Return Php Values (for 'AjaxfileUpload')?

Dec 8, 2011

I am trying to build an interface to upload files and change some of the form (hidden) values depending on the file uploaded, here is where I got so far:

$('#buttonUpload').click(function (){
$.ajaxFileUpload({
url:'doajaxfileupload.php',
secureuri:false,
fileElementId:'fileToUpload',
dataType: 'txt',
[Code]....

My problem is that I want doajaxfileupload.php to return a variable to javascript/change some html form value. The code works as it is for the file upload, I just need to add something for the output, Edit: I just noticed that some previous part of the code is still there: the part that changes the color of the button depending if the file is uploaded or not. Now I want those values to change depending on what file is uploaded.

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HTML:

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Code:

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(Example)

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(Example)

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Code:

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Here my full code:

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You probably don't need the code for the form as it is pretty basic but
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