JQuery :: Declaring Return Values Within A $.each

Sep 8, 2011

I have a understanding problem with this:

var loadData = function(){
$.post('/search.php', { myvar: 12345 }, function(data){
$.each(data, function(key, val) {
// here I have to validate my data I retrieved
if(first condition){
return false;
[Code]...

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Declaring Variables Within HTML - Save The Input And Pass It Into The URLs That Are The Option Values?

Mar 15, 2011

Trying to build a little tool here..

<html>
<body>
Artist ID: <input type=TEXT id=ArtistID name= ArtistID value="Artist ID">[code]....

I'm trying to save the input and pass it into the URLs that are the option values. So Artist ID being 111 would take you to url..../<WHATEVER OPTION YOU CHOSE FROM DROP DOWN>/111
What am I doing wrong/What am I not doing?

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JQuery :: Attr() Return Different Values Across The Versions?

Jan 8, 2012

I have a problem with attr() function.I made my own lightbox and with jQuery 1.4.x it works nice. But now I use 1.7 and there is a problem. When I called attr in 1.4 $(element).attr("rel") when element hasn't rel, it returns empty string, but in 1.7 it returns undefined.Why? I read a changelog and I didn't find any change at that function.

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JQuery :: Declaring An Empty Array?

Aug 28, 2009

What I want to do is declare an empty array. so i do it like this:

var changedValues = {};

Now i m populating this array dynamically with values, something like this

changedValues[elemName] = elemValue;

This also works fine. BUT, when i do a alert(changedValues.length)....

it gives "UNDEFINED" even though the array is not empty. Saw it through firebug .. Can anyone tell me wht is happening here?

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How A Function Return Two Values?

Jul 11, 2006

Can javascript using pointer or pass variable by reference?

Or I need to using object or Array to return the two values?

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Return Php Values (for 'AjaxfileUpload')?

Dec 8, 2011

I am trying to build an interface to upload files and change some of the form (hidden) values depending on the file uploaded, here is where I got so far:

$('#buttonUpload').click(function (){
$.ajaxFileUpload({
url:'doajaxfileupload.php',
secureuri:false,
fileElementId:'fileToUpload',
dataType: 'txt',
[Code]....

My problem is that I want doajaxfileupload.php to return a variable to javascript/change some html form value. The code works as it is for the file upload, I just need to add something for the output, Edit: I just noticed that some previous part of the code is still there: the part that changes the color of the button depending if the file is uploaded or not. Now I want those values to change depending on what file is uploaded.

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OOP Won't Return Values / Get It To Work?

Jun 29, 2011

Ok so i'm going to try and be as descriptive as possible for this issue is extremely challenging for me to resolve.

I am creating an auto suggest search feature and I decided to do it in OOP.

My current set up is like this..code...

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Using Multiple Return Values ?

Jun 10, 2009

I was looking at some public code for detecting browser version/type as well as the new IE8 compatibility view. The code does a return of multiple values but I can't figure out how to use them in my html code.

I've managed to figure out most of what the code is doing but I haven't figured out how to access the returned information. I've only been coding JavaScript for a short time so I'm stumped.

Here's the code:

CODE:

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Return Sum Of All Input Values Within Loop

Jan 19, 2006

I have a bunch of input fields, each which will have a numerical value. There can be any number of input fields in the form, and that number will vary depending on what the user has selected prior in the application.

So basically I created a loop that goes though all of the INPUT fields within the form. How can I have it find the value of each field and add them all together, then return to me the total? It'll need to be made into a variable, but a simple alert with the total value will give me enough to work with.

