JQuery :: $.ajax Not Returning Data ?
Jun 10, 2009
Currently, I'm building a website with jQuery. The function below helps me to get content from a database. In the file content_ajax.php there are some functions to handle ajax-requests. JS calls the PHP-function correctly (I've send an email to myself inside that function to check) but the script doesn't return 'succes' and doesn't give me an error...Also, when I put an alert inside the succes and error function, it doesn't popup!
What may be relevant: - site uses mod_rewrite for friendly url's
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Aug 18, 2007
I'm having trouble placing some data returned by an ajax function in the page where I want it.
I've included the relevant html and the javascript function below. There is some php code included which works but is not relevant to this question. The first ajax part of the function works. I have tested it with positive results in another context.
The part starting with "var x . . ." is the part that is not working. This part is supposed to generate the following html: Code:
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Dec 21, 2009
I have this basic code following and its not returning anything at all. Even the alert is not alerting. I have checked and the select is sending the value fine But nothing happens on return. What i am missing?
$(function() {
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Apr 6, 2011
below are my code
$.getJSON("http://mydomain.com/phptest.php?jsoncallback=?",function(data)
{
alert(data.a);
});
phptest.php echos out the following
{"a":"hello world"}
Yet, when i made the json calls(cross domain), it just return me nothing. However, under the same domain, I got the pop-up alert and return me the relevant data. But getJSON is suppose to be feasible across all domains irrespective of the same-origin policy.
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Aug 3, 2011
With ajax request method
How do i return many lines of data?
The page eventos_search.php is supose to get more then 1 line of records
This process i dont know how it works.
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Dec 22, 2011
i happen to chase my fortunes in development as a newcomer. Scenario,// using jqm-rc2, sample registration - ajax callback scenario
1. Say formtoregister.phpcalls a studentsregister.php // Ajax/json and POST
2. Thisstudentsregister.phpdoes this 2.1 validates POST data, does db work and 2.2 sends back to formtoregister.php following messages //on success echo json_encode($promoinfo);// json format, see below the echoed content echo "<p>Welcome $user </p>" problem,is plain format text is printed Message is: {promo code: JsonNAjax}<p>Welcome Beginner </p>
[Code]...
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May 27, 2011
I'm doing some jquery and ajax work with C# asp.net MVC on the server.
I have this JS function:
function DeleteListing(receiptItemId){
$.ajax({
url: "DeleteListing",
type: "POST",
[Code].....
What I'm wondering is there ways to return values from DeleteListing on the server to the success function?
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Mar 9, 2011
I have been trying to get the feed from this url: [url]
But it keeps returning "data.responseData is null in the firebug console"
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Jun 27, 2011
I am using .ajax() to access cross-domain data using JSONP. Because I need to be able to cache the data I want to use a static name for thejsonpCallback function, so I have set the jsonpCallback option in the .ajax() request. However that appears to requires a global function whereas the auto generated function didn't (well maybe it did but that was all hidden from me).
I definitely need to be able to cache the results. Ideally I wouldn't have a global function handling the data. Is there another way to do this? If not what is the best practice way to go about using a global function these days and how do I provide it with the context of the object/module it was called from - which is where the data is needed?
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Nov 28, 2007
if it's possible to return an array from my php generated content to ajax's responseText. I tried echoing back the whole array variable but can't seem to fully receive it in javascript.
somewhere in file1.php
<?php
$myArray = array();
$myArray['name'] = "ajax tech";
$myArray['age'] = 20;
[Code]....
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Dec 1, 2009
I'm attempting to simplify my javascript code when it comes to ajax, but afterwords it only prints 'undefined' to the screen rather than what I want it to print.
I want to be able to put something like this on my main page onclick="document.getElementById('output').innerHTML = print_output();" where print_output() is the ajax function. This way I don't have to use a function to assign values directly to innerHTML and I don't have to muck about with a js file whenever I want to change my page layout.
To do this, I created a recursive function:
function print_output(return_value) {
if a value has been passed to the function, simply return it
if(return_value || return_value == 0) {
return return_value;
}
[Code].....
but like I said, it prints 'undefined' out to the screen. Why isn't this printing the contents that it receives from 'index.php' like it's supposed to?
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Jul 13, 2009
I am still new to jQuery and I am trying to figure something out. I have this code:
[Code]...
This is working fine on itself. What is does is when I click a link it loads data into the following div. When done loading it slides out. But I want to change the appearance of the slide. I have tried to do that like this: $(this).show("slide", { direction: "down" }, 1000); But this doesn't work. When I check firebug it says the following: o.easing[this.options.easing || (o.easing.swing ? "swing" : "linear")] is not a function
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May 5, 2010
I am running the scripts below which should return a string containing a URL.So far, it cannot find the form contents in Firefox, but displays the non-dynamic data such as ?Location=. It won't work at all in IE.
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Sep 12, 2011
I can not for the life of me get an ajax example/tutorial to work. I have tried dozens including prototype library and JQuery.
Here is my latest attempt:
As you can see I am trying to alert the variable teamH but I keep getting an undefined in the alert. I also tried a static drop down and I received the same undefined alert.
How I get that variable to contain my drop down choice?
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May 27, 2010
I'm making a script that requires cross-domain scripting to get the statuscode of other files. I'm currently using a small PHP script to relay the files from the remote server onto mine. If I want to get the files directly using AJAX, it is not allowed for obvious reasons. I don't want the actual files, I only want to get the status code of that file, and it is going to be either a 404 or a 301. I would've assumed that as the AJAX call is never attempted, the statusCode will be 0, and this is what the actual call variable returns.
However, in Firebug it shows the statuscode next to the request (404 or 301), even if, the call has never been made. Why is the statuscode appearing in Firebug but not in the statuscode variable?
