Is there a method to check if a user refreshed a page?
I'm designing an online psychological experiment and I want to see if the user refreshed a page (to see if he was trying to see an image that he was supposed to see only once).
I need to refresh a div which contains an ad while the rest of the page stays the same. I think I'm pretty close by reading the previous posts on this site, but one odd thing is tripping me up and I can't figure out why. When I call my function to refresh the div, it replaces everything on the page instead of just swapping out the div. Code:
View 6 Replies View RelatedI ma having an issue with a JavaScript slider. If you look at this page, at times the slider does not work and the user is having to refresh their page before it works. It's the same in Firefox and IE.[url]...
View 10 Replies View RelatedI'm new to javascript and im trying to add a close button function to my certain pages of my site. I use this code:
<a href='javascript:window.close();'>Close Window</a>
to create a hyperlink which closes the window. However with pages which
display data retrieved from a database using PHP i use a form to submit
a search on the page which displays results. At the bottom of the page
is the close window link, however it fails to work once a form has been
submitted on the page. It only works when the page first loads.
Any ideas guys on how i can get a close window option that works on my
results page after submitting a search?
I am very new to javascript so I'm sorry if this is a stupid question. I made this page by pecing scripts together that I found online. I don't even know if this is the best way to get my desired results. I want the background to fill up the entire window, as well as the text and link to remain on the bottom in their respective corners and also re-size with the window. The code doesn't work the first time the page is loaded, but it works fine after it is refreshed. Do y'all have any suggestions on how to fix this.
View 1 Replies View RelatedI am passing an argument from the first page to the second using form "get" method.
My second html page is a dynamic page.So i couldn't retain the data which im getting from the first page because when the second page is refreshed the data is lost as the URL content is changed.
I have several switch menus that are VITAL to my website's navigation. They all worked very well when I tested the pages in all browsers. However, I finally FTPed my site to the internet, now when you click a link from a switch menu, instead of staying opened due to the onLoad function in the body, they do not appear.
Strangely, the only way to get my switch menus to show is to refresh the page.
I'm loading external div content into another page div based on the hash. It works fine but when you click the link, the page loads, but it's blank. If you refresh the page it appears.I'm looking for some way to refresh the content (once).
View 1 Replies View RelatedI have a form within an iframe that I want to use to refresh the location of the parent. I am using the form to set session variables that are used within the parent. So in the iframe I have:
<form name="MyForm" method="POST"
action="<?php echo $_SERVER['PHP_SELF'] . '?' . SID; ?>">
And to submit this form I'm using this link:
<a href="javascript: submitform()">Search</a>
Which refers to this script:
<SCRIPT LANGUAGE="JavaScript">
<!--
function loadParent()
{
parent.location.href = "/search_results.php?";
}
function submitform()
{
document.MyForm.submit();
loadParent();
}
//-->
</SCRIPT>
(I think!) my problem is this; it works fine if the MyForm action, i.e. ="<?php echo $_SERVER['PHP_SELF'] . '?' . SID; ?>", completes before loadParent() is executed but if there is a slight delay in the time it takes for the server to do this, loadParent() is executed too early and the input from MyForm is lost.
What I need is to tell the script to wait until the MyForm action has completed, i.e. the page has refreshed, before running loadParent(). I'm sure there are loads of different ways of doing this. Ideally I would like something that detects the page refresh within the iframe (caused by the MyForm action) and not something that relies on a timed delay loop.
Script to show on the web page that how many times user loaded it or refresh it. the counter restarted from 0 on closing the browser and open it again.
View 9 Replies View RelatedI need to refresh multiple images on my site. So every time the page gets refreshed the images need to change. It worked fine with the script below, but this is only related to 1 image
I tried to copy the script and change the "ID's" but this does not do the job.
What should I change/add to the script below?
In head:
In body:
How do I check if the method of text() starts with a 1
View 1 Replies View RelatedI have a left side textbox and a find button and similarly, a right side textbox and a find button. Clicking on the either side button will display a grid with populated data. The right side button should not display any grid, IF the left side grid is not displayed and any row is not selected in that grid. for this validation, I have scripted the code as follows:
Collapse | Copy Code:
If left grid is present, if even though no row is selected in it, this method works fine. But if, no grid is present on the page, this method doesn't get called and right grid gets displayed without passing this validation.
How to get the method called even if there is no grid on the screen.
Here is the HTML: [URL] I'm trying to uncheck the selected radio button, then set the value to 1 (Yes), basically overwriting theinitialvalue to 1. I've looked at prop(), val(), and attr(), and just don't know where to start. Should I select $('#set_q157 input') or$('#set_q157 input:radio'), or each individual radio?
Do I need to each them, and check if its checked, then change its value, or is there a way to select all three inputs as just one radial button? It would also need to work if the input has not yet been checked.
I want to check whether the user have enabled javascript on their browser or know if not then give an alert msg.