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Return Values From Windows.onload

Jan 30, 2006

i am finding value for a table height in window.onload=function(){

boxheight=document.getElementById('tableid').offsetHeight;
}
i want to assign box height to an outside variable boxheight. Code:

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Firefox - Safari Return Opposite 'disabled' Values On Startup

Aug 12, 2009

This has me completely stumped. I have a multiple select form element in my HTML document that needs to be manipulated by two different sets of context-sensitive controls. One set of controls is marked up as follows:

<div id="divControls1" name="divControls1" style="display:none">
<form id="fControls1" name="fControls1">
<input type="button" id="btnAdd" name="btnAdd" value="Add" onClick="addStuff();" />
<input type="button" id="btnEdit" name="btnEdit" value="Edit" onClick="editStuff();" disabled />
<input type="button" id="btnDelete" name="btnDelete" value="Delete" onClick="deleteStuff();" disabled />
</form>
</div>

When I load this page into Safari (on Mac OS X) and set the style of divControls1 to "display:block," I have an enabled "Add" button, a disabled "Edit" button, and a disabled "Delete" button, just as I expected. (I monitor selections in a multiple selection element to turn the buttons on and off.) But when I load this page into Firefox (also Mac OS X), all three buttons are disabled at startup. My page runs a function called startup() when the body fires onLoad. To try to troubleshoot the problem, I wrote this line at the beginning of the startup() function:

function startup() {
alert (document.getElementById("btnAdd").disabled);
...

When I run this code in Safari, the alert returns "false" (not disabled), just as I would expect, and intended. However, the same code in Firefox (Mac OS X) returns "true" (disabled) ... but the same code in Firefox (WinXP) returns "false"!

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JQuery :: Dynamically Declaring Functions - 'array' Variable Contains Strings Representing The Id's Of Different Elements

Oct 12, 2010

Demonstration code:

The 'array' variable contains strings representing the id's of different elements. If the for loop above were to finish iterating, would all the links in all three elements call the click function (that displays an alert message), or would only the last element ("element3") have the click function? For me, the latter seems to be the case unless if I'm doing something wrong, but I would like clarifications and, if possible, alternative solutions as to how I can achieve the former result.

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Declaring / Using Array Of Arrays

Mar 27, 2010

(the "code" below is pseudo code, just to get the idea across)

Here's what I currently have:

var bill = new array[20];
var sam = new array[20];
var nancy = new array[20];
var Oscar = new array[20];

I'm assigning objects to them (ie Oscar[5] = new objLabel() This seems like a kluge, however. Here's what I'd like (again, pseudo-code)

var Objects = {bill:null; sam:null; nancy:null; Oscar:null};
var theObject = new Array of Objects[20];
// yes: i know that's wrong... and that's the part I'm having trouble with

so that I can do something like:

[Code]....

Just seems to me that keeping a single array of multiple objects is likely to be less error-prone than multiple arrays of single objects... But I don't have the syntax right... or can it be done in JS? If it's doable, would someone be kind enough to show me how to declare and access that example?

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Declaring Parameter As An Array?

Jun 10, 2010

I have a php script which calls a javascript function with a parameter. I am having trouble getting this parameter act as an array inside the javascript function:

php:
Code:
<? $array1 = '"apple","orange","banana"';
$array2 = '"corn","bean","beet"';
$arrays = $array1.'///'.$array2;

[Code]..

JS sees fruits and vegs as a string rather then an array, so if I try to output fruits[0]; it gives me the entire string rather then seeing it as an array and giving me the first element.

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JQuery :: $('#mydiv').css('margin-left') Return 0px (must Return Auto)

Jun 3, 2010

All is on the title, sorry for my english, i'm french :) I have an html page with style

<style>
#mydiv {
margin-left:auto;
margin-right:auto;
width:250px;
}
</style>

with jquery, i try to get the margin-left ($('#mydiv').css('margin-left'), but the function return 0px, unable to retrieve the good value (auto) anyone has idea to retrieve the value "auto" when margin-left is "auto" ?

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Difference Between Declaring Var Inside Function And Outside?

Aug 21, 2010

I worked on a simple image slide-show with javascript, and I assigned a value to a var outside of a function using getElementById() like this:

Code:
window.onload = initLinks;
myImg = new Array("images/img01.jpg","images/img02.jpg","images/img03.jpg","images/img04.jpg");
curPic = 0;[code]..........