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Jun 5, 2011
I'm trying to prevent duplicate entires in my DB for a newsletter submissions form. I'm successfully preventing the duplicate entries, but I haven't been able to revise my jQuery to print the error.I've included the PHP just incase I'm missing something there..
jQuery:
Code:
$('#newsletterForm').validate({
submitHandler: function(form) {[code].....
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May 31, 2010
i have a series of <select> fields. The first one, via ajax(), generates a 2nd one, based on the first ones' data with the .change() method. there is then a 3rd <select> - who's data will depend on choice of the second one although step 1 works, and i can generate the 2nd one, i still can't generate the 3rd one.
when i test the script on its own, both the 2nd and 3rd <select> fields are fine - but not via the ajax, which leads me to believe that the .change() from the 2nd one, isnt triggering the ajax call - its not being picked up (even the 'hello' alert isnt working).
[Code]...
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Jul 30, 2009
I have a few input and textarea fields and when the submit button is pressed, I use $.ajax to send the data to a PHP script, which in turn, simply prints the data, which in turn is displayed in an alert msg box back in my callback. (The script will eventually load the data into a database but for simplification this is all it does for now).
The only problem, is that the $.ajax encodes/escapes special characters automatically and I can't figure out how to decode/unescape them to make them usable again. Here is the javascript (I simplified it to make it easy to understand):
$.ajax(
Here is my php ajax script (super simple)
So anyways, everything appears to work fine. I enter some info into 'myTextArea', and press submit. The script sends it to the PHP script, which it turn returns the same value and the javascript puts it in a message box.
So the problem specifically is if I send special characters like any of the quotes ' " (single or double quotes). Lets say my text area had this text in it: It's My "Birthday"
$.ajax sends the following data: It's My "Birthday"
So how do I unescape this? Ya, I could simply replace all backslashes, but I assume there are other characters it may escape in special ways I'm not sure about. What is the proper way to do it?
The only possible way I could figure out to do this was to use escape($('#myTextArea').val())
So the data gets sent as: It%27s%20My%20%22Birthday%22
And then use the PHP command "urldecode" on the other end. It turns out correct that way. However, that doesn't seem like the proper way to do it. Javascript 'escape' command was meant for escaping characters for sending GET variables and for sending formatted URLs. Not for text and input forms. Is there a better/more proper way?
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Mar 3, 2011
I have the following piece of code:
$.ajax({
data: someData,
url: submissionUrl,
[code]....
where someData is a vanilla object of key/value pairs, submissionUrl is a valid URL and ajaxSuccess/ajaxError are both functions.Using jQuery 1.5.1, the GET request is delivered to the server without the data. Using jQuery 1.4.4, the request contains the data.Has something changed in the way I should be assigning data to an ajax request in 1.5.1? The docs don't seem to suggest I'm doing anything incorrectly.
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Dec 21, 2010
I've got an ajax call that runs a password verification. The username/password work fine but I can't get the php to send data to to the AJAX, instead it just echoe's the result in an alert box code...
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Jul 8, 2010
$.ajax({
So I'm loading the div#my_events by prepend(data) where "data" is another well styled div. Is there anyway to animate this returned data. Unfortunately I can't just specify a unique ID on the incoming data. So I was wondering how else I might be able to address this data I'm returning.
It is basically a topic list, with a modal that sends jquery to add a topic to the database, and returns the topic from the database, hides the modal, and displays the last added topic at the top of the topic list. Now I'd like it to do something slightly fancy like animate the color of the background to bring the user's attention to it.
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Nov 19, 2010
How do you assign .hover() to data received from an Ajax call? I have a post returning and I wanted to change the bgcolor of the containing div.
Posts.aspx
<div class="postContainerOut">
<div class="postItem">Column 1</div>
<div class="postItem">Column 2</div>
[Code]....
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Jul 12, 2009
I would like to send my form data to a php file but not to get any response. I want to send an ID so that PHP can do MySQL search and generate a PDF file. Problem seems to be that PHP is responding something back to HTML and that is messing my code. So I just want to send the data and run the scripit in PHP so that nothing is returned back to HTML.
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Sep 30, 2010
I really don't understand why I am getting this error (parsererror TypeError: data is null [object XMLHttpRequest]) after making the following AJAX request:
var base_url = $('span#base_url').text();
var model_url = "index.php/status/get_xml/"
$.ajax({
type: "POST",
[Code].....
So I am wondering why the .ajax function has an error, and yet the XML is being returned?
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Feb 27, 2010
I'm experiencing a weird problem when trying to do a $.ajax call. When I pass 5 variables, with either GET or POST, the script runs as I would like. However, when I use 6 or more variables, the script does not run. Does anyone know why this is?
Relevant code (stops1-5 are defined as JS variables earlier in my script, and the alerts are for testing)
$(".barcrawl-stop-id").each(function(){
alert("running ajax function");
$.ajax({
url: "/handlers/ajax/barcrawl_reorder.php",
[Code]....
So, the way it is now, it works fine (I get the first alert for each instance of .barcrawl-stop-id, and get an alert at the end with the returned data). However, when I add another variable to the data, like stop4: stop4, the script does not run (all I see is one alert with "running ajax function").
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Jun 1, 2010
I am creating a dialog using jQuery, and want to populate it with dynamic data. The data in question is properly formatted XML (parsed using jQuery). The call I make looks something like this:
function getXML() {
var $link = $(this);
var $dialog = $('<div></div>')
.load('xml_results_formatted_jquery.php' + ' #dialogcontent')
[Code]....
If I preview the xml_results_formatted_jquery.php file, I see the data so I know the webservice is being queried correctly. However, when I call my function above, the dialog box created has no text in it (apart from the text already present in the dialogcontent DIV). The bit that shows the results of the XML parse is empty.
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