View 16 Replies View RelatedNot sure if I posted this in the right area since its a Javascript/PHP related problem.I have no clue how to check if a user didn't leave the site.Ofcourse you can use the Onunload() or Beforeunonload() function.But some browsers like Opera and Safari and who know what other browsers don't support it.Is there any other alternative?Like expecting server side each X seconds a AJAX request from the user?If the user doesn't send a request, the user has left.
View 2 Replies View RelatedI have to come up with a user authenication page the logs the user in and also gives them access to do the right things. I have attached the code and the access file and have got started on a few things.I first need to create a login page with the fields username and password have that check the access database and then proceed it to a page to do the following depending on the user access. For The Login button to even be enabled the username and password must have a value in it. I have no idea how to do that
Add A User [No duplicate Users]
Modify A User
Delete A User
[code]....
i installed a shout box for my users, its integrated by using session username. but what i want to do is have a username list under the shoutbox that shows which members (usernames) have the box open. that way the other members can see someone is out there to see their message.. one alternative would be to just have the shoutbox auto open (which i need to learn how to do) as soon as they sign on to the site, but what if they close it right away i still have the same issue (they cant see the message that someone is sending them) here is how i open the window now, they have to click on the link.
<a href="#" onClick="javascript:popup=window.open('shoutbox/minichat.php','SHTB','status=0,menubar=0,resizable=0,scrollbars=0,width=297px,height=300px');"><font size="2">Shoutbox</font></a>
so how do i know which users have it open? and how to i autostart the shoutbox? (do i used onload and onunload?)
i am using netbean to develop a registration form.As this i want to know what is the coding to check input of text, integer, email , so i can restrict what they input..
View 3 Replies View RelatedI need to find a way of modifying this function so it only initiates a request if there is a period of say 2 seconds of inactivity. The user inputs some text, and if they stop typing for 2 seconds, it should then fire off the request. Can someone tell me how i can check for inactivity in the #inputString field? This must involve some kind of timer, but how should it be structured?the lookup function sends the current value of inputstring to another function which posts it to the server side file which then returns the results in a box.
$(function() {
$('#inputString').keyup(function(e) {
[code]....
how to check if a user didn't leave the site.Ofcourse you can use the Onunload() or Beforeunonload() function.But some browsers like Opera and Safari and who know what other browsers don't support it. And I don't want to have false information about users still being there while they left.Is there any other alternative? Like expecting server side each X seconds a AJAX request from the user?If the user doesn't send a request, the user has left.
View 2 Replies View Related<?php
if($_SESSION['id'])
echo '<h1>Hello, '.$_SESSION['usr'].'! You are registered and logged in!</h1>';
else echo '<h1>Please, <a href="demo.php">login</a> and come back later!</h1>';
echo 'Should i find a new login'
?>
im trying to use this as a check to see if someone is logged in
I currently run a website similar to digg, where users can vote on a story. What I have been using so far to create the vote buttons, are just simply links that insert a vote into a database. And if a user tries to vote again on the same story, it attempts to insert the vote into the database, (im using MySQL btw), but when it cannot, they are redirected to a page where it tells them they have already voted on the story.
Now I thinking there has to be a better way to do this, and that's when digg came to mind. Can someone please point me in the direction of a javascript tutorial/wiki etc. on creating javascript buttons that interact with a mysql database AND remember that you have voted.
As this forum has been so helpful before, this time it's a JS question:I have a list of checkboxes from which the user can select 1 or more to check and perform an action upon.Thus, all checkboxes have the same "name" (in ASP code, since it's DB-related):
response.write "<input type=checkbox name=""FieldName"" value="&obj("OrderID").value&">"
I call JS using a button:
<img src="images/TrashBin.png" border=0 onclick="Delete(document.FormName.FieldName)">
[code]....
I'm trying to figure out with Java Script how I would have Java Script check and see if a check box is or not empty. The goal is to only allow the user to have one box checked at any time in a form. That means, if they click on another one and there is already one checked, it would uncheck the one that was checked and make the one that the person checked on next checked.
View 4 Replies View RelatedI am trying to allow a user to easily uncheck/check all checkboxes in a form by checking or unchecking a checkbox. The checkboxes would be in a form like so:
<form action="" method="post">
<input type="checkbox" name="checked[]" value="1">
<input type="checkbox" name="checked[]" value="2">
<input type="checkbox" name="checked[]" value="3">
<input type="checkbox" name="checked[]" value="4">
</form>
I use an event handler to call a function:
<input type="checkbox" name="checkall" onchange="checkall('checked[]', this.checked)">
And here is the function:
function checkall(box_name, current_state) {
all = document.getElementsByName(box_name);
action = (current_state == "checked") ? "false" : "true";
for (i = 0; i < all.length; i++) {
all[i].checked=action;
}}
The event handler should pass the name of the checkboxes and whether the "check all" checkbox is currently checked or not to the checkall() function. Nothing happens when I check/uncheck the "check all" function.