I'm trying to prevent duplicate entires in my DB for a newsletter submissions form. I'm successfully preventing the duplicate entries, but I haven't been able to revise my jQuery to print the error.I've included the PHP just incase I'm missing something there..
jQuery:
Code:
$('#newsletterForm').validate({
submitHandler: function(form) {[code].....
I have a mySQL that is continuously being added to and I need to make an AJAX function that checks the database periodically and only returns the results that it hasn't seen before.
View 8 Replies View RelatedOkay guys, this might be very simple, but i just cant find the answer.
What i want to do is prevent users from submiting entries that already exist in the database using php. code...
All want is to be sure that if the there is an existing row in name with an entry of 'asdf' (example) then it will echo something like name already exists, but if it doesnt i want it to echo okay. What happens is that it ALWAYS echos okay, in other words it always says there is no row named 'name' with the value of 'asdf'
I have a simple AJAX chat room and it's taking too much local bandwidth when it downloads. What I want to do is call a page with AJAX that checks for new entries in the database and sends a response if there are new ones. But if there's nothing new it just doesn't respond. That way a user won't have to download a response with no new material. Is this okay to do? Am I correct in assuming this will have a positive affect on bandwidth?
View 8 Replies View RelatedI'm loading a list of elements into mydiv with ajax, I want them to be selectable so I call the UI plugin selectable after the list has loaded.
The list building function produces this:
<div id='mydiv'>
<ul id='mylist'>
....
</ul>
[Code].....
The problem is, every time I click the link to reload the list via ajax, I get a duplicate selectable event handler created. Should I be removing the old event handlers before reloading the div ? if so, how?
Everything works, as in selectable still works, and only seems to fire once but I get ever growing memory usage in firefox and an ever growing list of event handlers in the firebug script tab. Eventually firefox starts to crawl and I have to restart the browser.
For a webpage displaying test results I have written jQuery in order to display the points scored as percentage of the maximum, and animated bars that expand and display different colours depending on the result.FF and Webkit display this without any problem, but IE somehow does not like it. First it displays the values as intended, but after clicking away the error message, I'm left with "NaN"..
View 1 Replies View Relatedi have java script below. i am retrieving states from mysql database and list them dropdown menu. oscommerce, mysql and php. this script works well when it is embedded between head tags to each php file in old version. goes to city_get.php and takes the state result from there. but in the new version (no head tags in php file) i saved the script as js file and try to call from template_top.php (which shows the all the java's way), explorer gives error in the below line. i have followed this error from explorer error messages.
[Code]...
I'm trying to get a return of
[
["red","green","blue"]
,["blue","red","green"]
[code]....
Currently, I'm building a website with jQuery. The function below helps me to get content from a database. In the file content_ajax.php there are some functions to handle ajax-requests. JS calls the PHP-function correctly (I've send an email to myself inside that function to check) but the script doesn't return 'succes' and doesn't give me an error...Also, when I put an alert inside the succes and error function, it doesn't popup!
What may be relevant: - site uses mod_rewrite for friendly url's
if it's possible to return an array from my php generated content to ajax's responseText. I tried echoing back the whole array variable but can't seem to fully receive it in javascript.
somewhere in file1.php
<?php
$myArray = array();
$myArray['name'] = "ajax tech";
$myArray['age'] = 20;
[Code]....
I'm attempting to simplify my javascript code when it comes to ajax, but afterwords it only prints 'undefined' to the screen rather than what I want it to print.
I want to be able to put something like this on my main page onclick="document.getElementById('output').innerHTML = print_output();" where print_output() is the ajax function. This way I don't have to use a function to assign values directly to innerHTML and I don't have to muck about with a js file whenever I want to change my page layout.
To do this, I created a recursive function:
function print_output(return_value) {
if a value has been passed to the function, simply return it
if(return_value || return_value == 0) {
return return_value;
}
[Code].....
but like I said, it prints 'undefined' out to the screen. Why isn't this printing the contents that it receives from 'index.php' like it's supposed to?
I'm having trouble placing some data returned by an ajax function in the page where I want it.
I've included the relevant html and the javascript function below. There is some php code included which works but is not relevant to this question. The first ajax part of the function works. I have tested it with positive results in another context.
The part starting with "var x . . ." is the part that is not working. This part is supposed to generate the following html: Code:
With ajax request method
How do i return many lines of data?
The page eventos_search.php is supose to get more then 1 line of records
This process i dont know how it works.
i happen to chase my fortunes in development as a newcomer. Scenario,// using jqm-rc2, sample registration - ajax callback scenario
1. Say formtoregister.phpcalls a studentsregister.php // Ajax/json and POST
2. Thisstudentsregister.phpdoes this 2.1 validates POST data, does db work and 2.2 sends back to formtoregister.php following messages //on success echo json_encode($promoinfo);// json format, see below the echoed content echo "<p>Welcome $user </p>" problem,is plain format text is printed Message is: {promo code: JsonNAjax}<p>Welcome Beginner </p>
[Code]...
I am running the scripts below which should return a string containing a URL.So far, it cannot find the form contents in Firefox, but displays the non-dynamic data such as ?Location=. It won't work at all in IE.
