Ajax :: Returning A Value Directly From A Function?
Dec 1, 2009
I'm attempting to simplify my javascript code when it comes to ajax, but afterwords it only prints 'undefined' to the screen rather than what I want it to print.
I want to be able to put something like this on my main page onclick="document.getElementById('output').innerHTML = print_output();" where print_output() is the ajax function. This way I don't have to use a function to assign values directly to innerHTML and I don't have to muck about with a js file whenever I want to change my page layout.
To do this, I created a recursive function:
function print_output(return_value) {
if a value has been passed to the function, simply return it
if(return_value || return_value == 0) {
return return_value;
}
[Code].....
but like I said, it prints 'undefined' out to the screen. Why isn't this printing the contents that it receives from 'index.php' like it's supposed to?
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Mar 11, 2010
I am currently using this template by flowplayer.org: [URL]. The functionality I need is the ability to link directly to a specific ajax tab (i.e. Seagram Building, Barcelona Pavilion, New National Gallery). As of now they are just line items without any anchor tags.
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Jan 11, 2011
I have a requirement that my javascript function can be called directly from the other website. I know how to add the external javascript and then call respective function
<input type="button" value="Testing direct function call of javascript" onclick="CALL THE EXTERNAL JAVASCRIPT(which will call main function in it" />
how can I create such javascript
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Jul 11, 2010
I have a form.On the form I have a drop down box that allows the user to select a data set to work with (A or B). The table loads just fine and all is right with the world. No problems there.What I need is for the user to be able to edit the data set and have those changes written directly back to the mySQL database. They also need the option of deleting a record entirely.I know how to do all the database queries, updates, etc. I just don't know how to write the ajax forms to accomplish this.
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Jun 10, 2009
Currently, I'm building a website with jQuery. The function below helps me to get content from a database. In the file content_ajax.php there are some functions to handle ajax-requests. JS calls the PHP-function correctly (I've send an email to myself inside that function to check) but the script doesn't return 'succes' and doesn't give me an error...Also, when I put an alert inside the succes and error function, it doesn't popup!
What may be relevant: - site uses mod_rewrite for friendly url's
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Nov 28, 2007
if it's possible to return an array from my php generated content to ajax's responseText. I tried echoing back the whole array variable but can't seem to fully receive it in javascript.
somewhere in file1.php
<?php
$myArray = array();
$myArray['name'] = "ajax tech";
$myArray['age'] = 20;
[Code]....
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Aug 18, 2007
I'm having trouble placing some data returned by an ajax function in the page where I want it.
I've included the relevant html and the javascript function below. There is some php code included which works but is not relevant to this question. The first ajax part of the function works. I have tested it with positive results in another context.
The part starting with "var x . . ." is the part that is not working. This part is supposed to generate the following html: Code:
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Jun 7, 2010
I am trying to write a function that is being invoked when some one clicks the submit button on the form.<form name="sectionA" action="optionpage.cfm" onSubmit="return abc()">I have three tables with initials textboxes. I want to check if they are empty and return false(stay on the same page), else go to action page.Here is what I am doing, I Created three functions tableA(), tableB(),tableC() call them from function abc(). These functions tableA(), tableB(), tableC() return false if one of the field is empty and stop furthur processing and remain in the same page. If none(errors), then go the other page.i.e if table B has empty fields, page should stop furthur processing and remain in the same page.Here is how I am doing it Can somebody please point out what I am doing wrong here.Even when there is empty field, the code moves me to the actionPage.
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Aug 3, 2011
With ajax request method
How do i return many lines of data?
The page eventos_search.php is supose to get more then 1 line of records
This process i dont know how it works.
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Dec 22, 2011
i happen to chase my fortunes in development as a newcomer. Scenario,// using jqm-rc2, sample registration - ajax callback scenario
1. Say formtoregister.phpcalls a studentsregister.php // Ajax/json and POST
2. Thisstudentsregister.phpdoes this 2.1 validates POST data, does db work and 2.2 sends back to formtoregister.php following messages //on success echo json_encode($promoinfo);// json format, see below the echoed content echo "<p>Welcome $user </p>" problem,is plain format text is printed Message is: {promo code: JsonNAjax}<p>Welcome Beginner </p>
[Code]...
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May 5, 2010
I am running the scripts below which should return a string containing a URL.So far, it cannot find the form contents in Firefox, but displays the non-dynamic data such as ?Location=. It won't work at all in IE.
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Sep 12, 2011
I can not for the life of me get an ajax example/tutorial to work. I have tried dozens including prototype library and JQuery.
Here is my latest attempt:
As you can see I am trying to alert the variable teamH but I keep getting an undefined in the alert. I also tried a static drop down and I received the same undefined alert.
How I get that variable to contain my drop down choice?
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Mar 27, 2009
The following code is supposed to return a variable containing text, currently the code posts the data but returns an "undefined" variable. Can someone tell me what's wrong? code...
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Mar 27, 2009
I would like to document.write the status value using the return function but I can't get it to work.
The output should be Markers On or Markers Off.
<html>
<head>
<script type="text/javascript">
[Code].....
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May 27, 2010
I'm making a script that requires cross-domain scripting to get the statuscode of other files. I'm currently using a small PHP script to relay the files from the remote server onto mine. If I want to get the files directly using AJAX, it is not allowed for obvious reasons. I don't want the actual files, I only want to get the status code of that file, and it is going to be either a 404 or a 301. I would've assumed that as the AJAX call is never attempted, the statusCode will be 0, and this is what the actual call variable returns.
However, in Firebug it shows the statuscode next to the request (404 or 301), even if, the call has never been made. Why is the statuscode appearing in Firebug but not in the statuscode variable?
