is how I can build an offline ordering process which
1) Allows the person browsing the cd photo gallery to select various photos, 2) Generate some sort of page/file which can then be printed then faxed, or even emailed if possible.
Does anyone have any tips on the best way to do this?
I have installed a purchased shopping cart and for the price is does most of what I need...the problem is the shopping cart doesn't empty after the order is sent. I have copied all of the various pieces of the script into an RTF if anyone would like to take a look at it. It's too long to post the whole thing here...or should I?
I have just joined this forum hoping for some help on a problem i am having, i have a feeling the solution is simple but im a noob at JAVA so i have no idea how to work it out.
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When you select US (West Coast) as your location it doesn't update the price on the right properly. If you select it first it just won't display anything. if you select it after choosing another one and hitting continue then it doesn't change.
I am designing a PayPal shopping cart/store for a client and have placed several of PayPal's shopping cart forms on the page to correspond with different products. Each form has a unique name though each of the form's elements have to use PayPal's required naming conventions to pass the data to their server.
Many of the forms have hard-coded data in them and these have not caused me any problems. The problems I am having are with 3 forms that need to send different amounts based on the quantity ordered. I wrote a small function that worked great on the 1st form but when I created the 2nd form and wrote the 2nd function, all of the forms that needed to send conditional amounts broke down and wouldn't work any more. Code:
And one of the features is selecting/making ads that you want to see in a separate page later on(something like a shopping cart) BUY way simpler
after a user search for something he gets a LIST of numbered ads(different ID for each) and a button SELECT/MARK this ad.
This select/mark button suppose to add the specific ad ID to a coockie and then when the user clicks "go to see my ads" its will pass ALL the ID numbers to aPHP page that will print what it should.
what I was trying to do is try to use a "shopping cart" script and just use the part that each product has a "add to cart" button and in the "my cart" page it will show the selected products, but as I have no clue about javascript in this way I was willing to pass the variables(ID numbers) with JS and $_GET them with PHP and from there I can continue
so what I need is : Asimple <form> that when u submit it , it sends a variable(ID) to a coockie and STAYS ON THE SAME PAGE then when you decide to see the selected list it will pass all the ID variables to the page with the link it self and I can GET it with PHP.
I want to enable the user to pick merchandise from a drop-down menu that is linked to the Javascript database. I want the ability for the user to pick multiple items and multiple quantities if desired. Then I want it to be able to calculate the price and display the info for the customer. I do not know how to link the drop-down menu w/the databaseHere is what I got so far:
I am currently using jquery .post ajax code to submit a form.
The problem is that when I click on submit it takes me to the php file page. Which is blank.
I don't want this... this functions just like if I made the form in html meaning when submit it takes you to the .php file well opens it in a page.
I want to use ajax that when you click submit it submits the form and then shows a message on screen.
When I click the submit button my message gets shown on the screen saying it submittedsuccessful then with at least 2 seconds it sends the user to the php file meaning opens the page up in the browser not a new tab or new window but sends the user to the php file. Which I don't want it to happen. So the page is blank.
I used the .post and serialized the form. Is this the right thing to do?
I don't want to send the user to the php file. Just use ajax and check if it updated the database and if so send either 1 or 0 depending if it went threw then the form page willreceivethat data and then fade in a message saying either error or success depending what went on.
I would like to know how you can use jquery ajax to submit a form without refreshing the page. I do know about the serialization function but would like to see an example of what is submit().
I currently tried to get my form working but but can't get it to work meaning to submit something from the form.
I have a general idea of how this works but i need further explanation. I have a form that needs to post into one list and then post into another list as well.Here is the ajax code and html code:
dt_save is a <form>, the submit trigger works as usual but when doing an Ajax request the code interrupts without any error. I put in 2 alert's just to check, only the first alert box appears when submitting the form. Also I can't find my request in Firebug's Network window (Firefox addon).
I'm not sure if this is a php issue or jquery issue. When I complete the form and hit submit it puts the successful message up like its supposed to but also with the fields still filled in the form which it shouldn't be doing and it doesn't actually post in the database so I'm not sure if its a php issue or jquery issue.
How can I submit the contents of my form? This code submits NO data. I want to submit the data in my form. I want the values of my form to be submitted.
My problem is that when I submit my form,writePersonneSGBD.php seems to be quite well executed , because my record is created as wished in my database, but there is no way it returns anything (out) and display something in my div container. instead of that,and I really dont understand why, after the end of the function, index.php is executed again and so a new form is displayed again in the div "container"
I'm using the submit and ajax functions to check a form. When the form is submitted the submit event executes and within that event the data (a code the user has to fill in) is sent to the server to check if it's correct. If it is correct, the submit event supposes to return true (so the form submits), if it's incorrect the submit event supposes to return false (so submitting the form cancels).
Here's my code that should do this: $(function(){ var submit = false; $('#login').submit(function(){ $('span.error').fadeOut('slow'); $.ajax({ url: '/ajax/login', type: 'POST', data: 'code=' + $('#code').val(), success: function(response){ if (response != ''){ $('span.error').fadeIn('slow').text(response); submit = false; }else{ submit = true; }}}) return submit; })});
But here's the problem: While jQuery does the ajax request, the script continues. So it will return false - even if the code is validated - because the var submit has been set to false at line 4. When I submit the form again, the form is validated because 'submit' is true (but that's set to true the first time). How can I ensure the submit function waits for the ajax request to finish?
i am trying to build my form to submit without reloading the screen. I am using jquery and it inserts the data but it also reloads the screen and two database records get inserted. It appears that one is being inserted by jquery and the other is being inserted by the normal form submission. How do I remove/override the normal form submission? My html code is as follows:
im trying to learn how jquery ajax function works by validating some form after submit is clicked.
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the alert didnt pop until i added the registration_ok = false; right before, so im assuming it has something to do with the ajax functions's scope.... why does the ajax function not affect the registration_ok variable outside the function? and how should i solve this problem? any better way of doing it?
I've literally tried everything. Read 26 tutorials, interchanged code, etc. My validation functions all work. My AJAX functions work (tested manually using servlet URL's). The second servlet validates the reCaptcha form that's generated on my webpage. After the form is validated, even if everything's correct, nothing happens upon clicking submit. I even have an alert pop up if with the captcha result, just for middle-layer debugging purposes.
I want to do all of my validation clientside; none serverside. However, going to be tough if I can't get my god damn form to submit. I've been puzzled by this for close to 36 hours straight. I can't see, and I'm going to get some rest and hope that there is some useful insight on my problem when I return.
I would like to submit a form depending on the success data of an ajax post.
Below is my jquery code; as you see #theform is the main form and before submitting the form I need to check the availability of the the date and time and the room using$.ajax. However it doesn't submit the main form if the date, time and the room is available.
required=["txtCal_Event_CalendarID","txt_TreatmentRoom","txtTreatmentID","txtTreatmentTypeID","datepicker1","datepicker2","timepicker1","timepicker2"]; emptyerror="Please fill out this field.";
I have a problem where if a form submission (set up to submit via AJAX) fails validation, the next time the form is submitted, it doubles the number of post requests - which is definitely not what I want to happen. I'm using the jQuery ValidationEngine plugin to submit forms and bind validation messages to my fields. This is my code below. I think my problem is that I need to unbind from the validationEngine plugin when the form fails, but I can't figure out how to do this.
I have a page (run with classic asp) that uses drop down boxes and this function to refresh the page for form submit: <script> function dept_onchange(frmSelect) { frmSelect.submit(); }; </script> <SELECT onchange="return dept_onchange(frmSelect)">
