What I want to do is declare an empty array. so i do it like this:
var changedValues = {};
Now i m populating this array dynamically with values, something like this
changedValues[elemName] = elemValue;
This also works fine. BUT, when i do a alert(changedValues.length)....
it gives "UNDEFINED" even though the array is not empty. Saw it through firebug .. Can anyone tell me wht is happening here?
Demonstration code:
The 'array' variable contains strings representing the id's of different elements. If the for loop above were to finish iterating, would all the links in all three elements call the click function (that displays an alert message), or would only the last element ("element3") have the click function? For me, the latter seems to be the case unless if I'm doing something wrong, but I would like clarifications and, if possible, alternative solutions as to how I can achieve the former result.
(the "code" below is pseudo code, just to get the idea across)
Here's what I currently have:
var bill = new array[20];
var sam = new array[20];
var nancy = new array[20];
var Oscar = new array[20];
I'm assigning objects to them (ie Oscar[5] = new objLabel() This seems like a kluge, however. Here's what I'd like (again, pseudo-code)
var Objects = {bill:null; sam:null; nancy:null; Oscar:null};
var theObject = new Array of Objects[20];
// yes: i know that's wrong... and that's the part I'm having trouble with
so that I can do something like:
[Code]....
Just seems to me that keeping a single array of multiple objects is likely to be less error-prone than multiple arrays of single objects... But I don't have the syntax right... or can it be done in JS? If it's doable, would someone be kind enough to show me how to declare and access that example?
I have a php script which calls a javascript function with a parameter. I am having trouble getting this parameter act as an array inside the javascript function:
php:
Code:
<? $array1 = '"apple","orange","banana"';
$array2 = '"corn","bean","beet"';
$arrays = $array1.'///'.$array2;
[Code]..
JS sees fruits and vegs as a string rather then an array, so if I try to output fruits[0]; it gives me the entire string rather then seeing it as an array and giving me the first element.
I am doing a password reset form using Jquery and PHP. If I try to submit an email id it should sent and email and report back the response text as success so that the user knows email has been sent. But I am stuck with JSON submit as I have an empty array to decode at the serverside. I am using minified version of json2.js from the official json.org website
Here is the code.
Code JavaScript:
var formdata = $("#log-box").serializeArray();
formdata = JSON.stringify(formdata);
var notifymsg;
alert(formdata);
$.ajax({
type: "POST",
url: "forgot-pass.php",
contentType: 'application/json',
data: formdata,
success: function(responsedata){
var some = responsedata.split("&");
$.each(some, function(index,value){
//alert("index="+index+"value="+value);
});
},
error: function(o, s, e){
alert("Form not posted
"+e);
}});
formdata alerted gives:
[{"name":"email","value":"ravi.k@gmail.com"},{"name":"acctype","value":"loginaccount"}]
PHP forgot-pass.php
Code PHP:
print_r($_POST);
Gives
Array(
)
How do i declare an empty array?
I need to iterate through a group of arrays and search for a user-chosen word every time.
The problem is i can't declare how many array elements will be needed, such as: new array = (12), because some words inside my arrays, occur more than others.
So i need to decalare an empty array with x number of possible values.
im currently working on a web app which uses heavy javascript. in one
of the functions, a simple array is created using "var admin_types =
new Array();". This array is not empty, it has a length of 0 but
contains one element with the name "clone" and the value
function () { var copy = {}; for (var i in this) { var value = this[i];
try { if (value != null && typeof (value) == "object" && value !=
window && !value.nodeType) { value.clone = Object.clone; copy[i] =
value.clone(); } else { copy[i] = value; } } catch (e) { copy[i] =
value; } } return copy; }
why does this element get created?? The weird thing is that i use a lot
of arrays and this is the only one that has that element.
i tried this in firefox 1.0, ie 5.5 and mozilla 1.7.1 and the element
is in the array for all of them...
I have the following code which will split the given input based on the comma(,) and will store each value in separate address of the same array.[code]...
How can we remove the empty values while displaying the output or how we can remove the spaces from array+
What type of variable is an empty array element? I thought it was undefined, but i noticed that they have different behavior than undefined does:
var r=Array(1);
var s=r.concat([0,"",null,undefined]);
alert (s.toSource()) //==="[, 0, "", null, (void 0)]"
typeof s[0] //==="undefined"
typeof s[4] //==="undefined"
As you can see, 0 and 4 both === undefined. Yet, they don't have the same toSource()...
Is this special type named anything specific? Or more importantly, can it be detected outside of an array as being distinct from undefined? I am thinking this would be the same type as ({}).nonProp ...
I guess the question is actually, "can you tell the difference between uninitialized and undefined"?
Is there a built in method to remove empty array elements?
