Below is the code for a Captive Portal Splash Page. I have tried to research how to fix the button at the bottom of my page but I can either add a link (which does not require checking the box to agree to terms) or simply how it came to me without the ability to send customer anywhere.
[Code]...
<?php
session_start();
if (empty($_SESSION['is_logged_in']))
{
header("Location:chatframe.php");
[Code]...
Im trying to develop a load more button, i have no idea where to start and google is not helping me find any decent resources.
View 2 Replies View RelatedCan somebody tell me why the button at the bottom of the page will not alert upon click [code]
View 1 Replies View RelatedI have this as my Dialog Javascript
$( "#dialog-form<?php echo $diagnumber; ?>" ).dialog({
autoOpen: false,
height: 300,
[code]....
How would I go about creating the coding for a submit button that links to another page? And I would I go about creating the coding for the reset button that resets the page? I go about creating a code to do so, but it never works. Here is the coding I have for the submit button:
<p id="pbuttons"><center>
<input type="reset" value="Reset" />
<input type="submit" value="Submit Order">
</center></p>
I have the following JS. In this, when I press the submit button, I have a JS function that will create 2 input boxes and one more submit button.
When I type the values in those input boxes and click on the newly created submit button, the addition of the above input values should display. But the entire input boxes and submit button gets lost and the old page is getting displayed.
My JS:
[URL]
I have a form on my contact page. when the user fills out the info and clicks on my submit button, I need that page (send_form_email.php)to load inside my div.
this is what I have now -
Code:
<input type="submit" value="Submit" /></td>
I have tried this but it doesn't work, I get a blank page.
<INPUT TYPE="button" onClick="javascript:ajaxpage('send_form_email.php', 'mainContent');">
I have a form that I perform some AJAX business on when it is submitted. However, I wanted to have an if...else statement but when I add it it allows the page to refresh upon submit. For example.
[Code]...
When I hit the submit button, the result are display on a new page. how do I force it to stay on the same page, here's my code.
[Code]....
I am attempting to redirect a page after a user clicks on a submit button.I have a button:
<input id="SubmitButton" type="submit" class="button" name="-Edit" value="Submit" onClick="toSubmitted();"
And a function:
function toSubmitted() {
document.myForm.action = some URL that has to do with a Filemaker Pro backend.
document.myForm.submit();
window.location = "www.google.com";
}
Supposed to submit myForm, which sends necessary data to the FileMaker backend, and then I am wanting to redirect to a new page immediately after that.
The "window.location = "www.google.com";" line does not seem to function in its present location.
I have a credit card donation page and what I wanted to do is after they click the submit button and transaction is successfult I wanted to capture the donation amount they enter from the donation page and show it to the next page.
View 2 Replies View RelatedI have a website containing 26 subdirectories 'a' to 'z'
On the home page I want a text field and submit button
If someone for example types 'j' it will go to the 'j' folder home page
Does anyone know where I might find code like this?
I would like to have a Back To Top button in the bottom right corner of the viewport. I figured that Javascript would be used for this, and after some searching, I found this Jump To Top Link script at DynamicDrive. I'm sure I could easily change its appearance from a link to a button but I don't like the jerky scrolling effect. I wondered if you guys could explain to me how to make the button (or link in the script's case) stay in the bottom right corner of the viewport at all times instead of scrolling?
View 3 Replies View RelatedI want to find a way to place a button at the bottom right corner of an image. The button should still be inside the image, not under the image. How? I know how to create a link button using FORM and INPUT tag, but can I use innerHtml to insert the button into the IMG tag? If not, how to do it? I tried, but the button is always outside the image.
View 5 Replies View RelatedI have it set up so that there are three frames (frames and the use of javascript are encourage for practice) "bar" on the left with navigational options, "main" in the center where the body of the drill is presented, and "feedback" along the bottom where the feedback will appear.
My issue is that I have everything working except the form! I'm not sure how to make it so that upon clicking the submit button the feedback is presented in the "feedback" frame. This was suggested to me but isn't working, maybe I have a mistake somewhere? Or is there another way I can do this?
<html>
<head>
<script type="text/javascript">
function CheckCheckbox() {
[Code]....
when I click on a button, it should display below the button a random randomStrings(AAA, AAB, AAC, AAD, or AAE). The problem is that when I click on the button nothing is being displayed. Instead it just re-opens the web page I am on.
How can I get it so that when I click on the button, a randomStrings appears at the bottom.
question 2 is that in the future I want the randomStrings to display AAA, AAB, AAC ... all the way to ZZZ. Is there a shorter way to display the randomStrings than just AAA, AAB, AAC and so on.
Below is my code
<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" />
<title>Create a Session</title>
<script type="text/javascript">
[Code].....
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
how I can make each radio button call a different page. For example If i click on radio button 1 and click submit it will take me to [url].... and if I click radio button 2 and click submit .
View 7 Replies View RelatedI have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I hired a programmer to develop a drag and drop system for my blog. The user should be able to browse one of my blog entries and click, drag and drop an image from my entry to a fixed bottom bar on that page.The problem we are facing is that when dragging an image, it wont place it on the bottom bar until the whole page is scrolled down to the bottom of the page. This is a problem because some of the pages can be very lengthy
View 2 Replies View RelatedI've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...