how to check if a user didn't leave the site.Ofcourse you can use the Onunload() or Beforeunonload() function.But some browsers like Opera and Safari and who know what other browsers don't support it. And I don't want to have false information about users still being there while they left.Is there any other alternative? Like expecting server side each X seconds a AJAX request from the user?If the user doesn't send a request, the user has left.
I want to change a db record when the user leave the website. I have this PHP script: <?php require_once("../config.inc.php"); if (isset($_POST["user"]) && isset($_POST["ip_address"])){ $query = 'UPDATE users SET logged = 0 WHEREuser= "' . $_POST["user"] . '" AND ip_address = "' . $_POST["ip_address"] . '" AND confirmed = 1;'; mysql_query($query, DB_LINK); } ?>
And this jQuery script: // script da includere in tutti i file delle pagine per l'utente loggato // cambia lo stato dell'utente da loggato a non-loggato quando viene chiusa la finestra del browser $(window).unload(function(){ $.ajax(AJAX_PATH + "logout.php", {type: "POST", data: "user=" + escape(USER) + "&ip_address=" + escape(IP_ADDRESS), success: function(){alert("Arrivederci!"); return true;}}); }); but it doesn't seem to work.
what i want to do is i need to make all clients to go through my custom .php page when they are trying to leave from my web page.this is to develop a billing system for internet access.i need to capture there time spent on internet.i need to direct them to my web page all the time they enter an url in address bar.each and every time they try to go to a new site by entering url in the address bar they need to go through my .php page.is that possible using javascript?
I'm new to javascript and was wondering if there was a way to do a 'time check' on my website?I would like it so that if the time is between Midnight and 6AM the user has access to the page. Any other time outside of this range gets a picture displayed or a pop-up message and access is restricted.
You know how the get time functions pulls info from the users computer? Is there a way i can get that same information from a web site or a clock on the the same web site?
Imagine a wife has signed on to a web site in a browser tab. She does not sign off and walks away to do something else. Her husband sits at the computer and seeing her signed on, opens a new tab and tries to sign on to the same site. I need to automatically sign the wife off when this happens so as to avoid confusion later regarding which session is active.
Im needing a script that when a user clicks the "X" (closing the browser) or abandons my site a new small pop up window will appear..
The new small pop up window will ask "Why are you abandoning my site? Did you have any questions .. please let us know.." and then the user has the option to answer it or not.... then submit message or totally close the new window and main window..
I know the "window.closed" is the key but I dont know how to use it .. I checked on the internet but no information nor samples of it...
I am looking for the script to resize my website pages according to user's screen size. The size of the table in the template is 1008 * 576 pixels and users with small screen are not able to see the whole page, they have to scroll horizontally. Is there anything possible without modifying my current template?
I'm new to javascript and I have a button in an interface for an app. It's like drag and drop and i want this button to link you to a certain website searching for what the user types in the searchField1 box. The button is button16. Such as you type dogs into the text box and you click the google button among other search engines and it will redirect you to a google search doing a search for dogs. But how do I make this button search google and search for whats in searchField1. I would really appreciate the help. Im looking everywhere to learn this but just cant find it. If you could tell me how or send me a link to a tutorial code...
Not sure if I posted this in the right area since its a Javascript/PHP related problem.I have no clue how to check if a user didn't leave the site.Ofcourse you can use the Onunload() or Beforeunonload() function.But some browsers like Opera and Safari and who know what other browsers don't support it.Is there any other alternative?Like expecting server side each X seconds a AJAX request from the user?If the user doesn't send a request, the user has left.
i installed a shout box for my users, its integrated by using session username. but what i want to do is have a username list under the shoutbox that shows which members (usernames) have the box open. that way the other members can see someone is out there to see their message.. one alternative would be to just have the shoutbox auto open (which i need to learn how to do) as soon as they sign on to the site, but what if they close it right away i still have the same issue (they cant see the message that someone is sending them) here is how i open the window now, they have to click on the link.
Is there a method to check if a user refreshed a page?
I'm designing an online psychological experiment and I want to see if the user refreshed a page (to see if he was trying to see an image that he was supposed to see only once).
i am using netbean to develop a registration form.As this i want to know what is the coding to check input of text, integer, email , so i can restrict what they input..
I need to find a way of modifying this function so it only initiates a request if there is a period of say 2 seconds of inactivity. The user inputs some text, and if they stop typing for 2 seconds, it should then fire off the request. Can someone tell me how i can check for inactivity in the #inputString field? This must involve some kind of timer, but how should it be structured?the lookup function sends the current value of inputstring to another function which posts it to the server side file which then returns the results in a box.
<?php if($_SESSION['id']) echo '<h1>Hello, '.$_SESSION['usr'].'! You are registered and logged in!</h1>'; else echo '<h1>Please, <a href="demo.php">login</a> and come back later!</h1>'; echo 'Should i find a new login' ?>
im trying to use this as a check to see if someone is logged in
I currently run a website similar to digg, where users can vote on a story. What I have been using so far to create the vote buttons, are just simply links that insert a vote into a database. And if a user tries to vote again on the same story, it attempts to insert the vote into the database, (im using MySQL btw), but when it cannot, they are redirected to a page where it tells them they have already voted on the story.
Now I thinking there has to be a better way to do this, and that's when digg came to mind. Can someone please point me in the direction of a javascript tutorial/wiki etc. on creating javascript buttons that interact with a mysql database AND remember that you have voted.
As this forum has been so helpful before, this time it's a JS question:I have a list of checkboxes from which the user can select 1 or more to check and perform an action upon.Thus, all checkboxes have the same "name" (in ASP code, since it's DB-related):
response.write "<input type=checkbox name=""FieldName"" value="&obj("OrderID").value&">" I call JS using a button: <img src="images/TrashBin.png" border=0 onclick="Delete(document.FormName.FieldName)">
I'm trying to figure out with Java Script how I would have Java Script check and see if a check box is or not empty. The goal is to only allow the user to have one box checked at any time in a form. That means, if they click on another one and there is already one checked, it would uncheck the one that was checked and make the one that the person checked on next checked.
I am trying to allow a user to easily uncheck/check all checkboxes in a form by checking or unchecking a checkbox. The checkboxes would be in a form like so: <form action="" method="post"> <input type="checkbox" name="checked[]" value="1"> <input type="checkbox" name="checked[]" value="2"> <input type="checkbox" name="checked[]" value="3"> <input type="checkbox" name="checked[]" value="4"> </form>
I use an event handler to call a function: <input type="checkbox" name="checkall" onchange="checkall('checked[]', this.checked)">
And here is the function: function checkall(box_name, current_state) { all = document.getElementsByName(box_name); action = (current_state == "checked") ? "false" : "true"; for (i = 0; i < all.length; i++) { all[i].checked=action; }}
The event handler should pass the name of the checkboxes and whether the "check all" checkbox is currently checked or not to the checkall() function. Nothing happens when I check/uncheck the "check all" function.
I would like to disable a check box depending on whether 1 of 3 radio buttons is chosen by the user. As I am a js noob, I don't have any beginning code to start with.