View 2 Replies View RelatedI'm not an expert with javascript nor am I too familiar with the syntax. What I'm trying to do is store all errors into an array like so:
Code JavaScript:
var errors = new Array();
var example = '';
if (example == '') {
errors[] = 'This example field is empty';
}
What I'm trying to do at the end is display the array if its not empty into a DIV called errors (or something). I know how to do this in PHP but I'm trying to do first validation layer through javascript. So something like this:
Code JavaScript:
<div class="errors">
if (errors != '') {//If the array is not empty
for (keyvar in errors) {
document.write(array[keyvar]);//Display Errors
}
}
</div>
anotherVar should be -1 if there are no matches, but it doesn't seem to work var string = "abadafa"; var matches = string.match(/a/gi); //doesn't work with /z/ for example
var anotherVar = matches.length || -1; The default operator should return the second value if the first is null or false, and according to try { alert(matches.length);
}
catch (e){
alert(e); //alerts null
} it's null.
fyi: http://helephant.com/2008/12/javascript-null-or-default-operator/
I have a understanding problem with this:
var loadData = function(){
$.post('/search.php', { myvar: 12345 }, function(data){
$.each(data, function(key, val) {
// here I have to validate my data I retrieved
if(first condition){
return false;
[Code]...
I worked on a simple image slide-show with javascript, and I assigned a value to a var outside of a function using getElementById() like this:
Code:
window.onload = initLinks;
myImg = new Array("images/img01.jpg","images/img02.jpg","images/img03.jpg","images/img04.jpg");
curPic = 0;[code]..........
is there any real difference between these two function declarations?
function DoSomething(parm) {
//do something here
}[code]...........
I've always wonder if there is diference when declaring and
initializing a varible inside/outside a loop.
What's a better practice?
Declaring and initializing variables inside a loop routine, like this:
for(var i=0; i<list; i++)
{
var name = list[i];
}
or outside a loop routine, like this:
var i;
var name;
for (i=0; i<list; i++)
{
name = list[i];
}
or are both the same....
As a programmer, i always try to practice good programming. I always
thought that by declaring and initializing the variable inside the
loop, i was creating a new memory space every time instead of just 1
time...
What do you think?
I am doing a Validation for Form "Text input". If the user leaves the input empty, a function is starting to run. If the field is bigger than 1 - so it doesn't get into the function.
The problem is: The first time, the user left the input empty, function ran, and I got the alert - that's OK. Second time, The user added 10 in the AGE input - And again he gets the Alert - But he should not.
Note: Age input value, returns from a different function (calc) to a var called: result.
[Code]...
Trying to build a little tool here..
<html>
<body>
Artist ID: <input type=TEXT id=ArtistID name= ArtistID value="Artist ID">[code]....
I'm trying to save the input and pass it into the URLs that are the option values. So Artist ID being 111 would take you to url..../<WHATEVER OPTION YOU CHOSE FROM DROP DOWN>/111
What am I doing wrong/What am I not doing?
The .find() method does not seem to match on input fields by using a class. The ti This problem seems to be only visible on input fields. The following is a demonstration of the issue:
Example at [url]
I am making a call like -
$('#display').load(adnwurl, function(response, status, xhr) {
alert(response);
});
And also tried with -
$.get(adnwurl,
{},
function(data) {[code]...
In both the cases I am getting an empty response instead of expected html response.If I just copy paste this adnwurl in browser, I do get a proper html response. Its not working with ajax call.
adnwurl = "http [url]...site_id=4764&partner_id=70606a913077034c&timeout=5000&version=1.5&language=jsp&format=wap&testing=1&target_params=AGE=>29||DOB=>1981-08-[code]....
The problem is(as stated in the title) that i cannot remove some empty elements, which is the [code]...
View 3 Replies View RelatedI have made a forum thats look like this:
<form action="" method="post" id="contactform">
<div id="name-wrap">
<label for="name" class="req">Namn</label><span>Fyll i ditt för- och efternamn</span>
[Code]....
I'm wondering how to check if load() is empty because if it is, I do not want to show()
$("#orderList").load("OrderListHandler.ashx?action=" + action + "&oid=" + sid +, function()
{
// if nothing came back from the ajax request to .ashx, then I need to hide()
$("#noOrdersContainer").show();
});
I have
$('select#species').change(function()
{
if ($(this).val() == "")
{
[Code]....
I'm attempting to check if the #species combobox is empty, if its empty then alert empty.
That code seems like it should work, but it doesn't. How do I check if the selectbox value is ""?
-Rich
How to turn table A to table B? code...
View 7 Replies View RelatedI have a need to use jquery to insert a row into a table (individual cells within row include images, input box, radio buttons; each with their own attributes). So far i've only been able to append rows to existing rows, or clone an existing row. Is it possible to insert a new row? The table html is already present. I have searched high and low for examples of this to no avail. Here is what the empty table looks like:
<!-- sub table for answer options -->
<table id="white_background" cellpadding="0" border="0">
<tr><td>
<table id="answer_options" cellspacing="1" cellpadding="3" border="0">
[Code].....