I have a form with 2 submit buttons.I have the following:
Code HTML4Strict:
<form action="page.php" method="post" onsubmit="return errorsOnSubmit(this);">
My question is how can I in my errorsOnSubmit() function check which submit button was clicked?
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
I have three submit buttons on a form:
<input name="update" type="submit" id="update" value="Update Record" />
<input name="delete" type="submit" id="delete" value="Delete Record" />
<input name="clear" type="submit" id="clear" value="Clear Form" />
In the onsubmit() function for the form I have called a function named confirmAction()).
In this function how can I determine which button submitted the form?
I have a submit-event attached to my form. The form contains a few different submit-buttons and I wan't to chech which one of them that triggered the submit. Shouldn't be to hard but i can't find out how to do it.
View 2 Replies View RelatedHere is my handler:
Here is my button:
How do i trigger a validate when the submit button is clicked?
All of my validations work while I am working with the form but the button does zilch.
I have a drop down selection box with items in it. I need to be able to pass the selected item through using an onclick event for the "Submit" button. Is this possible?
I have a Javascript that is calling a div to popup. This div is the drop down selector. I want the user to click a button to make the drop down appear, then they must select an item in the list and then hit submit. The submit button being clicked I need to bring in the selected value from the drop down and use it in the script that originally told the div to pop up (this is the first button that the user clicks, it actually runs the script which passes 2 variables, and is basically waiting on the drop down selection to save into a 3rd variable, which will then call a PageMethod).
I have
function AddTemplateToUUT(uutnumber,testerid){
var templatename=SelectTemplateToAssign();
PageMethods.AddTemplateToUUT(testerid,uutnumber,templatename,CallbackDiv,CallbackErrorAlert,'divchecklistarea');
ShowSelection('divtemplateblock','hide');
[Code]....
At the bottom of this page: [URL] There's a sign up button... When you click on it, the button is disabled, and the word 'Signup' is replaced by 'Signup in process'. The HTML on the button is:
Code HTML4Strict:
<button type="submit" id="SBIAgree" class="actionCreate" disableonsubmit="Signup in progress..." name="MSignal_SI-IA*">
And there is a tonne of javascript on the Fastmail Site here: [URL] I think it's something to do with the 'disableonsubmit' function, but when I tried to separate out that part of the JS into a test page myself, I can't get it to work. I wondered if anyone might be able to advise about the core JS elements that make this functionality work?
I've created a form with combobox with different values (this is for my website). What I want is when the user clicks 'submit' that it goes to a different page on the website depending on the value the person has selected in the combobox. Values are numerical, for example 1000, 2000, 5000 etc. I've been trying this for a couple of days now without success!
View 10 Replies View RelatedIm trying to use javascript history to resize an iframe when a submit button is clicked inside the iframe.
This is what i found so far.
Code:
Us this with iframe:
Code:
Code:
But im not really sure on how to apply this to my iframe, and i know that the resize part also needs to be edited, but what is missing?
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedThe following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
My form is going to be a pop up window. How can i close it 3 seconds after the submit button is clicked?
I need both PHP's message 'Member added successfully' to display and the window to close 3 seconds after.
This is my code (whats in red is my attempt to use setTimeout, but it seems php is overriding it : ( )
<?
include("config_fnsML.php");
$msg='';
$tdtitle = 'New Member';
[Code].....
How can I make this code disable the submit button once it has been pressed, then if the user hits back or GOES back, it will re-enable it again?
<SCRIPT LANGUAGE="JavaScript" TYPE="text/JavaScript">
function formControl(submitted)
{
[code]....
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I have this as my Dialog Javascript
$( "#dialog-form<?php echo $diagnumber; ?>" ).dialog({
autoOpen: false,
height: 300,
[code]....
Seems to me this would be a fairly common situation (if not commonly asked and answered), but the posts I did find about this subject didn't seem to
Given this basic code:
<form id="form" action="">
<input id="submit1">
[code]....
I have recently downloaded the jQuery Validation Plugin, and I want to use the bottom part of the demo [url] (Validating a Complete Form) and I have some questions to ask:
1. I want the validation to work after the user clicked "Submit"
2. If a column is wrong (username already taken or password length invalid) I want not only error message but also a picture in front of the error message.
3. I hope that after the user clicks "Submit" and then found a column is wrong then correct it, after the user corrected it and click to other place or other column the validator starts again to check the column the user just edited whether the user just corrected a wrong column or edited a correct column into error.
4. I hope to display a image in right of the column if that column is correct after the validator works.
im trying to learn how jquery ajax function works by validating some form after submit is clicked.
[Code]....
the alert didnt pop until i added the registration_ok = false; right before, so im assuming it has something to do with the ajax functions's scope.... why does the ajax function not affect the registration_ok variable outside the function? and how should i solve this problem? any better way of doing it?
I copied codes on internet and arranged them according to my knowledge of JQuery (which is very shallow).. The code works fine sometimes.... but not all the time. Can anyone help me to find out why the dialog box does not appear everytime I put wrong username and password?
Here is the JQuerycode:
[Code]...
Because I am using ui-darkness as the page theme, so at form tag, I don't have defaultbutton="but_submit" tag. If I add it back, I will get error while compiling..
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
[Code]...
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
Below is the code for a Captive Portal Splash Page. I have tried to research how to fix the button at the bottom of my page but I can either add a link (which does not require checking the box to agree to terms) or simply how it came to me without the ability to send customer anywhere.
[Code]...
Could anyone please tell me how to make a button look like "being clicked"? A button picture always looks static, though a link is associated with it.
View 7 Replies View Relatedit a .net app, in my client javascript code I would like to find out what event caused the page to validate. No, setting a hidden this or that will not do. I just want to know what event caused the validation.
View 7 Replies View Related