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May 27, 2011
I'm doing some jquery and ajax work with C# asp.net MVC on the server.
I have this JS function:
function DeleteListing(receiptItemId){
$.ajax({
url: "DeleteListing",
type: "POST",
[Code].....
What I'm wondering is there ways to return values from DeleteListing on the server to the success function?
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Feb 18, 2009
Why is my function returning the wrong value??
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Aug 13, 2011
So for whatever reason the convertToArray function in the following code returns false if the argument is more than 1 character long. If it's 1 character long it just returns the character as an array with only one value.What I'm trying to do is take a string of numbers, plus signs, and minus signs and convert it to an array.
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Jun 5, 2011
I'm trying to prevent duplicate entires in my DB for a newsletter submissions form. I'm successfully preventing the duplicate entries, but I haven't been able to revise my jQuery to print the error.I've included the PHP just incase I'm missing something there..
jQuery:
Code:
$('#newsletterForm').validate({
submitHandler: function(form) {[code].....
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Nov 3, 2005
I have a little problem in one of my functions, I would like to pass in a form field name and set the value to something that is passed in. here is my code:
function pickitem(id,type){
opener.document.getElementById("form").type.value = id;
window.close()
}
so i'm passing in an id and a formfield e.g. txtName The problem is with the type.value - i haven't touched javascript for ages so i'm really rusty!!
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Mar 9, 2009
The code is below but basically I have two global variables, then I have a function and then a function within that, I am simply trying to update these global variables from within the nested function so i can then go on and use them in another function! this sounds like quite a straight forward request to me, but maybe it can not be done? When I do an alert on the variables (after I have apparently updated their values) I get 'undefined'!
Code JavaScript:
var resultLatB;
var resultLngB;
function getLatLngFromTown(town, callbackFunction) {
var localSearchB = new GlocalSearch();
localSearchB.setSearchCompleteCallback(null,
function() {
if (localSearchB.results[0]){
resultLatB = localSearchB.results[0].lat;
resultLngB = localSearchB.results[0].lng;
pointA = resultLatB;
pointB = resultLngB;
//THIS WORKS
alert("Test 1 = " + resultLatB);
alert("Test 1 = " + resultLngB);
}});
localSearchB.execute(town + ", UK");
//DOESN'T WORK... SHOULD IT?
alert("Test 2 = " + resultLatB);
alert("Test 2 = " + resultLngB);
}
getLatLngFromTown("oxfordshire",null);
//I WANT THIS TO WORK!
alert("Test 3 = " + resultLatB);
alert("Test 3 = " + resultLngB);
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Sep 26, 2009
Here is a clip of code from a script project im working on. Now my document.getElementsByTagName is returning a "undefined" value.
<a href="[URL]" style="text-decoration: none; color: #EDDBAF; font-size: 16px;">
<center style="margin-left: 10px; margin-right: 10px;">
<font style="color: #EDDBAF; font-size: 16px;" id="title"></font>
</center></a>
<li id="name"><a http="[URL]" style="color: blue;">John Doe</a></li>
<script type="text/javascript">
var pname = document.getElementById('name').getElementsByTagName('a');
Now if I remove the ".getElementsByTagName('a')" it will actually work, but it also includes the <a> tag thats within the <li> tag, which I don't want.
document.getElementById('title').innerHTML=pname.innerHTML;
</script>
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Dec 4, 2006
I have several functions with code along the lines of:
var xmlDoc = requestXML("ajax.asp?SP=SelectRelatedTags&tag=" +
array[i]);
The requestXML() function includes the code:
var xmlDoc = null;
http_request.onreadystatechange = function() {
if (http_request.readyState == 4) {
if (http_request.status == 200) {
xmlDoc = http_request.responseXML;
} else {
alert('There was a problem with the request.' +
http_request.status);
}}};
http_request.open('GET', url, true);
http_request.send(null);
return xmlDoc;
However, the last line (the return) executes before the readyState
reaches 4. How do I return the xmlDoc to the functions only once the
xmlDoc has been assigned? I tried putting the return statement in a
while loop with the condition that the readyState must = 4 - this
worked, but makes the browser popup a message saying the script is
slowing down the system.
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Jun 3, 2010
I know this is a simple question with a simple answer, but I can't seem to wrap my brain around it.Sorry for the infantile nature of this post. Anyhow, I am making an AJAX call via JQuery and need the function to return a value from a calling function, like so:
[Code]...
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May 26, 2010
I have a weird bug that's occuring in pretty much all the browsers. If I close the tab, and then hit Ctrl -> Shift -> T to bring it back the width() method returns 0 on an appended image instead of what the image actually is. Hitting refresh on the tab removes this bug and everything works fine. I will also say that trying
.css('width') and
document.getElementById('divShadowLeft');
Both also return 0 for this bug.
I can't show all the code for security reasons, but I'll just outright ask.. what are the reasons that width() would return 0 on an image? I've checked to make sure that it was visible (both display and visibility properties), and I checked the length of the property to ensure it was there. I just can't figure out why width() is returning 0.
Here's a code snippet:
$(this).append('<img src="'+defaults["imagePath"]+defaults["imageLeft"]+'" alt="" id="'+defaults["imageClass"]+'Left" class="'+defaults["imageClass"]+'" style="" />');
alert('Length: '+$('#divShadowLeft').length+' | Width: '+$('#divShadowLeft').width()+' | Visible: '+$('#divShadowLeft').css('visibility'));
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Apr 23, 2010
I have a setup where I have a function, calling a function, calling a function. All functions do what they're supposed to do, but they don't return to the first function when all is done, so it doesn't display an alert that it's supposed to.
For those that don't want to look through tons of code and think they might know what I'm doing wrong, here's the "coles notes" version. code...
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