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Difference Between Ways For Declaring A Function?

Jul 30, 2010

is there any real difference between these two function declarations?

function DoSomething(parm) {
//do something here
}[code]...........

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Declaring/Initializing Variables Inside Or Outside A Loop?

Apr 30, 2007

I've always wonder if there is diference when declaring and
initializing a varible inside/outside a loop.

What's a better practice?
Declaring and initializing variables inside a loop routine, like this:

for(var i=0; i<list; i++)
{
var name = list[i];
}

or outside a loop routine, like this:

var i;
var name;

for (i=0; i<list; i++)
{
name = list[i];
}

or are both the same....

As a programmer, i always try to practice good programming. I always
thought that by declaring and initializing the variable inside the
loop, i was creating a new memory space every time instead of just 1
time...

What do you think?

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JS Declaring-Wrong Validation Due To Function With Variable Holding Same Valu?

May 21, 2011

I am doing a Validation for Form "Text input". If the user leaves the input empty, a function is starting to run. If the field is bigger than 1 - so it doesn't get into the function.

The problem is: The first time, the user left the input empty, function ran, and I got the alert - that's OK. Second time, The user added 10 in the AGE input - And again he gets the Alert - But he should not.

Note: Age input value, returns from a different function (calc) to a var called: result.

[Code]...

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JQuery :: Checking Multiple Input Values Against Various Other Hidden Minimum Values

Jul 19, 2011

I have a list of products where they have minimum quantities in a hidden input. Some products have multiple colours, though the same minimum quantity and I'm trying to implement a jQuery check that entries made are at least equal to the minimum.

Blank or '0' entries are fine but if it's below the minimum quantity it should set to the minimum.

HTML:

Is there something obviously wrong with this? It isn't performing the minimum check and I'm really not sure why.

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JQuery :: Get Return Object Not DOM?

Mar 4, 2010

alert($(
"ul li").get(0));

Thisalert show this, literally: [object] This [object] will not accept any DOM methods like addClass, etc

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JQuery :: Return Array From Php?

Jan 20, 2011

I have a problem.I want Internet explorer support to my site but I cant using json so I want return data array format from php. Is there a solution of this problem?

My php array : $myArray=array("caption"=>"number one","value"=>"Jquery");

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JQuery :: Return To Default Value?

Apr 20, 2011

I have this simple code for change combos based on selection.

$("#manufacturer_id").change(function(){
$.ajax({
url: 'index.php?route=catalog/product/getConsignaManufacturer&token=<?php echo $token; ?>&manufacturer_id=' + $('#manufacturer_id').val(),

[Code].....

This works perfectly. Now the mail combo have a option value="0" with title "Please select one" so if not change happen then the second combo never is activated. How when the user select the first option "Please select one" in the main combo (#manufacturer_id) I can disable the second combo?

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Ajax :: JQuery Return Value Always Has A Zero (0)

May 21, 2010

I have researched this error/bug/mistake thoroughly with no success. I must be the only one experiencing it. Also, this takes place on every site I develop with jQuery ajax. It happens regardless of whether I use .get, .post, .ajax etc. Problem: The result returned to my ajax function always has a zero (0) appended to it.

[Code]

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JQuery :: Can't Return To App Upon Exit And Restart?

Mar 23, 2011

When you click on the link to a web site, close the app, then open the app again, it displays the web site instead of the app. How do you get back to the app?

<li><a
href
=

[code]....

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JQuery :: Contains('text') Return Is Always True?

Feb 12, 2011

I have a question concerning :contains(). I use it in the following manner:

if($("div:contains('Built From')", $(itemProps)))
{
//Do stuff.
}

itemProps is DOM Element. It has a a div inside it which class is always something else however that div has either "Built From" or "Builds Into" as a text. Inside itemProps there is no other div with those words. I want to know which of those texts the div within itemProps contains. However this bit of code seems to always return true. Some goes for when I use the text "Builds Into". Even when the text is not in the div.

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