View 1 Replies View RelatedI can not for the life of me get an ajax example/tutorial to work. I have tried dozens including prototype library and JQuery.
Here is my latest attempt:
As you can see I am trying to alert the variable teamH but I keep getting an undefined in the alert. I also tried a static drop down and I received the same undefined alert.
How I get that variable to contain my drop down choice?
I'm making a script that requires cross-domain scripting to get the statuscode of other files. I'm currently using a small PHP script to relay the files from the remote server onto mine. If I want to get the files directly using AJAX, it is not allowed for obvious reasons. I don't want the actual files, I only want to get the status code of that file, and it is going to be either a 404 or a 301. I would've assumed that as the AJAX call is never attempted, the statusCode will be 0, and this is what the actual call variable returns.
However, in Firebug it shows the statuscode next to the request (404 or 301), even if, the call has never been made. Why is the statuscode appearing in Firebug but not in the statuscode variable?
I'm doing some jquery and ajax work with C# asp.net MVC on the server.
I have this JS function:
function DeleteListing(receiptItemId){
$.ajax({
url: "DeleteListing",
type: "POST",
[Code].....
What I'm wondering is there ways to return values from DeleteListing on the server to the success function?
I am not a javascript programmer, however are checking as I would like to investigate if I can do following:
I have a calculator that check the price for the properties for a choosen date, I use php and mysql to get the result and the result are displayed on the same page refreshing the page using this in the form: action="<?=$_SERVER['SCRIPT_NAME']?>#formdestination">
I know you can print the result using ajax or other javascripts to do this without having to refresh the page and jump to the result.
Was doing a research and I quckly found this link:[URL]..It does not look so complicated, however as I can see the form is done in javascript so I suppose if you have javascript disabled you cant use the calculator.
I would like to have a non javascript solution with the way I am doing it to work if javascript is disabled. An exampel of the calculator can be viewed on this link for exampel:[URL]..
i want to retrieve data from mysql database using ajax and php. my code is below which does not work
here is index.html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
[Code].....
The below coding is the javascript coding in which i have used AJAX coding also.its only pagenavigation coding.
function change(which)
{
if(which=="page1")
{
document.getElementById(which).style.borderBottomColor="white";
document.getElementById("page2").style.borderBottomColor="#778";
document.getElementById("page3").style.borderBottomColor="#778";
document.getElementById("page4").style.borderBottomColor="#778";
[Code]...
I have a question about ajax, php si mysql.. In mysql i have a table playlists and here is the code for php:
<?php
$playlist_result = mysql_query("SELECT *, COUNT(playlist_id) AS NumOccurrences FROM playlists WHERE created_by=$user_id GROUP BY playlist_id HAVING ( COUNT(playlist_id) > 0 ) ORDER BY date DESC");
$playlist_result_count=mysql_num_rows($playlist_result);
$i=0;
if($playlist_result_count > 0)
{
[Code]...
It`s working fine but in mysql is inserted the id of the last created playlist, not the one that I clicked. What am I doing wrong?
I am trying to use AJAX to pull back mysql table information. I tried to alter an example I found (w3 schools) where they showed how use a selection table to pull a specific line out of a mysql table, using the "q" (not really sure if the "q" character is important or not). xmlhttp.open("GET","xxxxxxx.php?q="+str,true) I follow what they were doing there, but I want to pull the entire table back not just specific lines. (So I got rid of the Q)
Here is a snipit of HTML. The showdata function is part of the testpull.js code. You click the button and it should run the javascript to pull back the entire table and place it in the "placedata" div section.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html lang="en" xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
[Code]....
[URL] Refer to the link, using the sample, I'm able to use php ajax to populate 1 text box which I've already pre-define (not using "echo '<input type='text'..") -- the info came from a table
e.g.
Search: [jo ]
Name: [John doe]
sql
---
select name from customer where name like '%jo%';
[Code]...
Ajax and jQuery is something I'm new to, but PHP, Javascript, and MySQL I'm pretty well seasoned with.For starters, I want to create a simple form where there are these fields:Name (text field)E-mail (text feld)Zip Code (text field)Cell Phone Number (text field)Phone Carrier (dropdown menu)Thing is, I want to check the database to see if an e-mail address has already been entered. I'd like for that to happen after they enter the email address and tab or click out of the e-mail text field. For instance, after they enter an e-mail address and tab to the Zip Code field, the script queries the database to see if that e-mail exists already. If it does, it notifies the user and greys out the submit button. If not, they're allowed to finish filling the form out and submit. It'll be a huge time saver if this Ajax script is in place.
View 1 Replies View RelatedI am attempting to create a profile page with PHP utilizing AJAX technologies as well. I need profile data to auto-refresh on the page when a change is made in the database but every 15-30 seconds intervals are fine too. I would really like to use AJAX/PHP for this because I think it will be good for me to know and learn.
I have checked the internet for this and all of the examples show a form select/combobox where you select a "User" and then it populates the information automatically in a div below.
But... I need AJAX or PHP to READ THE VARIABLE FROM THE URL instead of a form(Combobox) and ultimately refresh the data on the page with the results from the DB query in the php file.